Problem 14
Question
Find a function that models the simple harmonic motion having the given properties. Assume that the displacement is at its maximum at time \(t=0\) . amplitude 35 cm, period 8 s
Step-by-Step Solution
Verified Answer
The function modeling this simple harmonic motion is \( y(t) = 35 \cos\left(\frac{\pi}{4} t\right) \).
1Step 1: Understand Simple Harmonic Motion
Simple harmonic motion is typically modeled by a trigonometric function such as a sine or cosine function. Since the maximum displacement occurs at time \( t = 0 \), we will use a cosine function, because \( \cos(0) = 1 \).
2Step 2: Write the General Cosine Function for SHM
The general equation for simple harmonic motion using a cosine function is \( y(t) = A \cos(\omega t + \phi) \), where \( A \) is the amplitude, \( \omega \) is the angular frequency, and \( \phi \) is the phase shift. In this problem, the phase shift \( \phi = 0 \) because the maximum displacement is at \( t = 0 \).
3Step 3: Determine Amplitude
We are given the amplitude as 35 cm. Therefore, in our function, \( A = 35 \).
4Step 4: Calculate the Angular Frequency
The angular frequency \( \omega \) is related to the period \( T \) by the equation \( \omega = \frac{2\pi}{T} \). Here, the period \( T = 8 \) s, thus \( \omega = \frac{2\pi}{8} = \frac{\pi}{4} \).
5Step 5: Write the Complete Function
Substituting the values calculated: amplitude \( A = 35 \), angular frequency \( \omega = \frac{\pi}{4} \), and no phase shift, the function is given by \( y(t) = 35 \cos\left(\frac{\pi}{4} t\right) \).
Key Concepts
Amplitude: The Height of VibrationTrigonometric Function: The Motion DescribersAngular Frequency: The Speed of the Cycle
Amplitude: The Height of Vibration
In simple harmonic motion, amplitude refers to the maximum displacement of an object from its equilibrium position. Imagine it as the distance from the center to the farthest point of a swinging pendulum. Amplitude is important because it tells us how far the object travels during its motion.
- In our exercise, the amplitude is given as 35 cm. This value determines the peak displacements the function will achieve, above and below the equilibrium position.
- The larger the amplitude, the more energy the system has since it is moving a longer distance.
Trigonometric Function: The Motion Describers
Trigonometric functions like sine and cosine are tools used to model oscillatory or wave-like movements, making them perfect for simple harmonic motion. These functions repeat their values in a cyclical pattern because of their periodic nature.
- The cosine function is often used when the motion starts at the maximum displacement or peak because \(\cos(0) = 1\).
- In the context of the problem, the cosine function is ideal since the displacement is maximal at time \(t = 0\).
Angular Frequency: The Speed of the Cycle
Angular frequency is a measure of how quickly the motion cycles through its pattern. It tells us the rate at which the object goes through its full cycle, equivalent to \(2\pi\) radians per cycle. Mathematically, it's calculated using the relationship \(\omega = \frac{2\pi}{T}\), where \(T\) is the period of the motion in seconds.
- In the given problem, the period \(T\) is 8 seconds, leading to an angular frequency of \(\omega = \frac{\pi}{4}\).
- This means every 8 seconds, the system completes a full oscillation, moving swiftly or slowly depending on the period.
Other exercises in this chapter
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