Problem 11
Question
Find the slope of the line through P and Q. $$ P(1,-3), Q(-1,6) $$
Step-by-Step Solution
Verified Answer
The slope of the line through P and Q is \(-\frac{9}{2}\).
1Step 1: Identify Coordinates
Locate the coordinates of the given points: \(P(1, -3)\) and \(Q(-1, 6)\). This helps in identifying which values correspond to \(x_1, y_1\) and \(x_2, y_2\).
2Step 2: Apply Slope Formula
Use the slope formula \( m = \frac{y_2 - y_1}{x_2 - x_1} \) where \((x_1, y_1) = (1, -3)\) and \((x_2, y_2) = (-1, 6)\).
3Step 3: Substitute Values
Substitute the coordinates into the slope formula: \( m = \frac{6 - (-3)}{-1 - 1} \).
4Step 4: Calculate Numerator
Compute the numerator: \( 6 - (-3) = 6 + 3 = 9 \).
5Step 5: Calculate Denominator
Compute the denominator: \(-1 - 1 = -2\).
6Step 6: Compute Slope
Divide the calculated numerator by the denominator: \( m = \frac{9}{-2} = -\frac{9}{2} \).
Key Concepts
Slope FormulaCoordinate GeometryLinear Equations
Slope Formula
The slope of a line is a crucial concept in coordinate geometry, especially when working with linear equations. It measures the steepness or incline of a line, providing insights into how one variable changes with respect to another. To find the slope of a line passing through two distinct points, you can use the slope formula, which is defined as:\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]In this formula, \( (x_1, y_1) \) and \( (x_2, y_2) \) are the coordinates of two points on the line. The numerator \( y_2 - y_1 \) represents the vertical change, or rise, between the two points, while the denominator \( x_2 - x_1 \) represents the horizontal change, or run.
- If the slope \( m \) is positive, the line inclines upwards as it moves from left to right.
- If the slope is negative, the line declines.
- A zero slope indicates a horizontal line, while an undefined slope (caused by a denominator of zero) indicates a vertical line.
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, allows us to study geometry using a coordinate system. By employing algebraic methods, we can explore geometric problems and relationships in a more analytical way. It combines algebra and geometry by positioning shapes on a coordinate plane.
- The coordinate plane consists of two perpendicular axes: the x-axis (horizontal) and the y-axis (vertical).
- Each point on this plane is represented as an ordered pair \( (x, y) \), where \( x \) is the horizontal displacement from the origin and \( y \) is the vertical displacement.
Linear Equations
Linear equations represent straight lines on a graph, and they can be expressed in various forms such as slope-intercept form \( y = mx + b \), point-slope form, or standard form. In each, the slope \( m \) plays a vital role in defining the characteristics of the line.A linear equation essentially describes a linear relationship between two variables. For the coordinates \( P(1, -3) \) and \( Q(-1, 6) \), the slope \( m = -\frac{9}{2} \) indicates how changes in \( x \) affect the value of \( y \). In real-world applications, such relationships might represent anything from the rate of speed over time to changes in cost with respect to quantity.
- The intercept \( b \) in the slope-intercept form represents the point where the line crosses the y-axis.
- The steeper the slope, the more the line "climbs" or "falls" per unit of x.
Other exercises in this chapter
Problem 10
\(5-10\) . Determine whether the given points are on the graph of the equation. $$ x^{2}+y^{2}=1 ; \quad(0,1),\left(\frac{1}{\sqrt{2}}, \frac{1}{\sqrt{2}}\right
View solution Problem 10
Sketch the region given by the set. \(\\{(x, y) | y=-2\\}\)
View solution Problem 11
Write an equation that expresses the statement. \(z\) is proportional to the square root of \(y\)
View solution Problem 11
\(11-36\) Make a table of values and sketch the graph of the equation. Find the \(x\) - and \(y\) -intercepts. $$ y=-x $$
View solution