Problem 17
Question
Given the indicated parts of triangle \(A B C\) with \(\gamma=90^{\circ},\) express the third part in terms of the first two. $$\alpha, c ; \quad b$$
Step-by-Step Solution
Verified Answer
\(b = c \cdot \cos(\alpha)\)
1Step 1: Identify the Known Elements of the Right Triangle
In triangle \(ABC\), \(\gamma = 90^\circ\) indicates that this is a right triangle with \(C\) being the right angle. The known parts in this problem are angle \(\alpha\) and hypotenuse \(c\), and we are asked to express side \(b\).
2Step 2: Understand Trigonometric Relationships
In a right triangle, the relationship between an acute angle \(\alpha\), its opposite side \(a\), the hypotenuse \(c\), and the adjacent side \(b\) can be determined through trigonometric ratios. Specifically, \(\cos(\alpha) = \frac{b}{c}\).
3Step 3: Rearrange the Trigonometric Formula to Find \(b\)
From the cosine definition, \(\cos(\alpha) = \frac{b}{c}\) can be rearranged to solve for the side \(b\): \[ b = c \cdot \cos(\alpha) \]
4Step 4: Conclusion
The side \(b\) in the right triangle can be expressed in terms of the hypotenuse \(c\) and angle \(\alpha\) as \(b = c \cdot \cos(\alpha)\).
Key Concepts
Right TriangleTrigonometric RatiosCosine Function
Right Triangle
A right triangle is a type of triangle that has one angle equal to 90 degrees. This specific angle is known as the right angle. In every right triangle, the side opposite the right angle is the longest side, termed the hypotenuse. The other two sides that form the right angle are known as the legs or catheti of the triangle.
Right triangles are fundamental in trigonometry because they allow us to define and explore trigonometric functions using their consistent angle-side relationships.
Right triangles are fundamental in trigonometry because they allow us to define and explore trigonometric functions using their consistent angle-side relationships.
- The hypotenuse is always opposite to the right angle and is the longest side of the triangle.
- The two legs of the triangle can be referred to as either opposite or adjacent, depending on the angle in question.
Trigonometric Ratios
Trigonometric ratios are mathematical tools that relate the angles and sides of a right triangle. These ratios include sine, cosine, and tangent, each corresponding to a specific ratio between sides of the triangle. Knowing at least one angle besides the right angle and one side of the triangle allows you to find the other sides using these ratios.
The primary trigonometric ratios are:
The primary trigonometric ratios are:
- Sine ( \( \sin \theta \) ): This ratio compares the length of the side opposite the angle to the length of the hypotenuse, or \( \sin \theta = \frac{\text{opposite}}{\text{hypotenuse}} \).
- Cosine ( \( \cos \theta \) ): This ratio compares the length of the adjacent side to the hypotenuse, or \( \cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}} \).
- Tangent ( \( \tan \theta \) ): This ratio compares the length of the opposite side to the adjacent side, or \( \tan \theta = \frac{\text{opposite}}{\text{adjacent}} \).
Cosine Function
The cosine function is one of the main trigonometric functions and is particularly useful for finding unknown side lengths of right triangles when an angle and one side are known. The function is defined as the ratio of the length of the adjacent side to the hypotenuse in a right triangle.
Understanding the cosine function involves:
Understanding the cosine function involves:
- Recognizing that \( \cos(\alpha) \) gives you the ratio \( \frac{b}{c} \) , where:
- \( b \) is the length of the side adjacent to angle \( \alpha \)
- \( c \) is the hypotenuse
- Applying the formula: Rearranging the cosine formula \( \cos(\alpha) = \frac{b}{c} \) to solve for \( b \) gives \[ b = c \cdot \cos(\alpha) \] . This step is crucial in determining the side length of \( b \) in the triangle.
Other exercises in this chapter
Problem 16
Exer. \(13-16:\) Find the exact degree measure of the angle. $$\text { (a) }-\frac{5 \pi}{2} \quad \text { (b) } 9 \pi \quad \text { (c) } \frac{\pi}{16}$$
View solution Problem 16
Let \(P\) be the point on the unit circle \(U\) that corresponds to \(t .\) Find the coordinates of \(P\) and the exact values of the trigonometric functions of
View solution Problem 17
Find the amplitude, the period, and the phase shift and sketch the graph of the equation. \(y=-2 \sin (3 x-\pi)\)
View solution Problem 17
Use a formula for negatives to find the exact value. $$\text { (a) } \sin \left(-90^{\circ}\right) \quad \text { (b) } \cos \left(-\frac{3 \pi}{4}\right) \quad
View solution