Problem 15
Question
Tell which equation you would use to isolate a variable. Explain your reasoning. $$\begin{aligned} &m+4 n=30\\\ &m-2 n=0 \end{aligned}$$
Step-by-Step Solution
Verified Answer
The second equation \( m-2n=0 \) should be used to isolate a variable. Through manipulation, it gives \( m = 2n \), this expression can then be substituted into the first equation, leading to resolutions for both variables \( m = 10 \) and \( n = 5 \)
1Step 1: Isolate the desired variable
The second equation is chosen because it has a simpler form. Therefore, it's easier to choose any variable between \( m \) and \( n \) to isolate. Let's isolate \( m \) from second equation, which gives: \( m = 2n \).
2Step 2: Substitution
Now that \( m \) has been expressed in terms of \( n \), this expression can be substituted into the first equation. This gives a new equation: \( 2n + 4n = 30 \).
3Step 3: Solve for the Other Variable
Resolve the equation from step 2 to solve for \( n \), the result is \( n = 5 \)
4Step 4: Solve for Isolated Variable
Substitute the value of \( n \) into the equation \( m = 2n \) to find \( m \). The result is \( m = 10 \).
Key Concepts
Substitution MethodIsolating VariablesLinear Equations
Substitution Method
The substitution method is a fundamental technique for solving systems of equations. This method allows you to solve two or more equations by expressing one variable in terms of another. In this approach, you start by rearranging one of the equations to isolate one of the variables. Once you have isolated the variable, it provides a way to substitute this expression into another equation.
Consider the system of equations given in the exercise:
Consider the system of equations given in the exercise:
- Equation 1: \( m + 4n = 30 \)
- Equation 2: \( m - 2n = 0 \)
Isolating Variables
Isolating variables is a crucial step in solving any equation and is particularly useful when applying the substitution method. When you isolate a variable, you rearrange the equation so that the variable you are solving for is by itself on one side of the equation. This helps to simplify complex systems of equations and make substitution possible.
In the exercise, isolating a variable occurs in the second equation, \( m - 2n = 0 \). This equation is selected because it's straightforward to manipulate, allowing us to isolate \( m \) easily. Here's how it's done:
In the exercise, isolating a variable occurs in the second equation, \( m - 2n = 0 \). This equation is selected because it's straightforward to manipulate, allowing us to isolate \( m \) easily. Here's how it's done:
- Identify the variable to isolate. In our case, \( m \).
- Rearrange the equation so that the chosen variable is on one side. For example, adding \( 2n \) to both sides gives: \( m = 2n \).
Linear Equations
Linear equations form the backbone of algebra and are essential in solving systems of equations. A linear equation is any equation that can be written in the form \( ax + by = c \), where \( a \), \( b \), and \( c \) are constants. The equations given in the original exercise are both linear:
- \( m + 4n = 30 \)
- \( m - 2n = 0 \)
- They graph as straight lines on a coordinate plane.
- Each solution of a linear equation corresponds to a point on the line.
- They can be added, subtracted, and manipulated algebraically.
Other exercises in this chapter
Problem 15
Graph the system of linear inequalities. \(2 x+y>2\) \(6 x+3 y
View solution Problem 15
Choose a method to solve the linear system. Explain your choice. $$ \begin{aligned} &-3 x=36\\\ &-6 x+y=1 \end{aligned} $$
View solution Problem 15
Use linear combinations to solve the system of linear equations. $$\begin{aligned} &6.5 x-2.5 y=4.0\\\ &1.5 x+2.5 y=4.0 \end{aligned}$$
View solution Problem 16
Decide whether the ordered pair is a solution of the system of linear equations. $$ \begin{array}{ll} -2 x+y=-11 & \\ -x-9 y=-15 & (6,1) \end{array} $$
View solution