Problem 12
Question
In Problems 7-14, express the given function in the form \(f(z)=u+i v .\) $$ f(z)=z^{4} $$
Step-by-Step Solution
Verified Answer
\( f(z) = (x^4 - 6x^2y^2 + y^4) + i(4x^3y - 4xy^3) \)
1Step 1: Understanding the Problem
We need to express the function \( f(z) = z^4 \) in the form \( f(z) = u + iv \), where \( u \) and \( v \) are real-valued functions of \( x \) and \( y \). Here, \( z = x + iy \).
2Step 2: Expanding \( z^4 \) using \( x + iy \)
Since \( z = x + iy \), we can write \( z^4 = (x + iy)^4 \). We need to expand this expression to separate the real and imaginary parts.
3Step 3: Applying Binomial Theorem
Applying the binomial theorem to \( (x + iy)^4 \), we have: \[(x + iy)^4 = x^4 + 4x^3(iy) + 6x^2(iy)^2 + 4x(iy)^3 + (iy)^4 \]Next, compute each term.
4Step 4: Simplifying Each Term
- \( x^4 \) is real.- \( 4x^3(iy) = 4ix^3y \) is imaginary.- \( (iy)^2 = -y^2 \) so \( 6x^2(iy)^2 = -6x^2y^2 \), which is real.- \( (iy)^3 = -iy^3 \) so \( 4x(iy)^3 = -4ixy^3 \) is imaginary.- \( (iy)^4 = y^4 \) is real.
5Step 5: Combining Terms
Combine all the real and imaginary parts:\[f(z) = (x^4 - 6x^2y^2 + y^4) + i(4x^3y - 4xy^3) \]Thus, \( u = x^4 - 6x^2y^2 + y^4 \) and \( v = 4x^3y - 4xy^3 \).
Key Concepts
Binomial TheoremComplex VariablesReal and Imaginary Parts
Binomial Theorem
The Binomial Theorem is a powerful mathematical tool that helps us expand expressions like \((a + b)^n\). This theorem states that:
In the context of our original problem, we apply the Binomial Theorem to expand \((x + iy)^4\). This gives us terms involving powers of \(x\) and \(iy\) with specific coefficients.
Each term can be computed individually:
- \((a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\)
In the context of our original problem, we apply the Binomial Theorem to expand \((x + iy)^4\). This gives us terms involving powers of \(x\) and \(iy\) with specific coefficients.
Each term can be computed individually:
- The first term is \(x^4\).
- The second term, \(4ix^3y\), comes from \(4x^3(iy)\).
- We have \(-6x^2y^2\) from \(6x^2(iy)^2\) where \((iy)^2 = -y^2\).
- Then \(-4ixy^3\) from \(4x(iy)^3\), where \((iy)^3 = -iy^3\).
- Finally, \(y^4\) from \((iy)^4 = y^4\), making it real.
Complex Variables
A complex variable, denoted as \(z\), usually takes the form \(z = x + iy\), where \(x\) and \(y\) are real numbers, and \(i\) is the imaginary unit with the property \(i^2 = -1\).
The world of complex variables allows us to extend the idea of traditional two-dimensional numbers to a two-part system, where one part is the real part and the other is the imaginary part.
This approach helps facilitate a wide variety of mathematical, physical, and engineering problems. Unlike real numbers, these can be visualized as vectors or points in a complex plane, where the horizontal axis represents the real part and the vertical axis the imaginary part.
The world of complex variables allows us to extend the idea of traditional two-dimensional numbers to a two-part system, where one part is the real part and the other is the imaginary part.
This approach helps facilitate a wide variety of mathematical, physical, and engineering problems. Unlike real numbers, these can be visualized as vectors or points in a complex plane, where the horizontal axis represents the real part and the vertical axis the imaginary part.
- Real part: \(x\)
- Imaginary part: \(y\)
Real and Imaginary Parts
Splitting functions into real and imaginary parts involves expressing a complex function \(f(z)\) as \(u + iv\), where both \(u\) and \(v\) are real-valued functions of \(x\) and \(y\).
In our specific problem, the objective is to break down \(f(z) = z^4\) into such parts:
In our specific problem, the objective is to break down \(f(z) = z^4\) into such parts:
- Start by expressing \(z\) as \(x + iy\).
- Use algebra and the Binomial Theorem to expand \((x + iy)^4\).
- The real part \(u = x^4 - 6x^2y^2 + y^4\)
- The imaginary part \(v = 4x^3y - 4xy^3\)
Other exercises in this chapter
Problem 12
In Problems \(1-12\), express the given quantity in the form \(a+i b\). $$ \cosh (2+3 i) $$
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In Problems 11 and 12, express the given number in the form \(a+i b\). $$ \frac{e^{2+3 \pi i}}{e^{-3+\pi i / 2}} $$
View solution Problem 12
In Problems 9-22, sketch the set of points in the complex plane satisfying the given inequality. Determine whether the set is a domain. $$ \operatorname{Im}(z-i
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In Problems 11-14, write the number given in polar form in the form \(a+i b\). $$ z=8 \sqrt{2}\left(\cos \frac{11 \pi}{4}+i \sin \frac{11 \pi}{4}\right) $$
View solution