Problem 15
Question
Find the exact value of the trigonometric function at the given real number. $$ \begin{array}{llll}{\text { (a) } \tan \frac{5 \pi}{6}} & {\text { (b) } \tan \frac{7 \pi}{6}} & {\text { (c) } \tan \frac{11 \pi}{6}}\end{array} $$
Step-by-Step Solution
Verified Answer
(a) \(-\frac{\sqrt{3}}{3}\), (b) \(\frac{\sqrt{3}}{3}\), (c) \(-\frac{\sqrt{3}}{3}\).
1Step 1: Determine the Reference Angle for (a)
For \( \tan \frac{5\pi}{6} \), we start by finding the reference angle. The angle \( \frac{5\pi}{6} \) is in the second quadrant. The reference angle is \( \pi - \frac{5\pi}{6} = \frac{\pi}{6} \).
2Step 2: Identify the Sign of Tangent for (a)
In the second quadrant, the tangent function is negative. Thus, \( \tan \frac{5\pi}{6} = - \tan \frac{\pi}{6} \). Since \( \tan \frac{\pi}{6} = \frac{1}{\sqrt{3}} \) or \( \frac{\sqrt{3}}{3} \), \( \tan \frac{5\pi}{6} = -\frac{\sqrt{3}}{3} \).
3Step 3: Determine the Reference Angle for (b)
For \( \tan \frac{7\pi}{6} \), the angle is in the third quadrant. The reference angle here is \( \frac{7\pi}{6} - \pi = \frac{\pi}{6} \).
4Step 4: Identify the Sign of Tangent for (b)
In the third quadrant, tangent is positive. So, \( \tan \frac{7\pi}{6} = \tan \frac{\pi}{6} = \frac{\sqrt{3}}{3} \).
5Step 5: Determine the Reference Angle for (c)
For \( \tan \frac{11\pi}{6} \), we find that the angle is in the fourth quadrant. The reference angle is \( 2\pi - \frac{11\pi}{6} = \frac{\pi}{6} \).
6Step 6: Identify the Sign of Tangent for (c)
In the fourth quadrant, the tangent is negative. Therefore, \( \tan \frac{11\pi}{6} = -\tan \frac{\pi}{6} = -\frac{\sqrt{3}}{3} \).
Key Concepts
Tangent FunctionReference AngleQuadrant AnalysisExact Values
Tangent Function
The tangent function, often denoted as \( \tan \theta \), is one of the six primary trigonometric functions. It relates the angle in a right triangle to the ratio of the opposite side over the adjacent side. In the unit circle, it is represented as the ratio of the sine and cosine of an angle, given by \( \tan \theta = \frac{\sin \theta}{\cos \theta} \).
- It shows periodic behavior, with a period of \( \pi \), meaning that \( \tan(\theta + \pi) = \tan \theta \).
- Unlike sine and cosine, the tangent function can take any real value, and it is undefined where \( \cos \theta = 0 \).
Reference Angle
A reference angle is the smallest angle a given angle makes with the x-axis. It is always acute, meaning that it is between 0 and \( \frac{\pi}{2} \) radians (or 0 and 90 degrees).
- It is essential because it allows the calculation of trigonometric functions of any angle using their known values for acute angles.
- The reference angle can be found by subtracting the given angle from \( \pi \) or \( 2\pi \), depending on which quadrant the angle lies in. For instance, for an angle in the second quadrant \( \text{(like } \frac{5\pi}{6}\text{)} \), the reference angle is \( \pi - \frac{5\pi}{6} = \frac{\pi}{6} \).
Quadrant Analysis
Quadrant analysis is the study of how the signs of trigonometric functions vary according to the quadrant in which their angles lie. The unit circle is divided into four quadrants:
- First Quadrant (0 to \( \frac{\pi}{2} \)): All trigonometric functions are positive.
- Second Quadrant (\( \frac{\pi}{2} \) to \( \pi \)): Sine is positive, but cosine and tangent are negative.
- Third Quadrant (\( \pi \) to \( \frac{3\pi}{2} \)): Tangent is positive, while sine and cosine are negative.
- Fourth Quadrant (\( \frac{3\pi}{2} \) to \( 2\pi \)): Cosine is positive, and sine and tangent are negative.
Exact Values
Exact values in trigonometry refer to the precise, accurate values of trigonometric functions at specific angles. These angles usually include \( \frac{\pi}{6} \), \( \frac{\pi}{4} \), \( \frac{\pi}{3} \), etc., which correspond to 30°, 45°, and 60° in degrees.
- These values are derived from geometric relations of special triangles like the 30-60-90 and 45-45-90 triangles.
- Using these exact values, it becomes possible to compute the trigonometric functions of any angle by recognizing its reference angle and corresponding quadrant.
Other exercises in this chapter
Problem 14
7–52 Find the period and graph the function. $$y=\frac{1}{2} \csc x$$
View solution Problem 14
\(13-18=\) The point \(P\) is on the unit circle. Find \(P(x, y)\) from the given information. The \(y\) -coordinate of \(P\) is \(-\frac{1}{3}\) and the \(x\)
View solution Problem 15
Find the amplitude and period of the function, and sketch its graph. $$ y=\cos 2 x $$
View solution Problem 15
7–52 Find the period and graph the function. $$y=3 \sec x$$
View solution