Problem 15
Question
Sketch the graph of the polynomial function. Make sure your graph shows all intercepts and exhibits the proper end behavior. $$ P(x)=(x-3)(x+2)(3 x-2) $$
Step-by-Step Solution
Verified Answer
Plot the x-intercepts \(x = -2, \frac{2}{3}, 3\), the y-intercept \((0,12)\), and show the end behavior.
1Step 1: Identify the factors and roots
The polynomial function given is \( P(x) = (x-3)(x+2)(3x-2) \). To find the roots, set each factor equal to zero: \( x-3=0 \), \( x+2=0 \), and \( 3x-2=0 \). This gives us the roots \( x = 3 \), \( x = -2 \), and \( x = \frac{2}{3} \). These are the x-intercepts of the graph.
2Step 2: Determine the y-intercept
To find the y-intercept, substitute \( x = 0 \) in the polynomial function. \( P(0) = (0-3)(0+2)(3 \times 0 - 2) = (-3)(2)(-2) = 12 \). Thus, the y-intercept is the point \( (0, 12) \).
3Step 3: Analyze the end behavior
The end behavior is determined by the leading term when the polynomial is expanded. The leading term is obtained by multiplying the leading terms of each factor: \( x \cdot x \cdot 3x = 3x^3 \). Since the leading term is \( 3x^3 \), a positive cubic, the end behavior is: as \( x \to \infty \), \( P(x) \to \infty \) and as \( x \to -\infty \), \( P(x) \to -\infty \).
4Step 4: Sketch the graph
Plot the intercepts: the roots \((3,0)\), \((-2,0)\), and \((\frac{2}{3},0)\) and the y-intercept \((0,12)\). Use the end behavior to sketch the curve: starting from below the x-axis moving upward through \(-2\), reaching above the x-axis at the y-intercept, crossing back through \(\frac{2}{3}\) and continuing in a downward trend, then curving upward through \(3\). The graph will have a general 'S' shape consistent with cubic functions.
Key Concepts
Roots of PolynomialEnd Behavior of PolynomialsIntercepts of GraphsCubic Functions
Roots of Polynomial
In polynomial graphing, identifying the roots of the polynomial is an essential first step. Roots of a polynomial are the x-values where the polynomial intersects the x-axis, also known as the x-intercepts. For a function like \(P(x) = (x-3)(x+2)(3x-2)\), we can determine the roots by setting each factor equal to zero. Here's how it breaks down:
- For \(x-3=0\), solve to get \(x = 3\).
- For \(x+2=0\), solve to get \(x = -2\).
- For \(3x-2=0\), solve to get \(x = \frac{2}{3}\).
End Behavior of Polynomials
The end behavior of a polynomial describes how the graph behaves as \(x\) approaches infinity or negative infinity. This is crucial for understanding the overall direction and shape of the graph. In our case, we focus on the polynomial \(3x^3\) because it is the term with the highest degree and defines the polynomial's leading behavior.
- A positive leading coefficient with an odd degree, like \(3x^3\), means as \(x \to \infty\), \(P(x) \to \infty\) and as \(x \to -\infty\), \(P(x) \to -\infty\).
Intercepts of Graphs
Intercepts are crucial points on a polynomial graph, indicating where the graph crosses the axes. These intersections include both x-intercepts and the y-intercept. For our polynomial function \((x-3)(x+2)(3x-2)\), we already know the x-intercepts:
- \(x = 3\)
- \(x = -2\)
- \(x = \frac{2}{3}\)
Cubic Functions
Cubic functions are polynomials of degree three, taking the general form \(ax^3 + bx^2 + cx + d\). These functions have a distinctive 'S' shaped curve, due to their end behavior which is influenced primarily by their highest degree term. For example, consider the polynomial function \(P(x) = (x-3)(x+2)(3x-2)\). After expanding, the leading term is \(3x^3\).
- This leading term suggests a classic cubic shape: crossing the x-axis three times at its roots.
Other exercises in this chapter
Problem 15
Find the quotient and remainder using long division. \(\frac{x^{3}+3 x^{2}+4 x+3}{3 x+6}\)
View solution Problem 15
Find all rational zeros of the polynomial. $$ P(x)=x^{3}-6 x^{2}+12 x-8 $$
View solution Problem 16
13- 30 . Factor the polynomial completely and find all its zeros. State the multiplicity of each zero. $$ Q(x)=x^{2}-8 x+17 $$
View solution Problem 16
Find all horizontal and vertical asymptotes (if any). \(s(x)=\frac{2 x+3}{x-1}\)
View solution