Problem 12
Question
Write and evaluate a sum to estimate the area under each curve for the domain \(0 \leq x \leq 2\) . a. Use inscribed rectangles 1 unit wide. b. Use eircumscribed rectangles 1 unit wide. $$ y=-x^{2}+4 $$
Step-by-Step Solution
Verified Answer
The estimate of the area under the curve using inscribed rectangles is 7 square units, and using circumscribed rectangles is 11 square units.
1Step 1: Find the values of y
For each integer value of \(x\) in the range 0 to 2, we calculate the corresponding value of y in the function \(y=-x^{2}+4\). These are (0,4), (1,3), and (2,0).
2Step 2: Compute area using inscribed rectangles
In inscribed rectangles, we use the function's minimum value in the given interval as height. Here, the width is 1, and the heights are the y-values. Then the area A (estimate) would be: \[A = 1*(4 + 3) = 7\]
3Step 3: Compute area using circumscribed rectangles
In circumscribed rectangles, the function's maximum value in the given interval is used as height. Here, the widths are 1, and the heights are the y-values. Then the area A (estimate) would be: \[A = 1*(4 + 4 + 3) = 11\]
Key Concepts
Inscribed RectanglesCircumscribed RectanglesPolynomial Functions
Inscribed Rectangles
When estimating the area under a curve using inscribed rectangles, each rectangle is drawn within the curve. This means the top of the rectangle touches the curve at the lowest point within the given interval.
In our example, we are finding the area under the polynomial function given by \(y = -x^{2} + 4\), from \(x = 0\) to \(x = 2\).
The process involves:
In our example, we are finding the area under the polynomial function given by \(y = -x^{2} + 4\), from \(x = 0\) to \(x = 2\).
The process involves:
- Finding the smallest \(y\)-value within each subinterval to use as the rectangle's height.
- For intervals \([0,1)\) and \([1,2)\) in our example, these heights are 4 (from \(y(0)\)=4) and 3 (from \(y(1)\)=3) respectively because 3 is less than 0 at \(y(2)\).
- Multiplying each height by the width of the rectangles (1 unit in our case) and summing these areas gives the total estimated area.
Circumscribed Rectangles
Circumscribed rectangles estimate area by extending beyond or surrounding the curve. The top of the rectangle reaches the highest point of the curve within the interval. This provides an overestimate of the true area.
Let's consider the polynomial function \(y = -x^{2} + 4\) from \(x = 0\) to \(x = 2\).
To use circumscribed rectangles effectively:
Let's consider the polynomial function \(y = -x^{2} + 4\) from \(x = 0\) to \(x = 2\).
To use circumscribed rectangles effectively:
- Identify the highest \(y\)-value at each subinterval: For \([0,1)\) the height would be 4, for \([1,2)\) the height is 4 as well since it doesn’t drop below 3 in 0 to 1, and not yet hit 0.
- Multiply each height by the width (1 unit) and sum: This yields
- \(A = 1 \times (4 + 4 + 3) = 11\), which includes the extra block above \([1,2)\).
Polynomial Functions
Polynomial functions are mathematical expressions involving variables raised to whole-number powers, combined using arithmetic operations. They are quite flexible and can represent a wide variety of curves.
In the context of area estimation, polynomial functions often describe the curves we're interested in.
The function \(y = -x^{2} + 4\) is a simple quadratic, meaning its highest degree is \(x^2\).
Here are key characteristics of this type:
In the context of area estimation, polynomial functions often describe the curves we're interested in.
The function \(y = -x^{2} + 4\) is a simple quadratic, meaning its highest degree is \(x^2\).
Here are key characteristics of this type:
- The graph is a parabola, opening downwards, due to the negative coefficient of \(x^2\).
- The vertex is the highest point, at \((0,4)\) in this case, because
- the \(x\)-term is zeroed out and the constant provides the maximum height.
- This curve intersects the \(x\)-axis at roots or points \((2,0)\) and \((2,-2)\), where the value of \(y\) becomes zero.
Other exercises in this chapter
Problem 11
Is the sequence geometric? If so, find the common ratio and the next two terms. $$ -1,-6,-36,-216, \dots $$
View solution Problem 11
Find the 32nd term of each sequence. \(34,37,40,43, \ldots\)
View solution Problem 12
Decide whether each infinite geometric series diverges or converges. State whether each series has a sum. $$ 1+2+4+\ldots $$
View solution Problem 12
Is the sequence geometric? If so, find the common ratio and the next two terms. $$ \frac{1}{2}, \frac{1}{4}, \frac{1}{6}, \frac{1}{8}, \ldots $$
View solution