Problem 13
Question
In \(9-14 :\) a. Find the common difference of each arithmetic sequence. b. Write the \(n\) th term of each sequence for the given value of \(n .\) $$ -1,-3,-5,-7, \ldots, n=10 $$
Step-by-Step Solution
Verified Answer
The common difference is -2, and the 10th term is -19.
1Step 1: Identify the Sequence
The given sequence is \( -1, -3, -5, -7, \ldots \). We need to find its common difference and the nth term for \( n = 10 \).
2Step 2: Find the Common Difference
An arithmetic sequence has a constant difference between consecutive terms. Calculate the difference between the first two terms: \( -3 - (-1) = -3 + 1 = -2 \). Thus, the common difference \( d = -2 \).
3Step 3: Write the Formula for the n-th Term
The formula for the n-th term of an arithmetic sequence is given by \( a_n = a_1 + (n-1) \cdot d \), where \( a_1 \) is the first term and \( d \) is the common difference.
4Step 4: Substitute Values into the Formula
In this sequence, \( a_1 = -1 \). Substituting \( a_1 = -1 \) and \( d = -2 \) into the formula, we get: \( a_n = -1 + (n-1) \cdot (-2) \).
5Step 5: Simplify the Formula
Simplify the formula: \( a_n = -1 - 2(n-1) \). Expand and simplify: \( a_n = -1 - 2n + 2 \). Thus, \( a_n = 1 - 2n \).
6Step 6: Calculate the 10th Term
Substitute \( n = 10 \) into the simplified formula: \( a_{10} = 1 - 2(10) \). Calculate: \( a_{10} = 1 - 20 = -19 \).
Key Concepts
Understanding Common DifferenceThe n-th Term Formula ExplainedEasy Sequence Calculation
Understanding Common Difference
In an arithmetic sequence, the common difference is the consistent interval between successive terms. Identifying this constant is crucial because it defines the nature of the sequence. For instance, in the sequence \(-1, -3, -5, -7, \ldots\), our task is to find this common difference.
To determine the common difference, you simply subtract the first term from the second term in the sequence. Subtraction shows how much each term increases or decreases from the previous one. In our exercise, subtracting \(-3\) from \(-1\) gives:
To determine the common difference, you simply subtract the first term from the second term in the sequence. Subtraction shows how much each term increases or decreases from the previous one. In our exercise, subtracting \(-3\) from \(-1\) gives:
- \(-3 - (-1) = -3 + 1 = -2\)
The n-th Term Formula Explained
For arithmetic sequences, the n-th term formula is a magic tool. It lets you find any term in the sequence without listing all the terms beforehand. This is particularly helpful when you're dealing with sequences that go up to very large numbers.
The n-th term formula is expressed as:
In our sequence \(-1, -3, -5, -7, \ldots\), with \(a_1 = -1\) and \(d = -2\), we apply these values to get:
The n-th term formula is expressed as:
- \(a_n = a_1 + (n-1) \cdot d\)
In our sequence \(-1, -3, -5, -7, \ldots\), with \(a_1 = -1\) and \(d = -2\), we apply these values to get:
- \(a_n = -1 + (n-1) \cdot (-2)\)
Easy Sequence Calculation
Once you have both the common difference and the n-th term formula, calculating any specific term in the sequence becomes straightforward.
Let's say you want to find the 10th term of your sequence. You'd just plug \(n = 10\) into the n-th term formula \(a_n = 1 - 2n\).
Substitute \(n = 10\) into the formula to get:
With this process, you can quickly find any term in the sequence. By understanding the elements of the arithmetic sequence, performing such calculations becomes a breeze for any value of \(n\).
Let's say you want to find the 10th term of your sequence. You'd just plug \(n = 10\) into the n-th term formula \(a_n = 1 - 2n\).
Substitute \(n = 10\) into the formula to get:
- \(a_{10} = 1 - 2(10)\)
- \(= 1 - 20\)
- \(= -19\)
With this process, you can quickly find any term in the sequence. By understanding the elements of the arithmetic sequence, performing such calculations becomes a breeze for any value of \(n\).
Other exercises in this chapter
Problem 13
In \(3-18,\) write the first five terms of each sequence. $$ a_{n}=\frac{n}{n+1} $$
View solution Problem 13
In \(9-18,\) use the given information to a. write the series in sigma notation, and b. find the sum of the first \(n\) terms. $$ a_{1}=2, d=\frac{1}{2}, n=15 $
View solution Problem 14
In \(3-14 :\) a. Write each arithmetic series as the sum of terms. b. Find each sum. $$ \sum_{n=0}^{5}(-2 n)^{n+1} $$
View solution Problem 14
In \(3-14,\) find the sum of \(n\) terms of each geometric series. $$ a_{1}=1, a_{8}=128, n=10 $$
View solution