Problem 133
Question
Assertion: If \(a, b, c, d \in R+\) and \(a, b, c, d\) are in H.P., then \(b+c>a+d\) Reason: H.M > A.M. for unequal numbers
Step-by-Step Solution
Verified Answer
The assertion is incorrect when numbers are in H.P.; due to the inequality nature.
1Step 1: Understanding Harmonic Progression
A harmonic progression (H.P.) is a sequence of numbers where the reciprocals are in arithmetic progression (A.P.). If \(a, b, c, d\) are in H.P., then \(\frac{1}{a}, \frac{1}{b}, \frac{1}{c}, \frac{1}{d}\) are in A.P.
2Step 2: Using the Reasoning
The reason states that harmonic mean (H.M.) is less than arithmetic mean (A.M.) for unequal numbers. This means \(H.M. < A.M.\) implying \(\frac{1}{A} \left(= \frac{4abcd}{abc + abd + acd + bcd}\right) < A.M. \left(= \frac{a + b + c + d}{4}\right)\).
3Step 3: Convert the Assertion
To prove \(b+c>a+d\), we should use the property of H.P. that the sum of the product of terms excluding two adjacent terms and the product of the two adjacent terms; i.e., \((b+c) \cdot (a+d) > a \cdot d\).
4Step 4: Evaluating H.M. and A.M.
For H.P., means like H.M. calculated using reciprocals give inequalities. Given \(b + c \cdot (a + d) > a \cdot d\), rearrange to achieve \(b+c > a+d\) under suitable conditions.
Key Concepts
Harmonic MeanArithmetic MeanInequality of Means
Harmonic Mean
The harmonic mean (H.M.) is a type of average that is especially useful when dealing with rates or ratios. To find the harmonic mean of a set of numbers, you use the reciprocals of the numbers. For example, if you have numbers \(a, b, c, d\), the harmonic mean \(H\) is given by the formula:
- \( H = \frac{n}{{\frac{1}{a} + \frac{1}{b} + \frac{1}{c} + \frac{1}{d}}} \)
Arithmetic Mean
Arithmetic mean (A.M.) is often what people simply call the "average". It’s computed by summing all the given numbers and dividing by the count of numbers. For four numbers \(a, b, c, d\), the formula for the arithmetic mean \(A\) is:
- \( A = \frac{a + b + c + d}{4} \)
Inequality of Means
The inequality of means is a mathematical principle that states the harmonic mean is less than or equal to the arithmetic mean for a set of non-equal positive numbers. This can be expressed as:
- \( H.M. \leq A.M. \)
Other exercises in this chapter
Problem 130
\begin{tabular}{l} Column-I & Column-II \\ \hline I. If \(a, b, c\) are in A.P., \(b, c, d\) are in G.P. and \(c, d, e\) are in H.P., then (A) A.P. \\ \(\qquad
View solution Problem 132
Assertion: If \(a, b, c\) are distinct positive real numbers and \(a^{2}+b^{2}+c^{2}=1\), then \(a b+b c+c a\) is less than 1 . Reason: A.M. >G.M. for unequal n
View solution Problem 136
Assertion: For every natural number \(n,(n !)^{3}\) G.M. for \(n\) distinct positive quantities
View solution Problem 138
The value of \(2^{1 / 4} \cdot 4^{1 / 8} \cdot 8^{1 / 16} \ldots \infty\) is: (A) 1 (B) 2 (C) \(3 / 2\) (D) 4
View solution