Problem 17
Question
Use a formula for negatives to find the exact value. $$\text { (a) } \sin \left(-90^{\circ}\right) \quad \text { (b) } \cos \left(-\frac{3 \pi}{4}\right) \quad \text { (c) } \tan \left(-45^{\circ}\right)$$
Step-by-Step Solution
Verified Answer
(a) -1, (b) -√2/2, (c) -1
1Step 1: Understanding Sine with Negative Angles
The formula for sine with a negative angle is given by \( \sin(-x) = - \sin(x) \). This tells us that the sine of a negative angle is the negative of the sine of the positive angle. For \( \sin(-90^\circ) \), this means \( \sin(-90^\circ) = -\sin(90^\circ) \).
2Step 2: Calculating \( \sin(90^\circ) \)
From the unit circle, we know that the sine of \( 90^\circ \) is \( 1 \). Thus, \( \sin(-90^\circ) = -1 \times 1 = -1 \).
3Step 3: Understanding Cosine with Negative Angles
The formula for cosine with a negative angle is \( \cos(-x) = \cos(x) \). This tells us that the cosine of a negative angle is the same as the cosine of the positive angle. For \( \cos\left(-\frac{3\pi}{4}\right) \), this means \( \cos\left(-\frac{3\pi}{4}\right) = \cos\left(\frac{3\pi}{4}\right) \).
4Step 4: Calculating \( \cos\left(\frac{3\pi}{4}\right) \)
The angle \( \frac{3\pi}{4} \) radians corresponds to \( 135^\circ \). At this angle, cosine is \( -\frac{\sqrt{2}}{2} \), so \( \cos\left(-\frac{3\pi}{4}\right) = -\frac{\sqrt{2}}{2} \).
5Step 5: Understanding Tangent with Negative Angles
The formula for tangent with a negative angle is \( \tan(-x) = -\tan(x) \). This means that the tangent of a negative angle is the negative of the tangent of the positive angle. For \( \tan(-45^\circ) \), this means \( \tan(-45^\circ) = -\tan(45^\circ) \).
6Step 6: Calculating \( \tan(45^\circ) \)
From standard trigonometric values, we know that \( \tan(45^\circ) = 1 \). Therefore, \( \tan(-45^\circ) = -1 \times 1 = -1 \).
Key Concepts
Sine FunctionCosine FunctionTangent Function
Sine Function
The sine function is a fundamental component of trigonometry. It relates an angle in a right triangle to the ratio of the length of the opposite side to the hypotenuse. The formula for the sine of a negative angle is expressed as \( \sin(-x) = -\sin(x) \).
This identity tells us that the sine of a negative angle is simply the negative of the sine of its positive equivalent.
Let's apply this to calculate \( \sin(-90^\circ) \):
This identity tells us that the sine of a negative angle is simply the negative of the sine of its positive equivalent.
Let's apply this to calculate \( \sin(-90^\circ) \):
- The task involves calculating \( \sin(90^\circ) \).
- From the unit circle, \( \sin(90^\circ) \) is known to be equal to \( 1 \).
- Therefore, \( \sin(-90^\circ) = -1 \times 1 = -1 \).
Cosine Function
The cosine function, another key trigonometric concept, describes the ratio of the adjacent side of a right triangle to the hypotenuse. What's particularly interesting about the cosine function is how it deals with negative angles. The identity for cosine is \( \cos(-x) = \cos(x) \), which indicates that cosine values are unaffected by the sign of the angle.
For example:
For example:
- To find \( \cos\left(-\frac{3\pi}{4}\right) \), we first calculate \( \cos\left(\frac{3\pi}{4}\right) \).
- The angle \( \frac{3\pi}{4} \) is equivalent to \( 135^\circ \), where cosine is \( -\frac{\sqrt{2}}{2} \).
- Therefore, \( \cos\left(-\frac{3\pi}{4}\right) = -\frac{\sqrt{2}}{2} \).
Tangent Function
The tangent function offers a different perspective, connecting the two other functions, sine and cosine. Tangent of an angle is calculated by taking the ratio of the sine to the cosine of that angle. For negative angles, the tangent formula states \( \tan(-x) = -\tan(x) \), which mirrors the behavior we saw with the sine function.
Let's explore this with an example:
Let's explore this with an example:
- We need to find \( \tan(-45^\circ) \).
- First, find \( \tan(45^\circ) \), which is known to be \( 1 \).
- Applying the negative angle identity, \( \tan(-45^\circ) = -1 \times 1 = -1 \).
Other exercises in this chapter
Problem 17
Given the indicated parts of triangle \(A B C\) with \(\gamma=90^{\circ},\) express the third part in terms of the first two. $$\alpha, c ; \quad b$$
View solution Problem 17
Find the amplitude, the period, and the phase shift and sketch the graph of the equation. \(y=-2 \sin (3 x-\pi)\)
View solution Problem 17
Find the period and sketch the graph of the equation. Show the asymptotes. $$y=-\frac{1}{4} \tan \left(\frac{1}{2} x+\frac{\pi}{3}\right)$$
View solution Problem 17
Find the exact value. (a) cse \(240^{\circ}\) (b) \(\csc \left(-330^{\circ}\right)\)
View solution