Problem 15
Question
Write the expression as one logarithm. $$ \ln y^{3}+\frac{1}{3} \ln \left(x^{3} y^{6}\right)-5 \ln y $$
Step-by-Step Solution
Verified Answer
The expression simplifies to \( \ln x \).
1Step 1: Apply Power Rule for Logarithms
The power rule for logarithms states that \( a \ln b = \ln b^a \). In the expression, \( rac{1}{3} \ln (x^3y^6) \) can be rewritten using this rule. Calculate:\[ \frac{1}{3} \ln (x^3y^6) = \ln (x^3y^6)^{1/3} = \ln (x^{1}y^{2}) \]
2Step 2: Apply Product Rule for Logarithms
The product rule for logarithms states that \( \ln a + \ln b = \ln(ab) \). Use this rule to combine \( \ln y^{3} \) and \( \ln (x^{1}y^{2}) \):\[ \ln y^{3} + \ln (x^{1}y^{2}) = \ln(y^{3} imes x^{1}y^{2}) = \ln(xy^{5}) \]
3Step 3: Apply Quotient Rule for Logarithms
The quotient rule for logarithms states that \( \ln a - \ln b = \ln(\frac{a}{b}) \). Now, combine the resulting logarithm with \( -5 \ln y \) using the quotient rule:\[ \ln(xy^{5}) - 5\ln y = \ln \left( \frac{xy^{5}}{y^{5}} \right) = \ln x \]
4Step 4: Final Expression
After applying these rules, the expression is simplified to one logarithm:\[ \ln x \]
Key Concepts
Power Rule of LogarithmsProduct Rule of LogarithmsQuotient Rule of Logarithms
Power Rule of Logarithms
The power rule of logarithms is a fundamental concept that simplifies expressions involving logarithms with exponents. The rule states that if you have a logarithm of a number raised to a power, you can multiply the power by the logarithm of that number. Mathematically, this is expressed as:
For example, in our original problem, we applied the power rule to \( \frac{1}{3} \ln(x^3y^6) \), converting it to \( \ln(xy^2) \).
This transformation allows for easier manipulation and combination of logarithmic terms, preparing them for further simplification using other logarithmic properties.
- \( \ln(b^a) = a \ln(b) \)
For example, in our original problem, we applied the power rule to \( \frac{1}{3} \ln(x^3y^6) \), converting it to \( \ln(xy^2) \).
This transformation allows for easier manipulation and combination of logarithmic terms, preparing them for further simplification using other logarithmic properties.
Product Rule of Logarithms
The product rule of logarithms helps in combining logarithms of multiplied terms. According to this rule, the sum of logarithms is equivalent to the logarithm of the product of the individual terms:
After applying the rule, these terms were expressed as \( \ln(xy^5) \).
By reducing the number of logarithmic terms, the problem becomes much more manageable and closer to achieving the final simplified expression.
- \( \ln(a) + \ln(b) = \ln(ab) \)
After applying the rule, these terms were expressed as \( \ln(xy^5) \).
By reducing the number of logarithmic terms, the problem becomes much more manageable and closer to achieving the final simplified expression.
Quotient Rule of Logarithms
The quotient rule of logarithms is applied when you need to simplify the difference between two logarithms. This rule states that the difference of logarithms is the logarithm of the quotient of the terms:
It combines \( \ln(xy^5) \) with \(-5 \ln y \), resulting in \( \ln \left(\frac{xy^5}{y^5}\right) \).
After cancellation, the expression simplifies to \( \ln x \), showing how efficient use of logarithmic properties can lead to a concise solution.
- \( \ln(a) - \ln(b) = \ln\left(\frac{a}{b}\right) \)
It combines \( \ln(xy^5) \) with \(-5 \ln y \), resulting in \( \ln \left(\frac{xy^5}{y^5}\right) \).
After cancellation, the expression simplifies to \( \ln x \), showing how efficient use of logarithmic properties can lead to a concise solution.
Other exercises in this chapter
Problem 14
Exer. 5-16: Determine whether the function \(f\) is one-to-one. $$ f(x)=2 x^{3}-4 $$
View solution Problem 14
Sketch the graph of \(f\). $$f(x)=\left(\frac{2}{3}\right)^{x}$$
View solution Problem 15
Find the zeros of \(f\). $$ f(x)=x^{3}\left(4 e^{4 x}\right)+3 x^{2} e^{4 x} $$
View solution Problem 15
Exer. 11-24: Find the exact solution, using common logarithms, and a two- decimal-place approximation of each solution, when appropriate. $$ 2^{-x}=8 $$
View solution