Problem 17
Question
A person swimming 0.80 \(\mathrm{m}\) below the surface of the water in a swimming pool looks at the diving board that is directly overhead and sees the image of the board that is formed by refraction at the surface of the water. This image is a height of 5.20 \(\mathrm{m}\) above the swimmer. What is the actual height of the diving board above the surface of the water?
Step-by-Step Solution
Verified Answer
The actual height of the diving board is 6.116 m above the water surface.
1Step 1: Understand the concept
This problem involves refraction, which is the bending of light as it passes from one medium to another. We are given the apparent height seen by the swimmer and need to find the actual height using Snell's Law.
2Step 2: Identify the knowns and unknowns
- Given: Apparent height of image above water surface: 5.20 m; Depth of swimmer below water surface: 0.80 m
- Unknown: Actual height of the diving board above the water surface (real height).
3Step 3: Use Snell's Law for a level surface
Snell's Law relates the angle of incidence (i) and the angle of refraction (r) through the equation: \ \(n_1 \sin(i) = n_2 \sin(r)\).However, in terms of apparent depth (d') and real depth (d) for normal viewing angles from water to air, we can approximate: \ \(\frac{\text{apparent height}}{\text{real height} + \text{swimmer's depth}} = \frac{n_{air}}{n_{water}}\) \ where \(n_{air}\) is about 1.00 and \(n_{water}\) is about 1.33.
4Step 4: Set up the equation
Given the equation: \[\frac{5.20}{h + 0.80} = \frac{1.00}{1.33}\]where \(5.20\) m is the apparent height, \(h\) is the real height above the water, and the refractive indices are for air and water respectively.
5Step 5: Solve the equation for real height (h)
Rearrange the equation and solve for \(h\): \[5.20 \times 1.33 = (h + 0.80) \times 1.00\]\[6.916 = h + 0.80\]Subtract 0.80 from both sides:\[h = 6.916 - 0.80 = 6.116 \text{ m}\]
6Step 6: Interpretation and Conclusion
The calculated real height of the diving board above the surface of the water is 6.116 m. Therefore, the height that was seen by the swimmer is affected by the bending of light as it exited the water.
Key Concepts
Snell's LawRefractive IndexApparent DepthReal Depth
Snell's Law
Snell's Law is a fundamental principle that explains the refraction of light. When light travels from one medium to another, its speed changes, causing it to bend. Snell's Law provides a way to calculate this bending. The formula is:\[ n_1 \sin(i) = n_2 \sin(r) \]where:
- \( n_1 \) and \( n_2 \) are the refractive indices of the two media.
- \( i \) is the angle of incidence, and \( r \) is the angle of refraction.
Refractive Index
The refractive index is a measure of how much light bends when it enters a material. It is a dimensionless number that describes how fast light travels through the medium compared to vacuum. The refractive index for a material is shown as \( n = \frac{c}{v} \), where:
- \( c \) is the speed of light in vacuum.
- \( v \) is the speed of light in the medium.
Apparent Depth
Apparent depth is how deep an object appears when viewed from above the surface of a different medium. It results from refraction, where light rays bend upwards as they move from a denser medium like water to a less dense medium like air. To calculate apparent depth, the formula used is:\[ \frac{\text{apparent depth}}{\text{real depth}} = \frac{n_{air}}{n_{water}} \]In our exercise, the apparent depth helps determine how much the image of the diving board is shifted by refraction. This visible shift creates the illusion that objects under water seem closer to the surface than they actually are.
Real Depth
Real depth refers to the true distance of an object beneath the surface of a medium. Unlike apparent depth, real depth does not consider the effects of light bending. In solving our exercise, finding the real height or depth involves using apparent depth, refractive indices, and the swimmer's position below the water surface.By rearranging the refractive relationship, we were able to solve:\[ h = 6.916 - 0.80 = 6.116 \text{ m} \]This calculation provides the true height of the diving board above the water. Understanding the difference between apparent and real depths is crucial for underwater navigation and imaging.
Other exercises in this chapter
Problem 15
A speck of dirt is embedded 3.50 \(\mathrm{cm}\) below the surface of a sheet of ice \((n=1.309) .\) What is its apparent depth when viewed at normal incidence?
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The left end of a long glass rod 6.00 \(\mathrm{cm}\) in diameter has a convex hemispherical surface 3.00 \(\mathrm{cm}\) in radius. The refractive index of the
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