Problem 13
Question
A hydrocarbon of formula \(\mathrm{C}_{11} \mathrm{H}_{18}\) on reaction with ozone in dichloromethane gave, after the addition of water and finely divided zinc, three products in equimolar amounts that were identified as 2 -butanone \(\left(\mathrm{CH}_{3} \mathrm{COCH}_{2} \mathrm{CH}_{3}\right)\), methanal \(\left(\mathrm{CH}_{2} \mathrm{O}\right)\), and cyclohexane-1,4-dione \(\mathrm{Draw}\) the structure of the hydrocarbon \(\mathrm{C}_{11} \mathrm{H}_{18} .\)
Step-by-Step Solution
Verified Answer
The structure of the hydrocarbon is bicyclo[4.4.0]dec-1(6)-ene.
1Step 1: Identify Reaction Type
The reaction described is ozonolysis, a process that cleaves carbon-carbon double bonds in alkenes, forming carbonyl compounds such as aldehydes or ketones.
2Step 2: Analyze the Products Formed
The products formed are 2-butanone, methanal, and cyclohexane-1,4-dione. Since these are formed in equimolar amounts, each carbon-carbon double bond must produce one of these products or a fragment thereof.
3Step 3: Determine the Bonds Cleaved
2-butanone suggests a ketone was formed from an alkene with an internal double bond. Methanal formation implies the presence of a terminal alkene. Cyclohexane-1,4-dione suggests an alkene within a cyclic structure in the starting material.
4Step 4: Deduce the Hydrocarbon Skeleton
The products suggest the hydrocarbon might have multiple double bonds. A common structure with these features is bicyclo[4.4.0]dec-1(6)-ene, which can be cleaved by ozonolysis to form the three distinct products.
5Step 5: Draw Structure of the Hydrocarbon
The hydrocarbon is deduced to have the structure: a bicyclic compound made from a cyclohexene ring (providing cyclohexane-1,4-dione) and an attached butyl group forming a side chain that provides the other product fragments.
Key Concepts
Hydrocarbon structure determinationAlkene cleavageCarbonyl compound formation
Hydrocarbon structure determination
Deciphering the structure of a hydrocarbon from its chemical reactions and products is like solving a puzzle. In this exercise, we're given a hydrocarbon with the formula \( \mathrm{C}_{11} \mathrm{H}_{18} \). The key to figuring out its structure lies in the ozonolysis reaction—a method used to characterize alkenes by breaking them down into smaller, identifiable molecules. By analyzing these fragments, we can deduce the starting hydrocarbon's architecture.
The reaction provides three products: 2-butanone, methanal, and cyclohexane-1,4-dione. Each product gives us clues about the hydrocarbon's structure. 2-butanone and methanal hint at the presence of both internal and terminal double bonds, while cyclohexane-1,4-dione signals a cyclic component. Thus, we suspect our hydrocarbon is a polycyclic alkene, featuring rings with double bonds that can lead to these specific products when cleaved.
The reaction provides three products: 2-butanone, methanal, and cyclohexane-1,4-dione. Each product gives us clues about the hydrocarbon's structure. 2-butanone and methanal hint at the presence of both internal and terminal double bonds, while cyclohexane-1,4-dione signals a cyclic component. Thus, we suspect our hydrocarbon is a polycyclic alkene, featuring rings with double bonds that can lead to these specific products when cleaved.
Alkene cleavage
Alkene cleavage is a fascinating reaction process where double bonds in alkenes are broken to give smaller carbon-based molecules. Ozonolysis is the method applied here. This reaction uses ozone to cut the carbon-carbon double bonds, converting them into carbonyl groups.
- For 2-butanone to form, an internal double bond must be present far away from the end of the molecule.
- Methanal suggests a terminal alkene where the double bond is at the end of the chain.
- Cyclohexane-1,4-dione indicates a ring structure was originally present, with one or more internal double bonds.
Carbonyl compound formation
Carbonyl compounds, such as aldehydes and ketones, arise from the disruption of double bonds in alkenes through ozonolysis. As the molecule reacts with ozone, the double bonds are replaced with carbonyl groups, resulting in well-defined fragments.
In this case, the formation of 2-butanone indicates a rearrangement and conversion at an internal alkene site into an oxygen-bearing group, forming a ketone. Methanal results from the conversion of a terminal double bond into an aldehyde, illustrating a direct transformation of an endgroup on the hydrocarbon. Cyclohexane-1,4-dione's creation shows that a cyclic formation with possibly multiple carbonyls is possible when an alkene is positioned within a ring.
In this case, the formation of 2-butanone indicates a rearrangement and conversion at an internal alkene site into an oxygen-bearing group, forming a ketone. Methanal results from the conversion of a terminal double bond into an aldehyde, illustrating a direct transformation of an endgroup on the hydrocarbon. Cyclohexane-1,4-dione's creation shows that a cyclic formation with possibly multiple carbonyls is possible when an alkene is positioned within a ring.
- These conversions are fundamental to mapping the transformations from alkenes to stable structures containing carbonyl moieties.
Other exercises in this chapter
Problem 10
What products would you expect from hydroboration of the following alkenes with a dialkylborane, \(\mathrm{R}_{2} \mathrm{BH}\), followed by isomerization at \(
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a. Draw the structure and configuration of the product expected of the reaction between 1-bromo-1-hexyne and diethylborane, \(\left(\mathrm{C}_{2} \mathrm{H}_{5
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Starting with cyclohexene, show how you could prepare each of the following compounds: a. the epoxide of cyclohexene b. cis-cyclohexane-1,2-diol c. trans-cycloh
View solution Problem 17
Suppose you were given four unlabeled bottles, each of which is known to contain one of the following compounds: pentane, 1 -pentene, 2 -pentyne, or 1 -pentyne.
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