Problem 15
Question
Find each quotient $$ \frac{a^{7}}{a} $$
Step-by-Step Solution
Verified Answer
Answer: The quotient of the expression $$\frac{a^{7}}{a}$$ is $$a^6$$.
1Step 1: Identify the Exponents
In the given expression, the base is 'a' and the exponents are 7 and 1 respectively: $$a^7$$ and $$a^1$$.
2Step 2: Apply Quotient Rule for Exponents
According to the quotient rule, subtract the exponent in the denominator from the exponent in the numerator with the same base: $$a^m \div a^n = a^{m-n}$$. In this case, $$a^7 \div a^1 = a^{7-1} $$.
3Step 3: Simplify the Expression
Subtract the exponents as shown in the previous step to arrive at the simplified expression: $$a^{7-1} = a^6$$.
The quotient of the given expression $$\frac{a^{7}}{a}$$ is $$a^6$$.
Key Concepts
Understanding ExponentsThe Art of SimplificationAlgebraic Expressions and Their Simplifications
Understanding Exponents
Exponents provide a way to express repeated multiplication of a number by itself. In the expression \(a^7\), "7" is the exponent, and it tells us how many times "a" is multiplied by itself. This is read as "a raised to the power of 7." Similarly, in \(a^1\), the exponent is 1, which means "a" is used just once, essentially, it remains "a."
- The base "a": The number being multiplied.
- Exponent 7: The number of times "a" appears in the multiplication.
- Exponent 1: Indicates the number "a" exists singularly.
The Art of Simplification
Simplification is the process of making an expression easier to work with while maintaining its original value. When it comes to expressions with exponents, simplification often involves applying certain rules like the quotient rule.
In our given expression \(\frac{a^{7}}{a}\), simplification involves reducing the complexity by handling the exponents. When you apply the quotient rule, you focus on the exponents of the same base to perform subtraction. Here it means \(a^{7-1}\). It is crucial because it turns a potentially confusing fraction into a straightforward expression, \(a^6\), which is much easier to understand and use. Remember, simpler forms are not just neat; they are essential for further operations.
In our given expression \(\frac{a^{7}}{a}\), simplification involves reducing the complexity by handling the exponents. When you apply the quotient rule, you focus on the exponents of the same base to perform subtraction. Here it means \(a^{7-1}\). It is crucial because it turns a potentially confusing fraction into a straightforward expression, \(a^6\), which is much easier to understand and use. Remember, simpler forms are not just neat; they are essential for further operations.
Algebraic Expressions and Their Simplifications
Algebraic expressions can have variables, constants, and exponents. In any simplified algebraic expression like the one found here, understanding the role of each part is key.
Consider the original expression \(\frac{a^{7}}{a}\). It is an algebraic expression composed of a single variable "a" raised to different powers. To simplify such expressions, you use algebraic rules and properties, including the exponent rules.
Consider the original expression \(\frac{a^{7}}{a}\). It is an algebraic expression composed of a single variable "a" raised to different powers. To simplify such expressions, you use algebraic rules and properties, including the exponent rules.
- Quotient Rule: For same base division, subtract exponents: \(a^m \div a^n = a^{m-n}\).
- Result: Fewer terms and easier calculations, like going from \(a^{7}\) divided by \(a\) to \(a^6\).
Other exercises in this chapter
Problem 14
For the following problems, use the order of operations to find each value. $$3(8+2) \div 6+3$$
View solution Problem 15
For the following problems, write the appropriate relation symbol \((=,)\) in place of the \(*\). $$ 9[4+3(8)] * 6[1+8(5)] $$
View solution Problem 15
Make use of the power rule for quotients, the power rule for products, the power rule for powers, or a combination of these rules to simplify each expression. $
View solution Problem 15
For the following problems, write each of the quantities using exponential notation. \(x\) to the eighth
View solution