Problem 15
Question
Choose a method to solve the linear system. Explain your choice. $$ \begin{aligned} &-3 x=36\\\ &-6 x+y=1 \end{aligned} $$
Step-by-Step Solution
Verified Answer
The solution to the system is x = -12 and y = -71.
1Step 1: Solve First Equation for x
To solve the first equation for x, we divide both sides of -3x = 36 by -3. This gives us x = -12.
2Step 2: Substitute x in Second Equation
Next, substitute x = -12 into the second equation -6x + y = 1. This gives -6(-12) + y = 1, which simplifies to 72 + y = 1.
3Step 3: Solve for y
Then, to find the value of y, subtract 72 from both sides of the equation 72 + y = 1. This gives y = 1 - 72, and hence y = -71.
Key Concepts
Substitution MethodEquationsVariables
Substitution Method
The substitution method is a powerful way to solve systems of linear equations. It involves solving one of the equations for one variable and substituting this expression into the other equation. This technique allows you to focus on a single variable at a time, simplifying the process dramatically.
Let's look at how this method applies in practice. We started with the equations:
Next, we replaced \(x\) with \(-12\) in the second equation. This step simplified the equation to one involving only the variable \(y\), making it much easier to solve. The substitution method is especially useful when the equations can easily be rearranged to solve for one variable.
Let's look at how this method applies in practice. We started with the equations:
- \(-3x = 36\)
- \(-6x + y = 1\)
Next, we replaced \(x\) with \(-12\) in the second equation. This step simplified the equation to one involving only the variable \(y\), making it much easier to solve. The substitution method is especially useful when the equations can easily be rearranged to solve for one variable.
Equations
In mathematics, equations are statements that assert the equality of two expressions. Solving equations involves finding the values of variables that make the statement true.
In our exercise, we were given two linear equations:
By solving these equations, we're essentially finding the point where these lines intersect. This intersection point gives us the values of \(x\) and \(y\) that satisfy both equations simultaneously.
In our exercise, we were given two linear equations:
- \(-3x = 36\)
- \(-6x + y = 1\)
By solving these equations, we're essentially finding the point where these lines intersect. This intersection point gives us the values of \(x\) and \(y\) that satisfy both equations simultaneously.
Variables
Variables are symbols used to represent numbers whose values aren't yet known. In algebra, they help us create equations and express relationships between different quantities.
In our problem, we dealt with two variables: \(x\) and \(y\). These variables stand for unknown numbers that we need to discover. Initial equations often have more than one variable, each representing a different component of a problem.
By solving the first equation, we identified that \(x = -12\). This value was then substituted into the second equation, allowing us to solve for the second variable, \(y\).
Understanding variables and how they interact in equations is crucial to solving and interpreting mathematical expressions accurately.
In our problem, we dealt with two variables: \(x\) and \(y\). These variables stand for unknown numbers that we need to discover. Initial equations often have more than one variable, each representing a different component of a problem.
By solving the first equation, we identified that \(x = -12\). This value was then substituted into the second equation, allowing us to solve for the second variable, \(y\).
Understanding variables and how they interact in equations is crucial to solving and interpreting mathematical expressions accurately.
Other exercises in this chapter
Problem 15
Decide whether the ordered pair is a solution of the system of linear equations. $$ \begin{array}{ll} -15 x+7 y=1 & (3,5) \\ 3 x-y=1 \end{array} $$
View solution Problem 15
Graph the system of linear inequalities. \(2 x+y>2\) \(6 x+3 y
View solution Problem 15
Tell which equation you would use to isolate a variable. Explain your reasoning. $$\begin{aligned} &m+4 n=30\\\ &m-2 n=0 \end{aligned}$$
View solution Problem 15
Use linear combinations to solve the system of linear equations. $$\begin{aligned} &6.5 x-2.5 y=4.0\\\ &1.5 x+2.5 y=4.0 \end{aligned}$$
View solution