Problem 111
Question
If \(z=a+b i\), find \(z+\bar{z}\) and \(z-\bar{z}\).
Step-by-Step Solution
Verified Answer
\(z + \bar{z} = 2a\) and \(z - \bar{z} = 2b i\).
1Step 1: Identify the components
Given a complex number \(z = a + b i\). Here, \(a\) is the real part and \(b i\) is the imaginary part.
2Step 2: Compute the conjugate
The conjugate of \(z\), denoted as \(\bar{z}\), is derived by changing the sign of the imaginary part: \(\bar{z} = a - b i\).
3Step 3: Sum of the complex number and its conjugate
Add \(z\) and \(\bar{z}\): \(z + \bar{z} = (a + b i) + (a - b i) = a + b i + a - b i\). Simplifying, we get: \(2a\).
4Step 4: Difference of the complex number and its conjugate
Subtract \(\bar{z}\) from \(z\): \(z - \bar{z} = (a + b i) - (a - b i) = a + b i - a + b i\). Simplifying, we get: \(2b i\).
Key Concepts
ConjugateReal PartImaginary Part
Conjugate
In the realm of complex numbers, the concept of a conjugate plays a crucial role. A complex number, such as \( z = a + bi \), consists of a real part \( a \) and an imaginary part \( bi \). The conjugate of a complex number is obtained by changing the sign of the imaginary component. This means that if you have \( z = a + bi \), the conjugate \( \bar{z} \) is expressed as \( a - bi \).
This switch in the sign is what defines a conjugate. Relying on conjugates can simplify various algebraic operations with complex numbers, especially when working with their sums, differences or even products and quotients.
When a complex number is added to its conjugate, the imaginary parts are canceled out, leaving only the doubled real part. However, when you subtract the conjugate from the original complex number, the real parts cancel out, leaving a doubled imaginary part. This property makes conjugates exceedingly useful in simplifying and understanding operations with complex numbers.
This switch in the sign is what defines a conjugate. Relying on conjugates can simplify various algebraic operations with complex numbers, especially when working with their sums, differences or even products and quotients.
When a complex number is added to its conjugate, the imaginary parts are canceled out, leaving only the doubled real part. However, when you subtract the conjugate from the original complex number, the real parts cancel out, leaving a doubled imaginary part. This property makes conjugates exceedingly useful in simplifying and understanding operations with complex numbers.
Real Part
The real part of a complex number is fundamental to its structure. In our example, with \( z = a + bi \), "a" is what we call the real part. This is the component that exists on the real number line, independent of any imaginary influences. The real part provides the horizontal dimension in the complex plane, which is the plane on which all complex numbers can be represented.
- If you plot \( z \) on a graph, \( a \) determines how far along the x-axis (the real axis) the number will appear.
- The real part of a complex number impacts how we perceive its proximity to other numbers and to the center, or origin, of the complex plane.
Imaginary Part
In complex numbers, the imaginary part is equally as important as the real part, despite its seemingly abstract nature. The imaginary part consists of \( bi \), where "b" is a real number and \( i \) is the imaginary unit. The imaginary unit \( i \) is defined by the property \( i^2 = -1 \). This fundamental property distinguishes complex numbers from real numbers.
- The imaginary part gives a complex number its vertical position on the complex plane.
- It represents the influence of the imaginary unit \( i \), enabling calculations that extend beyond the real number system.
Other exercises in this chapter
Problem 110
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If \(z=a+b i\), find \(\bar{z}\). Use your answer to compute \(\overline{(\bar{z})}\), and compare your answer with \(z\).
View solution