Problem 13
Question
In Exercises 13-16, find the measure of the angle between the two vectors in both radians and degrees. \(\vec{u}=\langle 1,1\rangle, \vec{v}=\langle 1,2\rangle\)
Step-by-Step Solution
Verified Answer
The angle is approximately 0.6435 radians or 36.87 degrees.
1Step 1: Find the Dot Product
The dot product of two vectors \(\vec{u}=\langle a_1, a_2 \rangle\) and \(\vec{v}=\langle b_1, b_2 \rangle\) is found using the formula \(\vec{u} \cdot \vec{v} = a_1b_1 + a_2b_2\). Substitute \(a_1=1, a_2=1\) and \(b_1=1, b_2=2\) into the formula: \(1\cdot1 + 1\cdot2 = 1 + 2 = 3\). Thus, the dot product is 3.
2Step 2: Find the Magnitudes of the Vectors
The magnitude of a vector \(\vec{u}=\langle a_1, a_2 \rangle\) is calculated as \(\|\vec{u}\| = \sqrt{a_1^2 + a_2^2}\). Apply this formula to \(\vec{u}\): \(\|\vec{u}\| = \sqrt{1^2 + 1^2} = \sqrt{2}\). For \(\vec{v}\), \(\|\vec{v}\| = \sqrt{1^2 + 2^2} = \sqrt{5}\).
3Step 3: Calculate the Cosine of the Angle
The cosine of the angle \(\theta\) between vectors \(\vec{u}\) and \(\vec{v}\) is given by \(\cos \theta = \frac{\vec{u} \cdot \vec{v}}{\|\vec{u}\|\|\vec{v}\|}\). Substitute the dot product and magnitudes: \( \cos \theta = \frac{3}{\sqrt{2}\sqrt{5}} = \frac{3}{\sqrt{10}}\).
4Step 4: Solve for the Angle in Radians
Find \(\theta\) by taking the inverse cosine: \(\theta = \cos^{-1} \left(\frac{3}{\sqrt{10}}\right)\). Using a calculator, find \(\theta\). This value is the angle in radians. \(\theta \approx 0.6435\) radians.
5Step 5: Convert the Angle to Degrees
To convert the angle from radians to degrees, use the formula: degrees = radians \(\times \frac{180}{\pi}\). Therefore, \(\theta = 0.6435 \times \frac{180}{\pi} \approx 36.87\) degrees.
Key Concepts
Dot ProductVector MagnitudeAngle Between VectorsRadians and Degrees Conversion
Dot Product
The dot product is a fundamental concept in vector calculus, often forming the starting point in problems involving both direction and magnitude. It is a scalar quantity resulting from the operation applied to two vectors.
For vectors \(\vec{u} = \langle a_1, a_2 \rangle\) and \(\vec{v} = \langle b_1, b_2 \rangle\), the dot product \(\vec{u} \cdot \vec{v}\) is computed using the formula:
If vectors are perfectly aligned, their dot product is at its maximum. If they are perpendicular, the dot product is zero.
For vectors \(\vec{u} = \langle a_1, a_2 \rangle\) and \(\vec{v} = \langle b_1, b_2 \rangle\), the dot product \(\vec{u} \cdot \vec{v}\) is computed using the formula:
- \(\vec{u} \cdot \vec{v} = a_1b_1 + a_2b_2\)
If vectors are perfectly aligned, their dot product is at its maximum. If they are perpendicular, the dot product is zero.
Vector Magnitude
A vector's magnitude is a measure of its "length" in space, and it plays a crucial role when exploring the relationships between vectors such as during the calculation of angles.
The magnitude of a vector \(\vec{u} = \langle a_1, a_2 \rangle\) is given by:
Magnitude helps in determining how pronounced the vector is in terms of spatial orientation.
The magnitude of a vector \(\vec{u} = \langle a_1, a_2 \rangle\) is given by:
- \(\|\vec{u}\| = \sqrt{a_1^2 + a_2^2}\)
Magnitude helps in determining how pronounced the vector is in terms of spatial orientation.
Angle Between Vectors
Finding the angle between vectors involves understanding their geometric relationship, and it's a critical task in vector calculus.
The cosine of the angle \(\theta\) between vectors \(\vec{u}\) and \(\vec{v}\) is expressed as:
Subsequently, \(\theta\) is found by taking the inverse cosine (\(\cos^{-1}\)) of the computed value. Using the inverse trigonometric function, we can discover the actual angle in radians. This method allows us to convert the abstract relationship of vectors into a specific, measurable angle.
The cosine of the angle \(\theta\) between vectors \(\vec{u}\) and \(\vec{v}\) is expressed as:
- \(\cos\theta = \frac{\vec{u} \cdot \vec{v}}{\|\vec{u}\|\|\vec{v}\|}\)
Subsequently, \(\theta\) is found by taking the inverse cosine (\(\cos^{-1}\)) of the computed value. Using the inverse trigonometric function, we can discover the actual angle in radians. This method allows us to convert the abstract relationship of vectors into a specific, measurable angle.
Radians and Degrees Conversion
Understanding how to convert between radians and degrees is essential to interpreting and communicating angles in various contexts.
The relationship between radians and degrees is given by the equation:
In many mathematical applications, angles are calculated in radians, but converting these values into degrees might be necessary for clearer communication or practical applications.
The relationship between radians and degrees is given by the equation:
- degrees = radians \(\times \frac{180}{\pi}\)
In many mathematical applications, angles are calculated in radians, but converting these values into degrees might be necessary for clearer communication or practical applications.
Other exercises in this chapter
Problem 13
Write the vector, parametric and symmetric equations of the lines described. Passes through \(P=(1,1)\), parallel to \(\vec{d}=\langle 2,3\rangle\).
View solution Problem 13
Vectors \(\vec{u}\) and \(\vec{v}\) are given. Compute \(\vec{u} \times \vec{v}\) and show this is orthogonal to both \(\vec{u}\) and \(\vec{v}\). \(\vec{u}=\la
View solution Problem 13
Describe the region in space defined by the inequalities. \(x \geq 0, y \geq 0, z \geq 0\)
View solution Problem 14
Give the equation of the described plane in standard and general forms. Contains the parallel lines \(\vec{\ell}_{1}(t)=\langle 1,1,1\rangle+t\langle 4,1,3\rang
View solution