Problem 12
Question
a. Draw the structure and configuration of the product expected of the reaction between 1-bromo-1-hexyne and diethylborane, \(\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{BH}\). b. When the product is treated with sodium methoxide, \(\mathrm{NaOCH}_{3}\), then with propanoic acid, trans-3-octene is formed. Show the steps involved in forming this trans-alkene.
Step-by-Step Solution
Verified Answer
Trans-3-octene is the result of reacting vinyl bromide with sodium methoxide and propanoic acid.
1Step 1: Reaction Setup
1-Bromo-1-hexyne reacts with diethylborane, \( (\mathrm{C}_2\mathrm{H}_5)_2\mathrm{BH} \), where B attaches to the terminal carbon of the alkyne, leading to hydroboration.
2Step 2: Hydroboration
Diethylborane adds across the triple bond of 1-bromo-1-hexyne in an anti-Markovnikov fashion. This step forms a vinyl borane where the boron is attached to the terminal end of the alkyne.
3Step 3: Formation of Vinyl Bromide
The reaction forms a vinyl bromide following the hydroboration step. The molecule now has a C-Br bond and a B(C2H5)2 group attached to adjacent carbons of the double bond.
4Step 4: Reaction with Sodium Methoxide
Sodium methoxide \( \mathrm{NaOCH}_3 \) will remove the diethylborane group from the vinyl bromide, replacing it with a methoxide group.
5Step 5: Reaction with Propanoic Acid
The intermediate product from the previous step then reacts with propanoic acid, leading to the removal of the methoxy group and regeneration of a more stable alkene bond.
6Step 6: Trans-3-Octene Formation
After the treatment with sodium methoxide followed by propanoic acid, the reaction stabilizes as \( \text{trans-3-octene} \), a trans-alkene due to elimination that occurs in a trans manner.
Key Concepts
HydroborationVinyl BoraneSodium MethoxideTrans-3-OcteneAnti-Markovnikov Addition
Hydroboration
Hydroboration is a crucial reaction in organic chemistry that facilitates the addition of boron across carbon-carbon multiple bonds, such as alkenes and alkynes. When 1-bromo-1-hexyne reacts with diethylborane, hydroboration occurs as diethylborane,
- adds to the triple bond of the alkyne in an orderly fashion, and
- connects with the terminal carbon, initiating the transformation.
Vinyl Borane
The formation of vinyl borane is a direct consequence of the hydroboration process. Upon the addition of boron,
- a structure emerges where the carbon-to-boron bond is formed at the extremity of the former alkyne,
- creating what is known as a vinyl borane.
Sodium Methoxide
In this reaction sequence, sodium methoxide \( \mathrm{NaOCH}_3 \) plays a significant role as a nucleophile.
- First, it reacts with the vinyl borane, effectively replacing the boron group with a methoxide group.
- Nucleophilic substitution takes place, where the vinyl bromide formed from the hydroboration step loses the diethylborane and gains a new methoxide group.
Trans-3-Octene
The synthesis of trans-3-octene is a two-step process following the initial hydroboration. The vinyl bromide product treated with sodium methoxide undergoes a further reaction with propanoic acid.
- This subsequent reaction leads to the removal of the methoxy group, favoring the generation of a stable alkene form.
- The double bond formed in this process is in a trans configuration, thus resulting in the creation of trans-3-octene.
Anti-Markovnikov Addition
Anti-Markovnikov addition refers to the process where the less substituted carbon atom in a double or triple bond becomes bonded to the addend.
- This concept is exemplified in the reaction of 1-bromo-1-hexyne with diethylborane.
- Unlike Markovnikov's addition, where the more substituted carbon would form the bond, anti-Markovnikov addition places the new group on the less hindered carbon.
Other exercises in this chapter
Problem 8
Consider that it is necessary to synthesize pure samples of \(D, L\) -hexane- \(3,4-\mathrm{D}_{2}\) and meso-hexane- \(3,4-\mathrm{D}_{2} .\) Show how this mig
View solution Problem 10
What products would you expect from hydroboration of the following alkenes with a dialkylborane, \(\mathrm{R}_{2} \mathrm{BH}\), followed by isomerization at \(
View solution Problem 13
A hydrocarbon of formula \(\mathrm{C}_{11} \mathrm{H}_{18}\) on reaction with ozone in dichloromethane gave, after the addition of water and finely divided zinc
View solution Problem 16
Starting with cyclohexene, show how you could prepare each of the following compounds: a. the epoxide of cyclohexene b. cis-cyclohexane-1,2-diol c. trans-cycloh
View solution