Problem 17
Question
As you eat your way through a bag of chocolate chip cookies, you observe that each cookie is a circular disk with a diameter of \(8.50 \pm 0.02 \mathrm{cm}\) and a thickness of \(0.050 \pm 0.005 \mathrm{cm} .\) (a) Find the average volume of a cookie and the uncertainty in the volume. (b) Find the ratio of the diameter to the thickness and the uncertainty in this ratio.
Step-by-Step Solution
Verified Answer
(a) Average volume of a cookie: \(2.834 \text{ cm}^3\) with uncertainty \(0.411 \text{ cm}^3\). (b) Diameter to thickness ratio: 170 with uncertainty 17.47.
1Step 1: Determine the Formula for Volume
To find the volume of a cookie, we assume the shape of a cylindrical disk. Hence, the volume \(V\) is given by the formula: \[ V = \pi \left( \frac{D}{2} \right)^2 h \] where \(D\) is the diameter, and \(h\) is the thickness.
2Step 2: Calculate the Average Volume
Substitute the given values into the volume formula to calculate the average volume. The diameter \(D = 8.50\, \text{cm}\) and thickness \(h = 0.050\, \text{cm}\). So, \[V = \pi \left( \frac{8.50}{2} \right)^2 (0.050) \approx 2.834 \text{ cm}^3\] rounded to three decimal places.
3Step 3: Calculate the Uncertainty in Volume
To find the uncertainty in volume \((\Delta V)\), use the formula for uncertainty propagation: \[ \frac{\Delta V}{V} = 2 \frac{\Delta D}{D} + \frac{\Delta h}{h} \]Substituting \(\Delta D = 0.02\, \text{cm}\), \(D = 8.50\, \text{cm}\), \(\Delta h = 0.005\, \text{cm}\), and \(h = 0.050\, \text{cm}\), we find:- \( \Delta V \approx 2.834 \left( 2 \cdot \frac{0.02}{8.50} + \frac{0.005}{0.050} \right) \approx 0.411 \text{ cm}^3\).
4Step 4: Determine the Formula for Diameter to Thickness Ratio
The ratio of diameter to thickness \( R \) is given by: \[ R = \frac{D}{h} \] This ratio is used to assess the relationship between the disk's lateral dimensions.
5Step 5: Calculate the Average Ratio
Calculate \( R \) using the average values for diameter and thickness: \[ R = \frac{8.50}{0.050} = 170 \]
6Step 6: Calculate the Uncertainty of the Ratio
To find the uncertainty \((\Delta R)\) in the ratio, use the uncertainty propagation formula for division: \[ \frac{\Delta R}{R} = \frac{\Delta D}{D} + \frac{\Delta h}{h} \]Substitute \(\Delta D = 0.02\, \text{cm}\), \(D = 8.50\, \text{cm}\), \(\Delta h = 0.005\, \text{cm}\), and \(h = 0.050\, \text{cm}\):- \( \Delta R \approx 170 \left( \frac{0.02}{8.50} + \frac{0.005}{0.050} \right) \approx 17.47 \) rounded to two decimal places.
Key Concepts
Uncertainty PropagationDiameter to Thickness RatioMeasurement Error
Uncertainty Propagation
In the world of measurements, achieving absolute certainty is often impossible. This is where uncertainty propagation comes into play. When you calculate the volume of a cylinder, such as a cookie shaped like a disk, you use specific measurements for diameter and thickness. However, these measurements come with uncertainties. Uncertainty propagation helps us understand how these small measurement errors influence the final calculated quantity—like volume in our case.
To calculate the uncertainty in volume \(\Delta V\), start by determining the relative uncertainties for each measurement. The formula used here is:
To calculate the uncertainty in volume \(\Delta V\), start by determining the relative uncertainties for each measurement. The formula used here is:
- \(\frac{\Delta V}{V} = 2 \frac{\Delta D}{D} + \frac{\Delta h}{h}\)
Diameter to Thickness Ratio
The diameter to thickness ratio gives insight into the proportion and shape of a cylindrical object like a cookie. This ratio, represented as \(R = \frac{D}{h}\), essentially compares how 'wide' a disk is to how 'tall' it is. For the cookies, with a diameter \(D\) of 8.50 cm and a thickness \(h\) of 0.050 cm, this ratio calculates to:
When assessing the precision of this ratio, knowing its uncertainty is vital. Using the uncertainty propagation principles again, the formula employed is:
It's a useful calculation when designing or evaluating materials where shape and dimension consistency are critical.
- \(R = \frac{8.50}{0.050} = 170\)
When assessing the precision of this ratio, knowing its uncertainty is vital. Using the uncertainty propagation principles again, the formula employed is:
- \(\frac{\Delta R}{R} = \frac{\Delta D}{D} + \frac{\Delta h}{h}\)
It's a useful calculation when designing or evaluating materials where shape and dimension consistency are critical.
Measurement Error
Measurement error is an unavoidable aspect of taking physical measurements. It's the difference between the measured value and the actual value. When you measure the diameter and thickness of a cookie, the tool or method used introduces tiny discrepancies—these are your measurement errors.
These errors could arise from several sources:
Understanding measurement error is essential for interpreting results. By quantifying measurement errors, such as \(\pm 0.02\, \text{cm}\) for diameter and \(\pm 0.005\, \text{cm}\) for thickness, you can better evaluate the reliability of calculated properties like volume and the diameter to thickness ratio.
Correctly accounting for measurement errors enables scientists, engineers, or even bakers to make more informed decisions based on data that comes with known limitations.
These errors could arise from several sources:
- Imperfections in the measuring instrument.
- Environmental conditions affecting measurements.
- Human error in reading or recording measurements.
Understanding measurement error is essential for interpreting results. By quantifying measurement errors, such as \(\pm 0.02\, \text{cm}\) for diameter and \(\pm 0.005\, \text{cm}\) for thickness, you can better evaluate the reliability of calculated properties like volume and the diameter to thickness ratio.
Correctly accounting for measurement errors enables scientists, engineers, or even bakers to make more informed decisions based on data that comes with known limitations.
Other exercises in this chapter
Problem 14
With a wooden ruler you measure the length of a rectangular piece of sheet metal to be 12 \(\mathrm{mm}\) . You use micrometer calipers to measure the width of
View solution Problem 16
A rectangular piece of aluminum is \(5.10 \pm 0.01 \mathrm{cm}\) long and \(1.90 \pm 0.01 \mathrm{cm}\) wide. (a) Find the area of the rectangle and the uncerta
View solution Problem 19
A rather ordinary middle-aged man is in the hospital for a routine check-up. The nurse writes the quantity 200 on his medical chart but forgets to inchude the u
View solution Problem 22
Four astronauts are in a spherical space station. (a) If, as is typical, each of them breathes about 500 \(\mathrm{cm}^{3}\) of air with each breath, approximat
View solution