Problem 13
Question
Find the \(n\)th term, the fifth term, and the eighth term of the geometric sequence. $$2,2^{x+1}, 2^{2 x+1}, 2^{3 x+1}, \ldots$$
Step-by-Step Solution
Verified Answer
\( a_n = 2^{nx-x+1} \); 5th term: \( 2^{4x+1} \); 8th term: \( 2^{7x+1} \).
1Step 1: Identify the first term and common ratio
The first term of the sequence is given as the first number, which is 2. To find the common ratio, divide the second term by the first term. In this case, the second term is \(2^{x+1}\) and the first term is \(2\). The common ratio \( r \) is thus \( r = \frac{2^{x+1}}{2} = 2^x \).
2Step 2: General formula for the nth term of a geometric sequence
The general formula for the \(n\)th term of a geometric sequence is given by \( a_n = a_1 \cdot r^{n-1} \), where \( a_1 \) is the first term and \( r \) is the common ratio. For this sequence, \( a_1 = 2 \) and \( r = 2^x \). Thus, the \(n\)th term is \( a_n = 2 \cdot (2^x)^{n-1} = 2^{1 + (n-1)x} = 2^{nx - x + 1} \).
3Step 3: Calculate the 5th term
Use the general formula \( a_n = 2^{nx - x + 1} \) to find the 5th term of the sequence by substituting \( n = 5 \). This gives us \( a_5 = 2^{5x - x + 1} = 2^{4x + 1} \).
4Step 4: Calculate the 8th term
Similarly, substitute \( n = 8 \) into the general formula to find the 8th term. This yields \( a_8 = 2^{8x - x + 1} = 2^{7x + 1} \).
5Step 5: Summarize the terms
The general \(n\)th term of the sequence is \( a_n = 2^{nx - x + 1} \). The 5th term is \( 2^{4x + 1} \), and the 8th term is \( 2^{7x + 1} \).
Key Concepts
nth term formulacommon ratioexponent rulessequence terms
nth term formula
In a geometric sequence, each term is found by multiplying the previous term by a constant value known as the common ratio. To find any term in the sequence, you need a formula that combines both the initial term and the common ratio. This is the nth term formula, defined as follows: \[ a_n = a_1 \cdot r^{n-1} \] where:
- \( a_n \) is the nth term of the sequence.
- \( a_1 \) is the first term.
- \( r \) is the common ratio.
- \( n \) is the term number you want to find.
common ratio
The common ratio is a fundamental part of understanding geometric sequences. It is the factor by which we multiply to move from one term to the next. To determine the common ratio, divide any term in the sequence by the previous term.In our specific sequence starting with 2 and continuing with terms like \( 2^{x+1} \), the common ratio \( r \) can be calculated as:\[ r = \frac{2^{x+1}}{2} = 2^x \]This ratio \( 2^x \) is constant throughout the sequence, ensuring that each term is obtained by multiplying the previous term by \( 2^x \). Understanding this helps in generating the sequence and directly impacts the nth term formula.
exponent rules
Exponent rules are essential when working with geometric sequences that involve expressions with powers. In our sequence, each subsequent term involves powers of 2, often requiring simplification.Some important exponent rules include:
- \( a^m \cdot a^n = a^{m+n} \) – When you multiply powers with the same base, add the exponents.
- \( \frac{a^m}{a^n} = a^{m-n} \) – When you divide powers with the same base, subtract the exponents.
- \( (a^m)^n = a^{mn} \) – When raising a power to another power, multiply the exponents.
sequence terms
Understanding sequence terms involves both identifying the specific terms and calculating them using the nth term formula. Let's take two specific terms as examples: the fifth and the eighth.Using the derived formula \( a_n = 2^{nx - x + 1} \), plug in:
- For the fifth term: \( n = 5 \). Substitute to get \( a_5 = 2^{4x + 1} \).
- For the eighth term: \( n = 8 \). Substitute to get \( a_8 = 2^{7x + 1} \).
Other exercises in this chapter
Problem 12
Exer. 1-26: Prove that the statement is true for every positive integer \(n\). $$ \begin{aligned} \frac{1}{1 \cdot 2 \cdot 3}+\frac{1}{2 \cdot 3 \cdot 4} &+\fra
View solution Problem 12
Exer. 11-12: Find the common difference for the arithmetic sequence with the specified terms. $$ a_{4}=14, a_{11}=35 $$
View solution Problem 13
If \(P(E)=\frac{5}{7}\), find \(O(E)\) and \(O\left(E^{\prime}\right)\)
View solution Problem 13
Ten people wish to play in a basketball game. In how many different ways can two teams of five players each be formed?
View solution