Problem 16
Question
A rectangular piece of aluminum is \(5.10 \pm 0.01 \mathrm{cm}\) long and \(1.90 \pm 0.01 \mathrm{cm}\) wide. (a) Find the area of the rectangle and the uncertainty in the area. (b) Verify that the fractional uncertainty in the area is equal to the sum of the fractional uncertainties in the length and in the width. (This is a general result; see Challenge Problem \(1.98 .\))
Step-by-Step Solution
Verified Answer
(a) Area: 9.69 cm², Uncertainty: ±0.070 cm². (b) Yes, fractional uncertainties match.
1Step 1: Calculate the Area
To find the area of the rectangle, multiply the length by the width.\[ A = l \times w = 5.10 \times 1.90 = 9.69 \, \text{cm}^2 \]
2Step 2: Calculate the Uncertainty in the Area
The area uncertainty can be obtained using the formula for multiplication of uncertain measurements:\[ \left( \frac{\Delta A}{A} \right) = \left( \frac{\Delta l}{l} \right) + \left( \frac{\Delta w}{w} \right) \]First, find the fractional uncertainty for both length and width:- \( \frac{\Delta l}{l} = \frac{0.01}{5.10} \approx 0.00196 \)- \( \frac{\Delta w}{w} = \frac{0.01}{1.90} \approx 0.00526 \)Add these fractional uncertainties:\[ \frac{\Delta A}{A} = 0.00196 + 0.00526 = 0.00722 \]Then, calculate \( \Delta A \):\[ \Delta A = A \times 0.00722 = 9.69 \times 0.00722 \approx 0.070 \text{ cm}^2 \]
3Step 3: Verify the Fractional Uncertainty Relation
Summing the fractional uncertainties of length and width should be equal to the fractional uncertainty of the area, based on the previous computation.- Fractional uncertainty in length: \( 0.00196 \)- Fractional uncertainty in width: \( 0.00526 \)- Sum: \( 0.00196 + 0.00526 = 0.00722 \)This matches the calculated fractional uncertainty for the area, verifying the relation.
Key Concepts
Area CalculationFractional UncertaintyRectangular Measurements
Area Calculation
Calculating the area of a rectangle is a straightforward task but crucial for understanding geometry and measurement. The area represents the amount of space within the rectangle and is calculated through a simple formula.
In the given problem, the formula applied is:
In the given problem, the formula applied is:
- Area, \( A \), is calculated as the product of the length \( l \) and width \( w \).
Fractional Uncertainty
Understanding uncertainty is key to effective measurement in science and engineering. Fractional uncertainty indicates how accurate a measurement is by comparing the uncertainty to the actual measured value.
In this context, the fractional uncertainty for each dimension is calculated separately:
The overall formula for this is:\[ \frac{\Delta A}{A} = \frac{\Delta l}{l} + \frac{\Delta w}{w} \approx 0.00196 + 0.00526 = 0.00722 \]This step helps you determine how much the uncertainties in measuring dimensions affect the overall measurement of area. It's a powerful tool when considering precision in quantitative calculations.
In this context, the fractional uncertainty for each dimension is calculated separately:
- Length: \( \, \frac{\Delta l}{l} \approx \frac{0.01}{5.10} \approx 0.00196 \)
- Width: \( \, \frac{\Delta w}{w} \approx \frac{0.01}{1.90} \approx 0.00526 \)
The overall formula for this is:\[ \frac{\Delta A}{A} = \frac{\Delta l}{l} + \frac{\Delta w}{w} \approx 0.00196 + 0.00526 = 0.00722 \]This step helps you determine how much the uncertainties in measuring dimensions affect the overall measurement of area. It's a powerful tool when considering precision in quantitative calculations.
Rectangular Measurements
Rectangular measurements, encompassing both length and width, serve as a base for calculating other important properties, like area, and guide the assessment of uncertainty in physical measurements.
In problems involving rectangular shapes, each measurement often includes a specific uncertainty. This uncertainty reflects possible variances in measurement due to instruments' precision limits or other external factors.
In this problem:
This task underscores the importance of being meticulous with every measurement to ensure reliable and precise scientific computations.
In problems involving rectangular shapes, each measurement often includes a specific uncertainty. This uncertainty reflects possible variances in measurement due to instruments' precision limits or other external factors.
In this problem:
- Length is \( 5.10 \, \text{cm} \) with an uncertainty \( \pm 0.01 \, \text{cm} \)
- Width is \( 1.90 \, \text{cm} \) with an uncertainty \( \pm 0.01 \, \text{cm} \)
This task underscores the importance of being meticulous with every measurement to ensure reliable and precise scientific computations.
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