Problem 15
Question
Determine whether the equation defines \(y\) as a function of \(x\) or defines \(x\) as a function of \(y\) $$3 x+2 y=12$$
Step-by-Step Solution
Verified Answer
Answer: Yes, the equation can be expressed as both y being a function of x (y = -3/2x + 6) and x being a function of y (x = -2/3y + 4).
1Step 1: Express y in terms of x
To check if y is a function of x, let's try to rewrite the equation in a way that isolates y. This will allow us to see if y can be expressed as a function of x.
$$3x+2y=12$$
$$2y=-3x+12$$
$$y=-\frac{3}{2}x+6$$
This expression shows that y can be represented as a function of x.
2Step 2: Express x in terms of y
Similarly, we can try to express x in terms of y to check if x can be as a function of y.
$$3x+2y=12$$
$$3x=-2y+12$$
$$x=-\frac{2}{3}y+4$$
This expression also demonstrates that x can be represented as a function of y.
3Step 3: Conclusion
Through the process of isolating y and x in the given equation, we found that both scenarios are possible. The equation can represent y as a function of x (y = -\frac{3}{2}x+6) as well as x as a function of y (x = -\frac{2}{3}y+4).
Key Concepts
RelationsLinear EquationsExpression of Variables
Relations
When exploring mathematical relations, it's essential to understand the bond between two entities, such as variables. A relation in mathematics is any set of ordered pairs, where each pair connects particular elements from two sets. In the exercise provided, we have the equation \(3x + 2y = 12\), which forms a relation between \(x\) and \(y\). This relation indicates how \(x\) and \(y\) are linked through the given equation.
In this specific relation:
In this specific relation:
- \(x\) is known as the independent variable because we can choose its values freely.
- \(y\) is generally the dependent variable because its value depends on \(x\).
- Both variables can define one another under certain conditions, which is explored in the solution step-by-step.
Linear Equations
Linear equations are straightforward but crucial concepts in algebra. They have a strong presence in many mathematical applications because they create straight lines when graphed on a coordinate plane. The equation \(3x + 2y = 12\) is a classic example of a linear equation with two variables. The terms in linear equations are either constants or products of a constant and a single variable.
Let's review the essential features of linear equations:
Let's review the essential features of linear equations:
- Each equation forms a straight line, characterized by its slope and y-intercept when in slope-intercept form \(y = mx + b\).
- The linear equation \(3x + 2y = 12\) can be rewritten in this form to find the slope \(-\frac{3}{2}\) and y-intercept \(6\).
- This equation can be manipulated to isolate either \(x\) or \(y\), showing flexibility in uncovering the function relationship.
Expression of Variables
The expression of variables is a technique where we manipulate equations to "solve for" a particular variable. In this exercise, both \(x\) and \(y\) are expressed in terms of one another, demonstrating their functional relationships.
To express a variable:
To express a variable:
- Identify the variable you want to isolate. For instance, when we express \(y\) in terms of \(x\), we rearrange the equation \(3x + 2y = 12\) to get \(y = -\frac{3}{2}x + 6\).
- This equation now explicitly defines \(y\) as a function of \(x\), showing how \(y\) changes with different \(x\).
- Similarly, expressing \(x\) as \(-\frac{2}{3}y + 4\) illustrates \(x\) as a function of \(y\).
Other exercises in this chapter
Problem 15
Find the indicated values, where $$ g(t)=t^{2}-t \text { and } f(x)=1+x B$$ $$g(f(2)+3)$$
View solution Problem 15
Refer to these three functions: $$ \begin{aligned} f(x) &=\sqrt{x+3}-x+1 \\ g(t) &=t^{2}-1 \\ h(x) &=x^{2}+\frac{1}{x}+2 \end{aligned} $$ In each case, find the
View solution Problem 16
Use algebra to find the inverse of the given one-to-one function. $$f(x)=5+\sqrt{3 x-2}$$
View solution Problem 16
Find the average rate of change of the function f over the given interval. $$f(x)=\sqrt{x^{3}+2 x^{2}-6 x+5} \text { from } x=1 \text { to } x=1.00001$$
View solution