Problem 110
Question
First determine whether the solutions of each quadratic equation are real or complex without solving the equation. Then solve the equation. \(-3 x^{2}-x-4=0\)
Step-by-Step Solution
Verified Answer
The solutions are complex: \(x = -\frac{1}{6} \pm \frac{i\sqrt{47}}{6}\).
1Step 1: Determine the Discriminant
To find out if the solutions are real or complex, we calculate the discriminant of the quadratic equation. The formula for the discriminant is given by \(\Delta = b^2 - 4ac\), where \(a = -3\), \(b = -1\), and \(c = -4\) in our equation. Substitute these values to get \(\Delta = (-1)^2 - 4(-3)(-4)\).
2Step 2: Calculate the Discriminant
Substitute the values into the discriminant formula: \(\Delta = 1 - 48 = -47\). Since the discriminant is less than zero (\(\Delta < 0\)), the solutions are complex numbers.
3Step 3: Use the Quadratic Formula
Since the solutions are complex, we will use the quadratic formula: \(x = \frac{-b \pm \sqrt{\Delta}}{2a}\). Substitute \(a = -3\), \(b = -1\), and \(\Delta = -47\) into the formula to get \(x = \frac{-(-1) \pm \sqrt{-47}}{2(-3)}\).
4Step 4: Simplify the Quadratic Formula
Simplify the expression: \(x = \frac{1 \pm \sqrt{-47}}{-6}\). Since \(\sqrt{-47} = i\sqrt{47}\), further simplify it to \(x = \frac{1 \pm i\sqrt{47}}{-6}\).
5Step 5: Write the Final Solution
The solutions in terms of real and imaginary parts are \(x = -\frac{1}{6} \pm \frac{i\sqrt{47}}{6}\). Therefore, the solutions are complex numbers.
Key Concepts
DiscriminantComplex NumbersQuadratic Formula
Discriminant
When you encounter a quadratic equation, the discriminant helps you determine the nature of its solutions. The discriminant is part of the quadratic formula, represented by \( b^2 - 4ac \).
- If the discriminant is positive (\( \Delta > 0 \)), the quadratic equation has two distinct real solutions.
- If the discriminant is zero (\( \Delta = 0 \)), the equation has exactly one real solution, also called a repeated or double root.
- If the discriminant is negative (\( \Delta < 0 \)), the solutions are not real numbers; they are complex numbers.
Complex Numbers
Complex numbers are numbers that have both real and imaginary parts. They are typically written in the form \( a + bi \), where \( a \) is the real part and \( bi \) is the imaginary part, with \( i \) being the imaginary unit.
- The imaginary unit \( i \) is defined as the square root of -1, so \( i^2 = -1 \).
- Complex numbers can be added, subtracted, multiplied, and divided like real numbers, accounting for the imaginary part using \( i \).
Quadratic Formula
The quadratic formula is a universal tool for solving any quadratic equation of the form \( ax^2 + bx + c = 0 \). It is given by:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]This formula lets us find the solutions (roots) of the equation by substituting the coefficients \( a \), \( b \), and \( c \).
- The symbols \( \pm \) suggest there will be two solutions, one with a plus and the other with a minus.
- The square root of the discriminant \( \sqrt{b^2 - 4ac} \) determines if the solutions are real or complex.
- For complex solutions, expressed using an imaginary unit \( i \), the process leads to results outside the typical real numbers.
Other exercises in this chapter
Problem 109
First determine whether the solutions of each quadratic equation are real or complex without solving the equation. Then solve the equation. \(3 x^{2}-5 x+6=0\)
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