Problem 13
Question
In \(3-18,\) write the first five terms of each sequence. $$ a_{n}=\frac{n}{n+1} $$
Step-by-Step Solution
Verified Answer
The first five terms are \( \frac{1}{2}, \frac{2}{3}, \frac{3}{4}, \frac{4}{5}, \frac{5}{6} \).
1Step 1: Introduction to Sequences
We have a sequence defined by the formula \( a_{n} = \frac{n}{n+1} \). To find the first five terms, we need to substitute the first five positive integers for \( n \) into this formula.
2Step 2: Calculate the 1st Term
Substitute \( n = 1 \) into the sequence formula: \[ a_{1} = \frac{1}{1+1} = \frac{1}{2} \]. So, the first term is \( \frac{1}{2} \).
3Step 3: Calculate the 2nd Term
Substitute \( n = 2 \) into the sequence formula: \[ a_{2} = \frac{2}{2+1} = \frac{2}{3} \]. So, the second term is \( \frac{2}{3} \).
4Step 4: Calculate the 3rd Term
Substitute \( n = 3 \) into the sequence formula: \[ a_{3} = \frac{3}{3+1} = \frac{3}{4} \]. So, the third term is \( \frac{3}{4} \).
5Step 5: Calculate the 4th Term
Substitute \( n = 4 \) into the sequence formula: \[ a_{4} = \frac{4}{4+1} = \frac{4}{5} \]. So, the fourth term is \( \frac{4}{5} \).
6Step 6: Calculate the 5th Term
Substitute \( n = 5 \) into the sequence formula: \[ a_{5} = \frac{5}{5+1} = \frac{5}{6} \]. So, the fifth term is \( \frac{5}{6} \).
7Step 7: Conclusion
The first five terms of the sequence are \( \frac{1}{2}, \frac{2}{3}, \frac{3}{4}, \frac{4}{5}, \) and \( \frac{5}{6} \).
Key Concepts
Term CalculationSequence FormulaIntroduction to Sequences
Term Calculation
When dealing with sequences in algebra, term calculation is a fundamental concept. A sequence is an ordered list of numbers, and each number is called a "term." To find each term in a sequence, we usually apply a specific formula known as the sequence formula. In our example, the sequence is given by the formula \( a_{n} = \frac{n}{n+1} \).
- To calculate the terms, you substitute values for \( n \), starting from 1, and progressing incrementally.
- For instance, to find the first term, you substitute \( n = 1 \) into the sequence formula, yielding \( a_{1} = \frac{1}{2} \).
- The subsequent terms are found by increasing \( n \): \( a_{2} = \frac{2}{3} \), \( a_{3} = \frac{3}{4} \), and so on.
Sequence Formula
The sequence formula is the key to unlocking the terms in a sequence. It's a mathematical expression that tells you how to calculate each term based on its position in the sequence. For our sequence, the formula is \( a_{n} = \frac{n}{n+1} \). This means the term \( a_{n} \) depends on the integer \( n \) that indicates its position.
- The numerator \( n \) is the position number itself.
- The denominator \( n+1 \) is simply one more than the position number.
Introduction to Sequences
Sequences are all around us, especially in mathematics. They are ordered sets of numbers that follow a particular pattern or rule. Here, we have a sequence expressed by a formula: \( a_{n} = \frac{n}{n+1} \). Understanding sequences involves recognizing patterns in numbers and seeing how these patterns are formed.
- In algebra, sequences can be thought of as a step-by-step guide to numbers that builds upon each previous step.
- Sequences can be infinite, meaning they go on forever, or finite, where they stop after a certain number of terms.
Other exercises in this chapter
Problem 13
An infinitely repeating decimal is an infinite geometric series. Find the rational number represented by each of the following infinitely repeating decimals. 0.
View solution Problem 13
In \(3-14,\) determine whether each given sequence is geometric. If it is geometric, find \(r\) . If it is not geometric, explain why it is not. $$ 0.05,-0.1,0.
View solution Problem 13
In \(9-18,\) use the given information to a. write the series in sigma notation, and b. find the sum of the first \(n\) terms. $$ a_{1}=2, d=\frac{1}{2}, n=15 $
View solution Problem 13
In \(9-14 :\) a. Find the common difference of each arithmetic sequence. b. Write the \(n\) th term of each sequence for the given value of \(n .\) $$ -1,-3,-5,
View solution