Problem 17
Question
Solve the inequality involving absolute value. Write your final answer in interval notation. $$ |3 x-1|>11 $$
Step-by-Step Solution
Verified Answer
The solution is \((-\infty, -\frac{10}{3}) \cup (4, \infty)\).
1Step 1: Understanding the Absolute Value Inequality
We begin by recalling that the absolute value inequality \(|A| > B\) translates to two inequalities: \(A > B\) or \(A < -B\). So, for the inequality \(|3x - 1| > 11\), we set up the following two inequalities:1. \(3x - 1 > 11\)2. \(3x - 1 < -11\)
2Step 2: Solving the First Inequality
First, solve \(3x - 1 > 11\):- Add 1 to both sides to isolate the term with \(x\): \[ 3x > 12 \]- Divide both sides by 3 to solve for \(x\): \[ x > 4 \]
3Step 3: Solving the Second Inequality
Next, solve \(3x - 1 < -11\):- Add 1 to both sides: \[ 3x < -10 \]- Divide both sides by 3 to solve for \(x\): \[ x < -\frac{10}{3} \]
4Step 4: Writing the Solution in Interval Notation
The solutions from both inequalities are combined to get the final answer in interval notation. The solution is the union of the intervals from both inequalities: \(x > 4\) or \(x < -\frac{10}{3}\). In interval notation, this is written as:\[ (-\infty, -\frac{10}{3}) \cup (4, \infty) \]
Key Concepts
Interval NotationSolving InequalitiesAlgebraic Expressions
Interval Notation
Interval notation is a concise way of expressing a range of values, often used in mathematics to describe the set of solutions for inequalities. It's an essential tool because it helps represent complicated solution sets in a simple and readable manner.
Using interval notation involves certain symbols:
Using interval notation involves certain symbols:
- Square brackets [ ] indicate that an endpoint is included (called a closed interval).
- Parentheses ( ) indicate that an endpoint is not included (called an open interval).
- Infinity (∞) is always expressed with a parenthesis because infinity is a concept and cannot be "included" in the traditional sense.
Solving Inequalities
Solving inequalities is about finding the range of values that satisfy a given inequality. Inequalities can signify that one expression is greater than, less than, or even equal to another. Solving inequalities involving absolute values requires understanding and breaking down the expressions into manageable parts.
For the absolute value inequality \(|3x - 1| > 11\), we start by transforming it into two separate inequalities:
For the absolute value inequality \(|3x - 1| > 11\), we start by transforming it into two separate inequalities:
- \(3x - 1 > 11\)
- \(3x - 1 < -11\)
- Add or subtract terms to isolate the variable terms.
- Divide or multiply to solve for the variable while ensuring to flip the sign if multiplying or dividing by a negative number.
Algebraic Expressions
Algebraic expressions are the building blocks of algebra and include numbers, variables, and arithmetic operations. Understanding how to manipulate these expressions is crucial in solving equations and inequalities.
In the inequality we've dealt with, \(3x - 1\), we see a linear expression. When solving inequalities, our primary goal is to isolate the variable on one side of the inequality. We do this by performing operations like addition, subtraction, multiplication, or division:
In the inequality we've dealt with, \(3x - 1\), we see a linear expression. When solving inequalities, our primary goal is to isolate the variable on one side of the inequality. We do this by performing operations like addition, subtraction, multiplication, or division:
- For \(3x - 1 > 11\), adding 1 to both sides first gives \(3x > 12\).
- Then, dividing by 3 isolates \(x\) to provide \(x > 4\).
- Similarly, solving \(3x - 1 < -11\) by adding 1 gives \(3x < -10\), and dividing by 3 provides \(x < -\frac{10}{3}\).
Other exercises in this chapter
Problem 17
For the following exercises, solve the inequality involving absolute value. Write your final answer in interval notation. $$ |3 x-1|>11 $$
View solution Problem 17
For the following exercises, solve the following polynomial equations by grouping and factoring. $$ m^{3}+m^{2}-m-1=0 $$
View solution Problem 17
For the following exercises, perform the indicated operation and express the result as a simplified complex number. $$ (-5+3 i)-(6-i) $$
View solution Problem 17
For the following exercises, solve each rational equation for \(x\). State all \(x\) -values that are excluded from the solution set. $$ 2-\frac{3}{x+4}=\frac{x
View solution