Problem 16
Question
$$\text { Solve each formula for the indicated variable.}$$ $$\frac{1}{R}=\frac{1}{R_{1}}+\frac{1}{R_{2}} \text { for } R_{2}$$
Step-by-Step Solution
Verified Answer
R_2 = \frac{R R_1}{R_1 - R}
1Step 1 - State the Given Formula
The given formula is: \ \[\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2}\]
2Step 2 - Subtract \(\frac{1}{R_1}\) from Both Sides
To isolate \(\frac{1}{R_2}\), subtract \(\frac{1}{R_1}\) from both sides: \ \[\frac{1}{R} - \frac{1}{R_1} = \frac{1}{R_2}\]
3Step 3 - Combine the Fractions on the Left Side
Combine the terms on the left side by getting a common denominator. The common denominator for \(R\) and \(R_1\) is \(R R_1\): \ \[\frac{R_1 - R}{R R_1} = \frac{1}{R_2}\]
4Step 4 - Invert Both Sides
To solve for \(R_2\), take the reciprocal of both sides: \ \[R_2 = \frac{R R_1}{R_1 - R}\]
Key Concepts
Solving EquationsFractionsFormula IsolationReciprocal
Solving Equations
When we solve equations, we look for the value of a variable that makes the equation true. It's like finding the key to a lock. You must perform the same operation on both sides of the equation to keep it balanced, like a perfectly balanced seesaw. Here's what you need to keep in mind:
- Identify what you need to find (the variable to solve for).
- Make the variable you are solving for the subject of the formula.
- Use arithmetic operations (addition, subtraction, multiplication, and division) to isolate the variable.
Fractions
Fractions can seem tricky, but they are just numbers that represent parts of a whole. Understanding how to work with fractions is essential in algebra. There are a few key operations you need to know:
- Adding/Subtracting Fractions: To add or subtract fractions, they must have the same denominator.
- Multiplying Fractions: Multiply the numerators together and denominators together.
- Dividing Fractions: Multiply by the reciprocal of the divisor.
Formula Isolation
Isolating a formula means rearranging it to make a specific variable the subject. It’s like solving a puzzle where you must move pieces around to reveal the hidden picture. Here’s the general approach:
- Identify the variable that needs to be isolated.
- Use inverse operations to move other terms away from the target variable.
- Perform consistent operations on both sides of the equation.
Reciprocal
The reciprocal of a number is one divided by that number. In fractions, flipping the numerator and denominator gives the reciprocal. This is especially useful in solving equations involving fractions. Here's what to remember:
- Finding Reciprocals: For a fraction \(\frac{a}{b}\), the reciprocal is \(\frac{b}{a}\).
- Using Reciprocals: To solve equations, especially when dividing fractions, because multiplying by a reciprocal is equivalent to division.
- Reciprocal in Equations: Using reciprocals allows us to simplify and solve equations for variables.
Other exercises in this chapter
Problem 15
Perform the indicated operations. Reduce answers to their lowest terms. See Example \(I\) $$ \frac{x^{2}+4 x-6}{x^{2}-9}-\frac{x^{2}+2 x-12}{x^{2}-9} $$
View solution Problem 15
Which real numbers cannot be used in place of the variable in each rational expression? $$\frac{2 a-3}{a^{2}+5 a+6}$$
View solution Problem 16
Find the solution set to each equation. $$\frac{30}{x}=\frac{50}{x+10}+\frac{1}{2}$$
View solution Problem 16
Perform the indicated operations. Reduce answers to their lowest terms. See Example \(I\) $$ \frac{x^{2}+3 x-3}{x-4}-\frac{x^{2}+4 x-7}{x-4} $$
View solution