Problem 16
Question
Solve each exponential equation and express approximate solutions to the nearest hundredth. $$ 2 e^{x}=12.4 $$
Step-by-Step Solution
Verified Answer
The solution is approximately \( x = 1.82 \).
1Step 1: Isolate the Exponential Term
The given equation is \( 2e^{x} = 12.4 \). First, divide both sides by 2 to isolate the exponential term: \[ewecommand{\divide}{\frac{12.4}{2}}\ e^{x} = \divide = 6.2 \]
2Step 2: Apply the Natural Logarithm
To solve for \( x \), take the natural logarithm (ln) of both sides: \[ \ln(e^{x}) = \ln(6.2) \]
3Step 3: Use the Logarithmic Identity
Use the identity \( \ln(e^{x}) = x \) to simplify the left-hand side of the equation:\[ x = \ln(6.2) \]
4Step 4: Calculate the Natural Logarithm
Using a calculator, find the natural logarithm of 6.2:\[ x \approx 1.824 \]
5Step 5: Round to the Nearest Hundredth
Round the approximate solution to the nearest hundredth:\[ x \approx 1.82 \]
Key Concepts
Natural LogarithmSolve Exponential EquationsLogarithmic Identity
Natural Logarithm
The natural logarithm is a mathematical function denoted as \( \ln(x) \). It is the logarithm to the base \( e \), where \( e \) is an irrational constant approximately equal to 2.71828. The natural logarithm is particularly useful in calculus and when dealing with exponential equations because it simplifies equations involving exponentials.
- \( \ln(e) = 1 \) because \( e^1 = e \)
- \( \ln(1) = 0 \) because \( e^0 = 1 \)
Solve Exponential Equations
Solving exponential equations often involves transforming the equation so that the unknown variable is no longer in the exponent. For the equation \( 2e^x = 12.4 \):
- First, isolate the exponential term by dividing both sides by 2, resulting in \( e^x = 6.2 \).
- Then, take the natural logarithm of both sides: \( \ln(e^x) = \ln(6.2) \).
Logarithmic Identity
A critical tool in solving exponential equations is understanding and using logarithmic identities. These identities can simplify complex expressions and are key when working with both exponential and logarithmic equations.
One of the most important identities used in solving exponential equations is \( \ln(e^x) = x \). This identity is derived from the relationship between exponentials and logarithms, where the natural logarithm is the inverse operation of exponentiation.
When you apply this identity to \( \ln(e^x) \), the \( x \) is effectively "brought down" from the exponent, rendering an equation linear, which is beautifully simple to solve. This identity allowed us to simplify \( \ln(e^x) = \ln(6.2) \) to just \( x = \ln(6.2) \) in the step-by-step solution, thereby revealing the answer almost immediately. Familiarity with such identities transforms our problem-solving toolkit, creating shortcuts and solutions that are both efficient and understandable.
One of the most important identities used in solving exponential equations is \( \ln(e^x) = x \). This identity is derived from the relationship between exponentials and logarithms, where the natural logarithm is the inverse operation of exponentiation.
When you apply this identity to \( \ln(e^x) \), the \( x \) is effectively "brought down" from the exponent, rendering an equation linear, which is beautifully simple to solve. This identity allowed us to simplify \( \ln(e^x) = \ln(6.2) \) to just \( x = \ln(6.2) \) in the step-by-step solution, thereby revealing the answer almost immediately. Familiarity with such identities transforms our problem-solving toolkit, creating shortcuts and solutions that are both efficient and understandable.
Other exercises in this chapter
Problem 15
(a) list the domain and range of the function, (b) form the inverse function \(f^{-1}\), and (c) list the domain and range of \(f^{-1}\). $$ f=\\{(1,5),(2,9),(5
View solution Problem 15
Solve each of the equations. $$ 27^{4 x}=9^{x+1} \quad\left\\{\frac{1}{5}\right\\} $$
View solution Problem 16
Use your calculator to find \(x\) when given \(\log x\). Express answers to five significant digits. $$ \log x=0.5517 $$
View solution Problem 16
Write each logarithmic statement in exponential form. For example, \(\log _{2} 8=3\) becomes \(2^{3}=8\) in exponential form. $$ \log _{10} 100,000=5 $$
View solution