Problem 14
Question
In Exercises \(1-16,\) solve and check each linear equation. $$ 5 x-(2 x+2)=x+(3 x-5) $$
Step-by-Step Solution
Verified Answer
\(x = 3\)
1Step 1: Simplify the Equation
Start by simplifying both sides of the equation independently. On the left side simplify \(5x - (2x+2)\) and on the right side simplify \(x + (3x - 5)\). This results in \(3x - 2 = 4x - 5\).
2Step 2: Isolate the Variable Terms
Arrange the equation in such a way that the coefficients of \(x\) are on one side and the constants are on the other side. This can be achieved by subtracting \(3x\) from both sides resulting in \(x = 3\).
3Step 3: Validate the Solution
Validate this solution by substituting \(x = 3\) into the original equation \(5x - (2x + 2) = x + (3x - 5)\). If both sides of the equation are equal, then the solution is correct.
Key Concepts
Linear EquationAlgebraic ManipulationEquation SimplificationVariable Isolation
Linear Equation
A linear equation is an algebraic equation in which each term is either a constant or the product of a constant and a single variable. Linear equations are used widely in various fields. They can represent simple relationships, like the total cost of apples based on the number of kilograms purchased.
In the given exercise, the equation
In the given exercise, the equation
5x - (2x + 2) = x + (3x - 5) is a straightforward example of a linear equation, which has a single variable, x. The main goal when working with linear equations is to find the value of the variable that makes the equation true. This is often referred to as 'solving' the equation.Algebraic Manipulation
Algebraic manipulation involves using various algebraic techniques to alter the form of an algebraic expression or equation without changing its value.
These techniques include distributing multiplication over addition, combining like terms, and using properties of equality to maintain the balance of an equation. In our initial step, distributing multiplication over addition involves expanding
These techniques include distributing multiplication over addition, combining like terms, and using properties of equality to maintain the balance of an equation. In our initial step, distributing multiplication over addition involves expanding
(2x + 2) and (3x - 5), to integrate these terms with others on their respective sides of the equation. Algebraic manipulation is key in simplifying equations to make solving for the variable more straightforward.Equation Simplification
Equation simplification is a pivotal part of solving linear equations. This process includes combining like terms and reducing equations to their simplest form, which often makes subsequent steps much easier.
In our equation, simplifying both sides separately resulted in
In our equation, simplifying both sides separately resulted in
3x - 2 = 4x - 5. By doing this, we eliminated unnecessary complexity and prepared the equation for the next step, which involved isolating the variable. Simplification may involve adding or subtracting terms on one or both sides, multiplying or dividing, or even factoring. The key is to always strive for the simplest form that accurately represents the original equation.Variable Isolation
Variable isolation is the ultimate step in solving a linear equation. It involves rearranging the equation in such a way that the variable you're solving for is alone on one side of the equation.
In the solution provided, isolating the variable
In the solution provided, isolating the variable
x was achieved by subtracting 3x from both sides of the simplified equation. This left x on one side and the solution to the equation, 3, on the other side. 3 = 3 is our final check, making sure that the solution is consistent and satisfies the given linear equation. Isolating the variable not only yields the solution but it also provides an easy way to check if the solution is correct by plugging it back into the original equation.Other exercises in this chapter
Problem 14
In Exercises 13-26, express each interval in terms of an inequality and graph the interval on a number line. $$(-2,4]$$
View solution Problem 14
Let \(x\) represent the number. Write each English phrase as an algebraic expression. Five times the difference of a number and 6
View solution Problem 15
In Exercises \(9-20,\) find each product and write the result in standard form. $$(3+5 i)(3-5 i)$$
View solution Problem 15
Solve each quadratic inequality in Exercises \(1-28\) and graph the solution set on a real number line. Express each solution set in interval notation. $$ 2 x^{
View solution