Problem 109
Question
Think About It Let \(f\) be an even function. Determine whether \(g\) is even, odd, or neither. Explain. (a) \(g(x)=-f(x)\) (b) \(g(x)=f(-x)\) (c) \(g(x)=f(x)-2\) (d) \(g(x)=-f(x+3)\)
Step-by-Step Solution
Verified Answer
(a) \(g(x) = -f(x)\) is odd. (b) \(g(x) = f(-x)\) is even. (c) \(g(x) = f(x) - 2\) is even. (d) \(g(x) = -f(x + 3)\) is neither odd nor even.
1Step 1: Determine the nature of function g(x) = -f(x)
Substitute \(x\) with \(-x\) in the function \(g(x) = -f(x)\), thus we get \(g(-x) = -f(-x)\). However, since \(f\) is even, \(f(-x) = f(x)\) so, \(g(-x) = -f(x) = -g(x)\). Therefore, \(g(x)\) is an odd function.
2Step 2: Determine the nature of function g(x) = f(-x)
Substitute \(x\) with \(-x\) in the function \(g(x) = f(-x)\), thus we get \(g(-x) = f(x)\). Since \(g(-x) = g(x)\), \(g(x)\) is an even function.
3Step 3: Determine the nature of function g(x) = f(x) - 2
Substitute \(x\) with \(-x\) in the function \(g(x) = f(x) - 2\), thus we get \(g(-x) = f(-x) - 2 = f(x) - 2 = g(x)\). Therefore, \(g(x)\) is an even function.
4Step 4: Determine the nature of function g(x) = -f(x+3)
Substitute \(x\) with \(-x\) in the function \(g(x) = -f(x+3)\), then we get \(g(-x) = -f(-x+3) = -f(x+3) ≠ g(x)\). Thus, \(g(x)\) is neither, since it does not obey the rules of either an odd or even function.
Key Concepts
Function TransformationEven FunctionOdd FunctionFunction Properties
Function Transformation
Understanding function transformations is essential in determining how functions shift, stretch, rotate, or flip on a graph. Function transformation refers to the modification of a function's attributes, like its domain, range, and overall graph shape. These transformations can occur in several ways, each governed by specific operations:
- Translation: Moves the function horizontally or vertically.
- Reflection: Flips the function over a specific axis, such as the x-axis or y-axis.
- Scaling: Stretches or compresses the function's graph.
Even Function
An even function is characterized by its symmetry about the y-axis. This means that for every input \(x\), the function satisfies the condition:
- \(f(-x) = f(x)\)
- \(g(x) = f(-x)\) remains even because replacing \(x\) with \(-x\) yields \(g(-x) = f(x)\) which equals \(g(x)\).
- Similarly, \(g(x) = f(x) - 2\) is also even as it retains the symmetry of \(f(x)\) about the y-axis after a vertical translation of 2 units.
Odd Function
Odd functions possess a distinctive point symmetry about the origin, implying they exhibit a rotational symmetry of 180 degrees around the origin. The mathematical characteristic of an odd function is:
- \(f(-x) = -f(x)\)
- \(g(x) = -f(x)\) transforms from an even function to an odd function. When you substitute \(x\), the resulting \(g(-x) = -f(-x) = -f(x)\) indeed gives \(-g(x)\), confirming \(g(x)\) as an odd function.
Function Properties
Functions possess specific properties that allow us to classify and analyze them based on symmetry, continuity, and transformations. Understanding these properties clarifies whether a function is even, odd, or neither:
- An even function complements itself on opposite sides of the y-axis.
- An odd function complements itself across the origin, such that their graphs rotate 180 degrees around it.
- Functions like \(g(x) = -f(x+3)\), which lack symmetry, are neither. The combination of horizontal translation and reflection over the x-axis breaks the symmetrical pattern needed to retain even or odd properties.
Other exercises in this chapter
Problem 109
Let \(f\) be an even function. Determine whether \(g\) is even, odd, or neither. Explain. (a) \(g(x)=-f(x)\) (b) \(g(x)=f(-x)\) (c) \(g(x)=f(x)-2\) (d) \(g(x)=-
View solution Problem 109
Use the functions \(f(x)=\frac{1}{8} x-3\) and \(g(x)=x^{3}\) to find the indicated value or function. $$f^{-1} \circ g^{-1}$$
View solution Problem 110
Use the functions \(f(x)=\frac{1}{8} x-3\) and \(g(x)=x^{3}\) to find the indicated value or function. $$g^{-1} \circ f^{-1}$$
View solution Problem 111
Prove that a function of the following form is odd. $$y=a_{2 n+1} x^{2 n+1}+a_{2 n-1} x^{2 n-1}+\cdots+a_{3} x^{3}+a_{1} x$$
View solution