Problem 11
Question
Fill in the blanks to add (subtract) the polynomials. $$ \left(6 x^{2}+2 x+3\right)+\left(4 x^{2}-7 x+1\right) $$ $$ \begin{aligned} &=\left(6 x^{2}+\quad\right)+(\quad-7 x)+(3+\quad)\\\ &=\quad-5 x+ \end{aligned} $$
Step-by-Step Solution
Verified Answer
The summed polynomial is \(10x^2 - 5x + 4\).
1Step 1: Combine Like Terms for Each Polynomial Degree
Identify the like terms in the two polynomials. The expression given is \((6x^2 + 2x + 3) + (4x^2 - 7x + 1)\). You need to combine the terms with similar degrees. Specifically, \(6x^2\) and \(4x^2\) are the quadratic terms, \(2x\) and \(-7x\) are the linear terms, and \(3\) and \(1\) are the constant terms.
2Step 2: Add the Quadratic Terms
Add the quadratic terms \(6x^2\) and \(4x^2\) together. The calculation is \(6x^2 + 4x^2 = 10x^2\).
3Step 3: Add the Linear Terms
Combine the linear terms \(2x\) and \(-7x\). The calculation is \(2x - 7x = -5x\).
4Step 4: Add the Constant Terms
Add the constant terms \(3\) and \(1\). The calculation is \(3 + 1 = 4\).
5Step 5: Write the Final Combined Polynomial
Combine all the results from the previous steps: \(10x^2\) from the quadratic terms, \(-5x\) from the linear terms, and \(+4\) from the constant terms. So, the final polynomial is \(10x^2 - 5x + 4\).
Key Concepts
Quadratic Terms in Polynomial AdditionLinear Terms and Their RoleUnderstanding Constant Terms
Quadratic Terms in Polynomial Addition
Quadratic terms are those parts of a polynomial that include the variable squared, expressed as \( ax^2 \). In our exercise, the quadratic terms are \( 6x^2 \) and \( 4x^2 \). When adding or subtracting polynomials, we need to combine these terms separately from others because they share the same degree.
To add quadratic terms:
To add quadratic terms:
- Align terms with the same degree.
- Add the coefficients, maintaining the squared variable intact.
Linear Terms and Their Role
Linear terms in a polynomial are expressed in the form \( bx \). These are terms where the variable appears to the first power, like \( 2x \) and \(-7x \) in our current exercise. Although they involve the variable x, they don't carry the squared degree that quadratic terms do.
When combining linear terms:
When combining linear terms:
- Focus on adding or subtracting the coefficients of \( x \).
- Remember that the degree, which is 1 in linear terms, stays constant during addition or subtraction.
Understanding Constant Terms
Constant terms are the numbers without variables in polynomial expressions, such as \( 3 \) and \( 1 \) in our polynomial. They represent the polynomial's fixed value component, which doesn't change with the input value of the variable.
To add constant terms:
To add constant terms:
- Simply add the numbers together.
- No variables are involved, making the process straightforward.
Other exercises in this chapter
Problem 11
Find each product. See Example 1. $$ (m-6)^{2} $$
View solution Problem 11
Complete each solution. $$ \begin{aligned} (2 x+5)(3 x-2) &=2 x(3 x)-\quad(2)+\quad(3 x)-(2) \\ &=6 x^{2}-\quad+10 \\ &=6 x^{2}+\quad-10 \end{aligned} $$
View solution Problem 11
Make a term-coefficient-degree table like that shown in Example 1 for each polynomial. $$ 8 x^{2}+x-7 $$ (TABLE NOT COPY)
View solution Problem 11
Complete each solution to simplify each expression. \(\left(y^{5} y^{3}\right)^{-5}=(\quad)^{-5}=y \quad=\frac{1}{y}\)
View solution