Problem 17
Question
Use I'Hópital's rule to find the limits. $$\lim _{\theta \rightarrow \pi / 2} \frac{2 \theta-\pi}{\cos (2 \pi-\theta)}$$
Step-by-Step Solution
Verified Answer
The limit is \(-2\).
1Step 1: Identify the Indeterminate Form
The limit given is \( \lim_{\theta \rightarrow \pi/2} \frac{2\theta - \pi}{\cos(2\pi - \theta)} \). Let's evaluate the expression as \( \theta \to \pi/2 \). At \( \theta = \pi/2 \), the numerator becomes zero: \( 2(\pi/2) - \pi = 0 \). The denominator, \( \cos(2\pi - \pi/2) \), also becomes zero. Therefore, we have the indeterminate form \( \frac{0}{0} \).
2Step 2: Apply L'Hôpital's Rule
Since the expression is in the \(\frac{0}{0}\) form, we apply L'Hôpital's Rule, which involves differentiating the numerator and denominator separately. Differentiating the numerator \(2\theta - \pi\) gives \(2\). Differentiating the denominator \(\cos(2\pi - \theta)\) involves the chain rule, resulting in \(\sin(2\pi - \theta)(-1) = -\sin(2\pi - \theta)\).
3Step 3: Evaluate the Limit After Differentiation
Now, we evaluate the new limit: \( \lim_{\theta \rightarrow \pi/2} \frac{2}{-\sin(2\pi - \theta)} \). At \( \theta = \pi/2 \), the term \( \sin(2\pi - \theta) = \sin(\pi/2) = 1 \). Therefore, the limit simplifies to \(-2\).
Key Concepts
Indeterminate FormsDifferentiationLimits in Calculus
Indeterminate Forms
When calculating limits, you might find some expressions where traditional methods do not immediately provide an answer. Such cases are known as indeterminate forms. A common example is \( \frac{0}{0} \). This arises when both the numerator and denominator of a fraction tend to zero as a variable approaches a certain value. In our exercise, as \( \theta \to \pi/2 \), both the numerator \( 2\theta - \pi \) and the denominator \( \cos(2\pi - \theta) \) approach zero. Indeterminate forms like
- \( \frac{0}{0} \)
- \( \frac{\infty}{\infty} \)
Differentiation
Differentiation is the process of finding the derivative of a function. Derivatives measure how a function's output value changes as its input changes. In applying L'Hôpital's Rule, we need to differentiate both the numerator and the denominator of a given function. For the expression in the exercise, we have to differentiate:
- Numerator: \( 2\theta - \pi \)
- Denominator: \( \cos(2\pi - \theta) \)
Limits in Calculus
Limits are foundational in calculus, providing the basis for defining derivatives and integrals. They describe the behavior of functions as inputs approach a certain value. For instance, to solve the limit \( \lim_{\theta \to \pi/2} \frac{2}{-\sin(2\pi - \theta)} \), we substitute \( \theta = \pi/2 \) into the expression. This gives \(-\sin(\pi/2) = -1 \), and the limit thus reduces to \(-2\). Limits can use various methods for evaluation. Techniques like substitution, factoring, and L'Hôpital's Rule are often employed to find definitive values for limits with indeterminate forms. Grasping the concept of limits helps in understanding behavior and continuity of functions in calculus. Each method provides a tool for navigating different types of limit problems.
Other exercises in this chapter
Problem 17
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