Problem 17
Question
\(5-22=\) Solve the equation. $$ 3|x+5|+6=15 $$
Step-by-Step Solution
Verified Answer
The solution set is \(x = -2\) and \(x = -8\).
1Step 1: Isolate the Absolute Value Expression
First, subtract 6 from both sides of the equation to begin isolating the absolute value expression. This yields:\[3|x+5| + 6 - 6 = 15 - 6\]which simplifies to:\[3|x+5| = 9\]
2Step 2: Solve for the Absolute Value
Next, divide both sides by 3 to completely isolate the absolute value expression:\[\frac{3|x+5|}{3} = \frac{9}{3}\]which simplifies to:\[|x+5| = 3\]
3Step 3: Solve for x in Positive Case
The absolute value equation can now be split into two separate cases. The first case is when the expression inside the absolute value is equal to 3:\[x+5 = 3\]Subtract 5 from both sides:\[x = 3 - 5\]\[x = -2\]
4Step 4: Solve for x in Negative Case
The second case is when the expression inside the absolute value is equal to -3:\[x+5 = -3\]Subtract 5 from both sides:\[x = -3 - 5\]\[x = -8\]
5Step 5: Conclusion
The solutions are the values of \(x\) obtained from both the cases:\[x = -2\] and \[x = -8\]. Therefore, the equation is satisfied for \(x = -2\) and \(x = -8\).
Key Concepts
Isolate the Absolute ValueSolve for xPositive and Negative Cases
Isolate the Absolute Value
When you're solving absolute value equations, the first step is to isolate the absolute value expression. This means you want to get the absolute value term by itself on one side of the equation. In this exercise, we start with the equation:
\[ 3|x+5| + 6 = 15 \]
Our goal is to first get \( |x+5| \) alone on one side.
\[ 3|x+5| + 6 = 15 \]
Our goal is to first get \( |x+5| \) alone on one side.
- Subtract 6 from both sides to eliminate the constant term outside the absolute value. This gives us: \( 3|x+5| = 9 \).
- Next, divide both sides by 3, which simplifies the equation to: \( |x+5| = 3 \). Now the absolute value is completely isolated.
Solve for x
With the absolute value expression now isolated as \( |x+5| = 3 \), the next task is to "solve for x." The absolute value operation creates two distinct scenarios because it represents the distance from zero, which can be either positive or negative.
- First, consider the situation where \( x+5 \) is equal to the positive value of 3. This means solving: \( x+5 = 3 \). By subtracting 5 from both sides, we find: \( x = -2 \).
- Next, handle the scenario where \( x+5 \) equals the negative value, which is \(-3\). Set up the equation: \( x+5 = -3 \). Again, subtract 5 from each side to reveal: \( x = -8 \).
Positive and Negative Cases
When dealing with absolute value equations, understanding that each absolute value equation has two potential solutions due to its nature is essential. Once the absolute value is isolated, it shows distances on a number line that need to be addressed by two scenarios: the positive and the negative cases.
- The positive case assumes the expression inside the absolute value is equal to the positive side. For \( |x+5| = 3 \), this gives \( x+5 = 3 \), leading to \( x = -2 \).
- The negative case deals with when the expression is equal to the negative side. Here, it’s \( x+5 = -3 \), resulting in \( x = -8 \).
Other exercises in this chapter
Problem 16
The given equation is either linear or equivalent to a linear equation. Solve the equation. \(3+\frac{1}{3} X=5\)
View solution Problem 17
Evaluate the expression and write the result in the form a bi. $$ (-6+6 i)+(9-i) $$
View solution Problem 17
Solve the linear inequality. Express the solution using interval notation and graph the solution set. $$ 2 x+1
View solution Problem 17
Solve the equation by completing the square. $$ x^{2}+2 x-5=0 $$
View solution