Problem 17
Question
Find the multiplicative inverse of each number. $$\frac{6}{11}$$
Step-by-Step Solution
Verified Answer
The multiplicative inverse of \( \frac{6}{11} \) is \( \frac{11}{6} \).
1Step 1: Understanding the Problem
The multiplicative inverse of a number is another number that, when multiplied with the original number, gives the result of 1. For a fraction \( \frac{a}{b} \), the multiplicative inverse is \( \frac{b}{a} \).
2Step 2: Identify the Fraction Components
The given fraction is \( \frac{6}{11} \). Here, the numerator \( a = 6 \) and the denominator \( b = 11 \).
3Step 3: Find the Inverse
To find the multiplicative inverse, simply swap the numerator and the denominator of the fraction. Thus, the inverse of \( \frac{6}{11} \) is \( \frac{11}{6} \).
4Step 4: Verify the Inverse
Multiplying the original fraction with its inverse should yield 1: \( \frac{6}{11} \times \frac{11}{6} = \frac{6 \times 11}{11 \times 6} = \frac{66}{66} = 1 \). This confirms that \( \frac{11}{6} \) is indeed the multiplicative inverse.
Key Concepts
Understanding FractionsRole of the Numerator and DenominatorVerifying Results for Accuracy
Understanding Fractions
Fractions are an essential part of mathematics. They express a portion of a whole and are written in the form \( \frac{a}{b} \). Here, \( a \) and \( b \) are integers. The top number, \( a \), is called the numerator, and it tells us how many parts of the whole there are. On the other hand, the bottom number, \( b \), is the denominator, and it indicates the total number of equal parts the whole is divided into.
Fractions can be greater than 1 if the numerator is larger than the denominator (this is called an improper fraction), or they can be less than 1 if the numerator is smaller. For example, \( \frac{3}{4} \) is less than 1, and \( \frac{7}{4} \) is more than 1. Understanding these distinctions is crucial for manipulating and identifying equivalents or inverses.
Fractions can be greater than 1 if the numerator is larger than the denominator (this is called an improper fraction), or they can be less than 1 if the numerator is smaller. For example, \( \frac{3}{4} \) is less than 1, and \( \frac{7}{4} \) is more than 1. Understanding these distinctions is crucial for manipulating and identifying equivalents or inverses.
Role of the Numerator and Denominator
In any fraction, both the numerator and denominator play crucial roles in determining its value. When we talk about swapping them to find a multiplicative inverse, these roles get reversed. In our original fraction, \( \frac{6}{11} \), the numerator is 6, and the denominator is 11. By exchanging them, you create a new fraction \( \frac{11}{6} \).
This switching of positions essentially transforms the fraction's function, as making the numerator the larger number signifies an improper fraction. It's important because this new fraction, when multiplied with the original, must produce a whole (more specifically, number 1) to verify the multiplicative inverse.
This switching of positions essentially transforms the fraction's function, as making the numerator the larger number signifies an improper fraction. It's important because this new fraction, when multiplied with the original, must produce a whole (more specifically, number 1) to verify the multiplicative inverse.
Verifying Results for Accuracy
Verification is a vital step to complete when dealing with inverses. It's how you confirm that the calculations were successful. For fractions, this means checking that the product of a fraction and its inverse equals 1.
Let's take the exercise example again: multiply the original \( \frac{6}{11} \) by its inverse \( \frac{11}{6} \). When you perform the multiplication:
Let's take the exercise example again: multiply the original \( \frac{6}{11} \) by its inverse \( \frac{11}{6} \). When you perform the multiplication:
- Multiply the numerators: \( 6 \times 11 = 66 \)
- Multiply the denominators: \( 11 \times 6 = 66 \)
Other exercises in this chapter
Problem 17
Find the least common multiple (LCM) of each pair of numbers or monomials. $$16,3$$
View solution Problem 17
Find each sum or difference. Write in simplest form. $$\frac{3}{4}+\left(-\frac{5}{8}\right)$$
View solution Problem 17
Write each number as a fraction. $$60$$
View solution Problem 17
Find sum or difference. Write in simplest form. \(-\frac{3}{4}+\left(-\frac{3}{4}\right)\)
View solution