Problem 13
Question
Describe the region in space defined by the inequalities. \(x \geq 0, y \geq 0, z \geq 0\)
Step-by-Step Solution
Verified Answer
The region described is the first octant of 3D space, where all coordinates are non-negative.
1Step 1: Understand the Inequalities
The given inequalities are:- \( x \geq 0 \)- \( y \geq 0 \)- \( z \geq 0 \)Each inequality indicates that the respective coordinate (\(x\), \(y\), or \(z\)) is non-negative.
2Step 2: Visualize the Inequalities in 3D Space
In a 3-dimensional coordinate system, being non-negative for \(x\), \(y\), and \(z\) means the values are on or above the plane of each respective axis. This limits the region to the first octant where all coordinates are non-negative.
3Step 3: Define the Enclosed Region
Since all three coordinates must be greater than or equal to zero, the region is the set of all points where \(x\), \(y\), and \(z\) are zero or positive. This is the volume in space known as the first octant.
Key Concepts
First OctantInequalities in SpaceNon-negative Coordinates
First Octant
In three-dimensional space, the first octant is a specific region where all three coordinate values—\(x\), \(y\), and \(z\)—are non-negative. Think of each axis as dividing the space into different parts. When all three of these coordinates are greater than or equal to zero, the point lies in the part of the space we call the first octant.
- The \(x\)-axis is horizontal, going from left to right.
- The \(y\)-axis is also horizontal but goes from front to back.
- The \(z\)-axis is vertical, pointing upwards.
Inequalities in Space
The space in mathematics involving inequalities is more than just numbers on a line. In three-dimensional space, inequalities help define regions by setting limits on where a point can exist relative to its coordinates.
In our case, the inequalities \(x \geq 0\), \(y \geq 0\), and \(z \geq 0\) restrict points to the first octant. These inequalities tell us that every point within this region must be above or on each coordinate plane:
In our case, the inequalities \(x \geq 0\), \(y \geq 0\), and \(z \geq 0\) restrict points to the first octant. These inequalities tell us that every point within this region must be above or on each coordinate plane:
- \(x \geq 0\): points must be on or to the right of the \(yz\)-plane.
- \(y \geq 0\): points must be on or in front of the \(xz\)-plane.
- \(z \geq 0\): points must be on or above the \(xy\)-plane.
Non-negative Coordinates
Non-negative coordinates center around the concept that the values of \(x\), \(y\), and \(z\) are equal to or greater than zero. In 3D geometry, this non-negativity confines us to certain areas within the coordinate system.
Consider each axis as a foundation:
Consider each axis as a foundation:
- The \(x\)-axis: when \(x\geq0\), we stay on the side that lies to the right of the origin.
- The \(y\)-axis: \(y\geq0\) means staying on the side in front of the origin.
- The \(z\)-axis: \(z\geq0\) keeps us above the origin, akin to standing on the floor and moving upwards.
Other exercises in this chapter
Problem 13
Vectors \(\vec{u}\) and \(\vec{v}\) are given. Compute \(\vec{u} \times \vec{v}\) and show this is orthogonal to both \(\vec{u}\) and \(\vec{v}\). \(\vec{u}=\la
View solution Problem 13
In Exercises 13-16, find the measure of the angle between the two vectors in both radians and degrees. \(\vec{u}=\langle 1,1\rangle, \vec{v}=\langle 1,2\rangle\
View solution Problem 14
Give the equation of the described plane in standard and general forms. Contains the parallel lines \(\vec{\ell}_{1}(t)=\langle 1,1,1\rangle+t\langle 4,1,3\rang
View solution Problem 14
Write the vector, parametric and symmetric equations of the lines described. Passes through \(P=(-2,5)\), parallel to \(\vec{d}=\langle 0,1\rangle\).
View solution