Problem 16
Question
Determine the period, amplitude, and shifts (both horizontal and vertical) and draw a graph over the interval \(-5 \leq x \leq 5\) for the functions listed in Problems 16-23. $$ y=3 \cos \frac{x}{2} $$
Step-by-Step Solution
Verified Answer
Amplitude: 3, Period: \(4\pi\), no shifts.
1Step 1: Identify the Standard Form
The function given is \( y = 3 \cos \left( \frac{x}{2} \right) \). The standard form for a cosine function is \( y = A \cos(Bx - C) + D \). In this case, \( A = 3 \), \( B = \frac{1}{2} \), \( C = 0 \), and \( D = 0 \).
2Step 2: Determine the Amplitude
The amplitude of a cosine function \( y = A \cos(Bx - C) + D \) is given by the absolute value of \( A \). Here, \( A = 3 \), so the amplitude is \( 3 \).
3Step 3: Calculate the Period
The period of a cosine function \( y = A \cos(Bx - C) + D \) is calculated as \( \frac{2\pi}{B} \). With \( B = \frac{1}{2} \), the period is \( \frac{2\pi}{\frac{1}{2}} = 4\pi \).
4Step 4: Determine Horizontal and Vertical Shifts
Since \( C = 0 \) and \( D = 0 \), there are no horizontal or vertical shifts. The function \( y = 3 \cos \frac{x}{2} \) has its basic cosine shape centered at zero.
5Step 5: Sketch the Graph
Given the amplitude \( 3 \) and period \( 4\pi \), the function \( y = 3 \cos \frac{x}{2} \) oscillates between \( -3 \) and \( 3 \). The interval \(-5 \leq x \leq 5\) is less than one full period, so the graph will rise and fall following the cosine curve starting from its maximum value at \( x = 0 \).
Key Concepts
AmplitudePeriod of a FunctionCosine FunctionGraphing Trigonometric Functions
Amplitude
The amplitude of a trigonometric function like the cosine function represents half the distance between its maximum and minimum values. It provides a measurement of the height of the oscillation above and below the centerline of the graph.
For the cosine function in standard form \( y = A \cos(Bx - C) + D \), the amplitude is represented by \( |A| \). In this solution example, \( y = 3 \cos \left( \frac{x}{2} \right) \), the amplitude is \( 3 \).
This means the graph oscillates between \( 3 \) and \( -3 \) along the y-axis.
For the cosine function in standard form \( y = A \cos(Bx - C) + D \), the amplitude is represented by \( |A| \). In this solution example, \( y = 3 \cos \left( \frac{x}{2} \right) \), the amplitude is \( 3 \).
This means the graph oscillates between \( 3 \) and \( -3 \) along the y-axis.
- If \( A \) is positive, the graph will start at the maximum value, go down to the minimum, and return to maximum.
- If \( A \) were negative, the graph would start at its minimum value instead.
Period of a Function
The period of a trigonometric function is the horizontal length required for the function to complete one full cycle, returning to the same y-value at which it started. This measurement is critical for recognizing how frequently the function repeats itself over the x-axis.
For the general cosine function \( y = A \cos(Bx - C) + D \), the period is calculated using the formula \( \frac{2\pi}{B} \).
In the provided function, \( y = 3 \cos \left( \frac{x}{2} \right) \), \( B = \frac{1}{2} \). Thus, the period is \( \frac{2\pi}{\frac{1}{2}} = 4\pi \).
For the general cosine function \( y = A \cos(Bx - C) + D \), the period is calculated using the formula \( \frac{2\pi}{B} \).
In the provided function, \( y = 3 \cos \left( \frac{x}{2} \right) \), \( B = \frac{1}{2} \). Thus, the period is \( \frac{2\pi}{\frac{1}{2}} = 4\pi \).
- This means the function completes one cycle over \( 4\pi \) units.
- It's essential in graphing as knowing the period allows you to scale the x-axis properly.
Cosine Function
The cosine function, one of the primary trigonometric functions, is defined in a repeating wave-like pattern. It's known for having its maximum value at the start of its cycle, which is why its graph starts at its peak.
The standard form is \( y = A \cos(Bx - C) + D \), where:
The standard form is \( y = A \cos(Bx - C) + D \), where:
- \( A \) determines the amplitude, or vertical stretch of the graph.
- \( B \) affects the period, changing how quickly the wave repeats.
- \( C \) and \( D \) introduce horizontal and vertical shifts, respectively.
- The amplitude is 3, leading the function to range from -3 to 3.
- The period is \( 4\pi \), altering the speed of repetition.
- There are no shifts, keeping the graph centered on the y-axis.
Graphing Trigonometric Functions
Graphing trigonometric functions is about showcasing how these mathematical expressions represent periodic phenomena. The challenge lies in accurately reflecting amplitudes, periods, and phase shifts. Here's the approach for graphing \( y = 3 \cos \left( \frac{x}{2} \right) \):
- Start by considering the amplitude of 3, which informs how high and low the graph will go on the y-axis.
- Next, consider the period of \( 4\pi \). Your graph should show one full cycle over this interval.
- Note that there are no phase shifts or vertical shifts in this function.
- Split the period into four equal parts to locate key points, like maxima, minima, and intersection with the x-axis. These are usually at \( 0, \pi, 2\pi, 3\pi \), and \( 4\pi \).
Other exercises in this chapter
Problem 15
Express the solution set of the given inequality in interval notation and sketch its graph. $$ \frac{x+4}{x-3} \leq 0 $$
View solution Problem 15
Simplify as much as possible. Be sure to remove all parentheses and reduce all fractions. \((\sqrt{5}+\sqrt{3})(\sqrt{5}-\sqrt{3})\)
View solution Problem 16
In Problems \(11-16\), find the equation of the circle satisfying the given conditions. Center \((3,4)\) and tangent to \(x\)-axis
View solution Problem 16
In Problems \(11-16\), find the inverse of the given function \(f\) and verify that \(f\left(f^{-1}(x)\right)=x\) for all \(x\) in the domain of \(f^{-1}\), and
View solution