Problem 11
Question
\(11-36\) Make a table of values and sketch the graph of the equation. Find the \(x\) - and \(y\) -intercepts. $$ y=-x $$
Step-by-Step Solution
Verified Answer
Both intercepts are at (0, 0). The graph is a line through the origin with slope -1.
1Step 1: Understand the Equation
The given equation is \( y = -x \). This is a linear equation in slope-intercept form \( y = mx + b \), where the slope \( m = -1 \) and the y-intercept \( b = 0 \).
2Step 2: Create a Table of Values
Choose a few values for \( x \) and compute the corresponding \( y \) values using the equation \( y = -x \). For example: When \( x = -2 \), \( y = -(-2) = 2 \); when \( x = 0 \), \( y = 0 \); when \( x = 2 \), \( y = -2 \).
3Step 3: Plot the Points
Using the table of values from Step 2, plot the points on a coordinate plane. The points from the table include (-2, 2), (0, 0), and (2, -2).
4Step 4: Draw the Line
Connect the plotted points in a straight line extending through each point. This line represents the graph of the equation \( y = -x \).
5Step 5: Identify the Intercepts
For the y-intercept, set \( x = 0 \) in the equation to find \( y \): \( y = 0 \). This gives the y-intercept at the origin (0, 0). For the x-intercept, set \( y = 0 \) and solve for \( x \): \( 0 = -x \), which gives \( x = 0 \). Thus, the x-intercept is also at the origin (0, 0).
Key Concepts
Graphing Linear EquationsSlope-Intercept FormIntercepts
Graphing Linear Equations
Graphing linear equations involves plotting points on a coordinate plane and connecting them to form a line. It's a visual representation of relationships between variables. This can be understood through the equation provided, which is a linear function. In the example exercise, the equation given is \(y = -x\). This particular equation will create a line with a specific slope and intercept.
- First, you create a table of values. Select different values for \(x\) (such as -2, 0, and 2) and calculate the corresponding \(y\) values using the equation.
- For each \(x\), plug it into the equation to get \(y\). When \(x = -2\), \(y = 2\); when \(x = 0\), \(y = 0\); when \(x = 2\), \(y = -2\).
- These values form coordinate points (-2,2), (0,0), and (2,-2).
Slope-Intercept Form
The slope-intercept form is a way of expressing linear equations. It is represented as \(y = mx + b\) where \(m\) is the slope of the line and \(b\) is the y-intercept. Recognizing this form helps to quickly identify the slope and intercepts, crucial for graphing equations effectively. For the equation \(y = -x\), it is in slope-intercept form where the slope \(m\) is -1 and the y-intercept \(b\) is 0.
- The slope \(m = -1\) indicates that for every increase of 1 unit in \(x\), \(y\) decreases by 1 unit, suggesting a downward trend.
- The y-intercept \(b = 0\) implies that the line crosses the y-axis at the origin (0,0).
Intercepts
Intercepts are crucial points where the graph of an equation crosses the axes. Understanding intercepts helps in sketching graphs accurately. For linear equations, the x-intercept is where the line crosses the x-axis, and the y-intercept is where it crosses the y-axis.In the example of \(y = -x\), both the x-intercept and y-intercept occur at the origin (0,0).
- To find the y-intercept, set \(x = 0\) in the equation and solve for \(y\). Here, setting \(x = 0\) gives \(y = 0\), identifying the y-intercept at (0,0).
- For the x-intercept, set \(y = 0\) and solve for \(x\). Solving \(0 = -x\) gives \(x = 0\), indicating the x-intercept is also at (0,0).
Other exercises in this chapter
Problem 11
Find the slope of the line through P and Q. $$ P(1,-3), Q(-1,6) $$
View solution Problem 11
Write an equation that expresses the statement. \(z\) is proportional to the square root of \(y\)
View solution Problem 11
Sketch the region given by the set. \(\\{(x, y) | 1
View solution Problem 12
Find the slope of the line through P and Q. $$ P(-1,-4), Q(6,0) $$
View solution