Problem 14
Question
Find a counterexample to show that the statement is not true. If \(a, b,\) and \(c\) are nonzero real numbers, then \((a \div b) \div c=a \div(b \div c)\) (Note: The counterexample shows that the associative property does not hold for division.)
Step-by-Step Solution
Verified Answer
A counterexample can be \(a = 2\), \(b = 3\), \(c = 4\). As the results of \( (2 \div 3) \div 4 \) equals \( \frac{1}{6} \) and \( 2 \div (3 \div 4) \) equals \( \frac{8}{3} \) are clearly not equal. This shows that the associative property does not hold for division.
1Step 1: Choosing Real Numbers
Let's select any three nonzero real numbers, for instance \(a = 2\), \(b = 3\), \(c = 4\).
2Step 2: Calculation For \( (a \div b) \div c \)
Substitute the selected numbers into the first equation \( (a \div b) \div c \). Then, calculate \( (2 \div 3) \div 4 \), which equals to \( \frac{2}{3} \div 4 = \frac{2}{12} = \frac{1}{6}.\)
3Step 3: Calculation For \( a \div (b \div c) \)
Substitute the selected numbers into the second equation \( a \div (b \div c) \). Then, calculate \( 2 \div (\frac{3}{4}) = 2 \div 0.75 = \frac{8}{3}.\)
4Step 4: Compare Both Results
Comparison of both results shows they are not equivalent. \( \frac{1}{6} \) is not equal to \( \frac{8}{3} \), hence the statement \( (a \div b) \div c = a \div (b \div c) \) is not always true. This proves that the associative property does not hold for division.
Key Concepts
Understanding Nonzero Real NumbersThe Basics of DivisionWhat is a Counterexample?
Understanding Nonzero Real Numbers
When dealing with mathematical problems, especially those involving division, it is important to understand the concept of nonzero real numbers. Nonzero real numbers are simply all real numbers except for zero.
They can be either positive or negative, and include fractions and decimals as well. Why is it important that we discuss nonzero numbers? Because when you divide by zero, the operation becomes undefined. You can't perform division with zero as the divisor. This is why, in the provided exercise, we only use nonzero real numbers for calculation.
Real numbers can be:
They can be either positive or negative, and include fractions and decimals as well. Why is it important that we discuss nonzero numbers? Because when you divide by zero, the operation becomes undefined. You can't perform division with zero as the divisor. This is why, in the provided exercise, we only use nonzero real numbers for calculation.
Real numbers can be:
- Whole numbers like 1, 2, 3
- Fractions such as 1/2, 2/3
- Decimals like 0.5, 3.75
The Basics of Division
Division is one of the four fundamental arithmetic operations, and it essentially involves splitting a number into equal parts. Think of it as distributing items evenly. When you see notation like \(a \div b\), it means how many times \(b\) fits into \(a\).
Though division is generally straightforward, it possesses some intriguing properties:
Though division is generally straightforward, it possesses some intriguing properties:
- It is not commutative. Changing the order of division changes the result: \(a \div b eq b \div a\).
- Division is not associative, meaning that reorganizing terms can change the outcome, as seen in the exercise with the counterexample.
What is a Counterexample?
A counterexample is a specific case used to show that a general statement is false.
In mathematics, it can be quite powerful because it takes only one counterexample to disprove a universal statement.In our exercise, we were given the statement: "If \(a, b,\) and \(c\) are nonzero real numbers, then \((a \div b) \div c = a \div (b \div c)\)."Using the numbers \(a=2\), \(b=3\), and \(c=4\), we found:
In mathematics, it can be quite powerful because it takes only one counterexample to disprove a universal statement.In our exercise, we were given the statement: "If \(a, b,\) and \(c\) are nonzero real numbers, then \((a \div b) \div c = a \div (b \div c)\)."Using the numbers \(a=2\), \(b=3\), and \(c=4\), we found:
- \((2 \div 3) \div 4 = \frac{1}{6}\)
- \(2 \div (3 \div 4) = \frac{8}{3}\)
Other exercises in this chapter
Problem 13
Solve the equation. Check for extraneous solutions. $$ -5+\sqrt{x}=0 $$
View solution Problem 13
Find the domain and the range of the function. $$y=\sqrt{x+5}$$
View solution Problem 14
Find the distance between the two points. Round your solution to the nearest hundredth if necessary. $$ (-3,1),(2,6) $$
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USING THE PYTHAGOREAN THEOREM Find the missing length of the right triangle if \(a\) and \(b\) are the lengths of the legs and \(c\) is the length of the hypote
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