Problem 12
Question
In Problems 11 and 12, express the given number in the form \(a+i b\). $$ \frac{e^{2+3 \pi i}}{e^{-3+\pi i / 2}} $$
Step-by-Step Solution
Verified Answer
The expression simplifies to \(0 + ie^5\).
1Step 1: Simplify the Exponents
First, simplify the expression by separating the real and imaginary parts in the exponents. We have:\[e^{2+3 heta i} = e^2 e^{3\pi i} \quad \text{and} \quad e^{-3+\pi i / 2} = e^{-3} e^{\pi i / 2}\]
2Step 2: Simplify the Quotient
Divide each part separately:\[\frac{e^2 e^{3\pi i}}{e^{-3} e^{\pi i / 2}} = e^{2 - (-3)} \cdot \frac{e^{3\pi i}}{e^{\pi i / 2}}\]This simplifies to:\[e^5 \cdot e^{(3\pi - \pi/2)i} = e^5 \cdot e^{\frac{5\pi}{2}i}\]
3Step 3: Calculate Real and Imaginary Parts
Convert the exponential of an imaginary number to trigonometric form using Euler's Formula: \[e^{\theta i} = \cos(\theta) + i\sin(\theta)\]Thus:\[e^{\frac{5\pi}{2}i} = \cos\left(\frac{5\pi}{2}\right) + i\sin\left(\frac{5\pi}{2}\right)\]Note that \(\frac{5\pi}{2} = 2\pi + \pi/2\), which has the same sine and cosine as \(\pi/2\):\[ \cos(\pi/2) = 0, \quad \sin(\pi/2) = 1 \]Thus:\[e^{\frac{5\pi}{2}i} = 0 + i(1) = i\]
4Step 4: Multiply and Simplify
Combine the results of previous steps:\[e^5 \cdot e^{\frac{5\pi}{2}i} = e^5 (i)\]So the expression in the form \(a + ib\) is:\[0 + ie^5\]
Key Concepts
Exponential Form of Complex NumbersEuler's FormulaTrigonometric Form of Complex Numbers
Exponential Form of Complex Numbers
Complex numbers can be expressed in various forms, and the exponential form is one of them. It beautifully combines trigonometry with exponential functions, which can simplify many complex operations. In its exponential form, a complex number is written as \( e^{x+yi} \), where:
- \( x \) is the real part
- \( y \) is the imaginary part
- \( e \) is Euler's number, approximately equal to 2.71828
Euler's Formula
Euler's Formula provides the bridge between exponential and trigonometric forms of complex numbers. It states that for any real number \( \theta \):\[e^{i\theta} = \cos(\theta) + i\sin(\theta)\]Using this formula, you can convert complex numbers between these two forms seamlessly. Here’s how it helps:
- Transforms an exponential expression into a trigonometric one, revealing the relationship between the angles \( \theta \) and the real and imaginary parts.
- Makes it easier to visualize and work with rotations and oscillations in the complex plane.
Trigonometric Form of Complex Numbers
The trigonometric form, another way to express complex numbers, emphasizes the role of angles and magnitudes. It is written as \( r(\cos(\theta) + i\sin(\theta)) \), where:
- \( r \) is the magnitude of the complex number.
- \( \theta \) is the argument or angle.
Other exercises in this chapter
Problem 12
Answer Problems 1-16 without referring back to the text. Fill in the blank or answer true/false. If \(f(z)=x^{2}-3 x y-5 y^{3}+i\left(4 x^{2} y-4 x+7 y\right)\)
View solution Problem 12
In Problems \(1-12\), express the given quantity in the form \(a+i b\). $$ \cosh (2+3 i) $$
View solution Problem 12
In Problems 7-14, express the given function in the form \(f(z)=u+i v .\) $$ f(z)=z^{4} $$
View solution Problem 12
In Problems 9-22, sketch the set of points in the complex plane satisfying the given inequality. Determine whether the set is a domain. $$ \operatorname{Im}(z-i
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