Problem 13
Question
If \(P(E)=\frac{5}{7}\), find \(O(E)\) and \(O\left(E^{\prime}\right)\)
Step-by-Step Solution
Verified Answer
\(O(E) = \frac{5}{2}\), \(O(E') = \frac{2}{5}\).
1Step 1: Understand Probability and Odds
Probability is a measure of how likely an event is to occur, while odds are a different way to express that likelihood. The odds in favor of an event are calculated as the probability of the event occurring divided by the probability of it not occurring.
2Step 2: Calculate Probability of Complementary Event
The probability of the complementary event, denoted as \( P(E') \), can be found using the formula: \( P(E') = 1 - P(E) \). Thus, \( P(E') = 1 - \frac{5}{7} \).
3Step 3: Compute Complementary Probability
Calculate \(1 - \frac{5}{7}\):\[P(E') = 1 - \frac{5}{7} = \frac{7}{7} - \frac{5}{7} = \frac{2}{7}\]
4Step 4: Calculate Odds for Event
The odds in favor of an event \(E\) is given by the ratio \( \frac{P(E)}{P(E')} \). Using the probabilities found:\[O(E) = \frac{ \frac{5}{7} }{ \frac{2}{7} } = \frac{5}{2}\]
5Step 5: Calculate Odds Against Complementary Event
The odds against the complementary event \(E'\) is the same calculation as the odds for event \(E\):\[O(E') = \frac{P(E')}{P(E)} = \frac{ \frac{2}{7} }{ \frac{5}{7} } = \frac{2}{5}\]
Key Concepts
Probability of an EventComplementary EventOdds in FavorOdds Against
Probability of an Event
Probability helps us understand the likelihood that a specific event will occur. It's a number between 0 and 1, where 0 means the event will not happen, and 1 means it certainly will. For example, if the probability of an event is \( P(E) = \frac{5}{7} \), it means there are 5 chances out of 7 for the event to happen. To think about it in everyday terms, imagine you have 7 cards—5 of them are winning cards—and you pick one at random. The probability that you select a winning card is \( \frac{5}{7} \). This is quite a handy way to measure how likely or unlikely events are in our day-to-day lives.
Complementary Event
The complementary event of any event \(E\) is what occurs if \(E\) does not happen. The probability of this complementary event is denoted by \( P(E') \) or sometimes \( \overline{E} \). You can calculate it by subtracting the probability of the event from 1: \( P(E') = 1 - P(E) \). In our example, \( P(E') \) would be calculated as \( 1 - \frac{5}{7} = \frac{2}{7} \). This tells us there's a \( \frac{2}{7} \) chance that the event \(E\) will not occur. Complementary probabilities are always in complete contrast to the original event probabilities and they sum up to 1, helping us see both sides of the chance coin.
Odds in Favor
Odds provide another perspective on chance. They compare the probability of an event occurring to the probability of it not occurring. The odds in favor of an event, \(E\), can be determined using the ratio of its probability to that of its complementary event: \( O(E) = \frac{P(E)}{P(E')} \). In the given example, the odds in favor are \( \frac{ \frac{5}{7} }{ \frac{2}{7} } = \frac{5}{2} \). This tells us that for every 2 times the event does not happen, it is likely to happen 5 times. Simplifying these odds often helps in understanding and predicting outcomes, especially in scenarios like games and betting where understanding odds clearly can make a big difference.
Odds Against
The odds against an event is just the flip of the odds in favor. It represents how often the event will not occur compared to how often it will. For any event \(E\), the odds against are calculated using the ratio \( O(E') = \frac{P(E')}{P(E)} \). From our example, this would be computed as \( \frac{ \frac{2}{7} }{ \frac{5}{7} } = \frac{2}{5} \). This means for every 5 times the event happens, it doesn't happen 2 times. Easily understanding odds against helps in knowing the unfavorable scenarios, and provides an alternate viewpoint on the balance between likelihoods.
Other exercises in this chapter
Problem 12
Exer. 11-12: Find the common difference for the arithmetic sequence with the specified terms. $$ a_{4}=14, a_{11}=35 $$
View solution Problem 13
Find the \(n\)th term, the fifth term, and the eighth term of the geometric sequence. $$2,2^{x+1}, 2^{2 x+1}, 2^{3 x+1}, \ldots$$
View solution Problem 13
Ten people wish to play in a basketball game. In how many different ways can two teams of five players each be formed?
View solution Problem 13
Rewrite as an expression that does not contain factorials. $$ \frac{n !}{(n-2) !} $$
View solution