Problem 111
Question
Prove that a function of the following form is odd. $$y=a_{2 n+1} x^{2 n+1}+a_{2 n-1} x^{2 n-1}+\cdots+a_{3} x^{3}+a_{1} x$$
Step-by-Step Solution
Verified Answer
The given function \(y=a_{2 n+1} x^{2 n+1}+a_{2 n-1} x^{2 n-1}+\cdots+a_{3} x^{3}+a_{1} x\) is indeed an odd function, because it meets the condition f(-x) = -f(x).
1Step 1: Rewrite the Function
Start by writing the general form of the function as \(y=\sum_{n=0}^{N} a_{2 n+1} x^{2 n+1}\), where N is a positive integer and \(a_{2 n + 1}\) is an arbitrary constant and \(x^{2 n + 1}\) is raising \(x\) to an odd power.
2Step 2: Substitute -x for x
Substitute \(-x\) for \(x\) in this function, this will give: \( f(-x) = \sum_{n=0}^{N} a_{2 n+1} (-x)^{2 n+1} = \sum_{n=0}^{N} a_{2 n+1} (-1)^{2 n+1}x^{2 n+1}\). This simplifies to \(-\sum_{n=0}^{N} a_{2 n+1}x^{2 n+1}\).
3Step 3: Check if f(-x) = -f(x)
As we can see, when we substituted \(-x\) for \(x\), we got the negative of the original function \(-\sum_{n=0}^{N} a_{2 n+1}x^{2 n+1}\), which is exactly \(-f(x)\). Therefore, the given function is an odd function since it meets the condition f(-x) = -f(x).
Key Concepts
Polynomial FunctionFunction TransformationOdd Power TermsSymmetry in Functions
Polynomial Function
A polynomial function is an expression made up of terms, each consisting of a constant multiplied by a variable raised to a non-negative integer power. These functions are expressed in the general form:
The specific function in the exercise involves odd powers of \(x\), which fundamentally influences its behavior, especially in relation to the function's symmetry.
- The form typically looks like this: \(f(x) = a_nx^n + a_{n-1}x^{n-1} + \ldots + a_1x + a_0\)
- Each term, such as \(a_nx^n\), is a product of a coefficient \(a_n\) and a variable \(x\) raised to a power \(n\).
The specific function in the exercise involves odd powers of \(x\), which fundamentally influences its behavior, especially in relation to the function's symmetry.
Function Transformation
Function transformations involve changing the appearance of a function's graph. These transformations can include translations, reflections, stretches, and compressions. When dealing with functions, these transformations can alter its shape, position, and orientation.
- Transformations can describe shifts parallel to the axes, reflections across axes, or stretches.
- The expression \(f(-x)\) typically indicates a reflection over the y-axis.
Odd Power Terms
In polynomial functions, odd power terms are expressions where the variable is raised to an odd integer exponent, such as \(x^3\) or \(x^5\). These play a significant role in defining the overall behavior and shape of the function's graph.
- Odd power terms reflect that when \(x\) is replaced by \(-x\), the result is negative, leading to reflection properties.
- The sum of odd powered terms ensures that if the original function \(f(x)\) is given, then \(f(-x)\) will equate to \(-f(x)\).
Symmetry in Functions
Symmetry in functions is an essential property used to determine the type of function. A function can be either even, odd, or have no symmetry. In this context, for a function to be considered odd, it must satisfy the condition \(f(-x) = -f(x)\). This indicates a type of symmetry known as rotational symmetry about the origin.
- If the graph of the function looks the same after a 180-degree rotation around the origin, the function is indeed an odd function.
- This symmetry helps in understanding and predicting the behavior of the function across different inputs.
Other exercises in this chapter
Problem 109
Think About It Let \(f\) be an even function. Determine whether \(g\) is even, odd, or neither. Explain. (a) \(g(x)=-f(x)\) (b) \(g(x)=f(-x)\) (c) \(g(x)=f(x)-2
View solution Problem 110
Use the functions \(f(x)=\frac{1}{8} x-3\) and \(g(x)=x^{3}\) to find the indicated value or function. $$g^{-1} \circ f^{-1}$$
View solution Problem 111
Use the functions \(f(x)=x+4\) and \(g(x)=2 x-5\) to find the specified function. $$g^{-1} \circ f^{-1}$$
View solution Problem 112
Prove that a function of the following form is even. $$y=a_{2 n} x^{2 n}+a_{2 n-2} x^{2 n-2}+\cdots+a_{2} x^{2}+a_{0}$$
View solution