Problem 115
Question
Is every rational function a polynomial function? Why or why not? Does a true statement result if the two adjectives rational and polynomial are reversed? Explain.
Step-by-Step Solution
Verified Answer
No, not every rational function is a polynomial function because rational functions can have negative powers or division by a variable which polynomials cannot. However, every polynomial function can be considered a rational function.
1Step 1: Understanding Polynomial functions
A polynomial function is an expression consisting of variables and coefficients, which only employs the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables. Examples can be \(x^2\), \(3x^2 + 2x + 1\) etc.
2Step 2: Understanding Rational functions
A rational function is the ratio of two polynomials, with both polynomials in the ratio being defined by the rules of polynomial functions. Such functions look like this: \(f(x) = P(x)/Q(x)\), where both P and Q are polynomial functions.
3Step 3: Comparing the two
Every polynomial could be seen as a rational function. For example the polynomial function \(P(x) = x^2\) can also be defined as a rational function \(f(x) = x^2/1\). However, not every rational function is a polynomial. For example the rational function \(f(x) = 1/x\) is not a polynomial because, based on the definition, polynomials do not have negative powers or division by a variable.
4Step 4: Reversing the statement
If we reverse the adjectives, we say: 'Every polynomial function is a rational function'. This statement is true. Polynomials, such as \(x^2 + 2x + 1\), can be expressed as a ratio of two polynomials, such as \((x^2 + 2x + 1) / 1\).
Other exercises in this chapter
Problem 115
Exercises 113–115 will help you prepare for the material covered in the next section. Use $$ \frac{2 x^{3}-3 x^{2}-11 x+6}{x-3}=2 x^{2}+3 x-2 $$ to factor \(2 x
View solution Problem 115
Use $$\frac{2 x^{3}-3 x^{2}-11 x+6}{x-3}=2 x^{2}+3 x-2$$ to factor \(2 x^{3}-3 x^{2}-11 x+6\) completely
View solution Problem 115
Exercises \(113-115\) will help you prepare for the material covered in the next section. If \(S=\frac{k A}{P},\) find the value of \(k\) using \(A=60,000, P=40
View solution Problem 118
Use a graphing utility to graph \(y=\frac{1}{x^{\prime}}, y=\frac{1}{x^{3}},\) and \(\frac{1}{x^{5}}\) in the same viewing rectangle. For odd values of \(n,\) h
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