Problem 13
Question
Find the domain and the range of the function. $$y=\sqrt{x+5}$$
Step-by-Step Solution
Verified Answer
The domain of the function is \(x\geq -5\) and the range of the function is \(y\geq 0\)
1Step 1: Determine the Domain
The domain of a function consists of all possible input values. For a square root function, such as this one, the expression under the square root (the radicand) must be greater than or equal to zero, because the square root of a negative number doesn't result in a real number. Hence we get the inequality: \(x+5\geq 0\) . Solve this inequality for x which gives \(x\geq -5\). So the domain of the function is all real numbers greater than or equal to -5.
2Step 2: Determine the Range
The range of a function contains all possible output values. For a square root function, this represents possible values of y. Since taking the square root doesn't result in negative values, the range of a square root function is always greater than or equal to zero (as long as the domain doesn't restrict it further). Hence the range of the function is \(y\geq 0\).
Other exercises in this chapter
Problem 13
Simplify the expression. $$ 5 \sqrt{7}+2 \sqrt{7} $$
View solution Problem 13
Solve the equation. Check for extraneous solutions. $$ -5+\sqrt{x}=0 $$
View solution Problem 14
Find a counterexample to show that the statement is not true. If \(a, b,\) and \(c\) are nonzero real numbers, then \((a \div b) \div c=a \div(b \div c)\) (Note
View solution Problem 14
Find the distance between the two points. Round your solution to the nearest hundredth if necessary. $$ (-3,1),(2,6) $$
View solution