Problem 11
Question
Complete each solution to simplify each expression. \(\left(y^{5} y^{3}\right)^{-5}=(\quad)^{-5}=y \quad=\frac{1}{y}\)
Step-by-Step Solution
Verified Answer
The simplified expression is \(\frac{1}{y^{40}}\).
1Step 1: Simplify the Expression Inside the Parentheses
The expression inside the parentheses is \(y^5 y^3\). To simplify this, apply the product of powers rule, which states that when you multiply powers with the same base, you add the exponents: \(y^5 \cdot y^3 = y^{5+3} = y^8\).
2Step 2: Substitute the Simplified Expression
Now substitute \(y^8\) back into the expression: \((y^8)^{-5}\).
3Step 3: Apply the Power Rule for Exponents
Use the power of a power rule, which states that when raising a power to another power, multiply the exponents: \((y^8)^{-5} = y^{8 \cdot (-5)} = y^{-40}\).
4Step 4: Convert to a Reciprocal
An expression with a negative exponent \(y^{-40}\) can be converted to its reciprocal with a positive exponent: \(y^{-40} = \frac{1}{y^{40}}\).
Key Concepts
Product of Powers RulePower of a Power RuleNegative Exponents
Product of Powers Rule
When working with algebraic expressions, one essential rule to remember is the **Product of Powers Rule**. This rule makes it straightforward to simplify expressions when you're multiplying powers with the same base.
Here's how it works: if you have two expressions with the same base, like +y^a+ and +y^b+, you can simplify them by adding their exponents. This means that \( y^a \times y^b = y^{a+b} \).
For instance, simplify \( y^5 \times y^3 \):
Here's how it works: if you have two expressions with the same base, like +y^a+ and +y^b+, you can simplify them by adding their exponents. This means that \( y^a \times y^b = y^{a+b} \).
For instance, simplify \( y^5 \times y^3 \):
- First, ensure the bases are the same, which they are in this case (+y+).
- Next, simply add the exponents: \( 5+3 \), giving you \( y^8 \).
Power of a Power Rule
The next rule we'll explore is the **Power of a Power Rule**. This rule simplifies expressions where a power is raised to another power, such as \( (y^a)^b \).
To apply this rule, multiply the exponents: \( (y^a)^b = y^{a \cdot b} \). It ensures that even when expressions seem more complex, you can manage them efficiently.
Consider the expression \( (y^8)^{-5} \). Here's how you simplify it using this rule:
To apply this rule, multiply the exponents: \( (y^a)^b = y^{a \cdot b} \). It ensures that even when expressions seem more complex, you can manage them efficiently.
Consider the expression \( (y^8)^{-5} \). Here's how you simplify it using this rule:
- Identify the base, which is +y+, and the exponents, which are +8+ and +(-5)+.
- Multiply the exponents together: \( 8 \times (-5) = -40 \).
- The simplified expression becomes \( y^{-40} \).
Negative Exponents
Negative exponents can be puzzling at first, but once understood, they become quite logical. A **Negative Exponent** indicates that we take the reciprocal of the base raised to the opposite positive exponent.
In simpler terms, \( y^{-a} = \frac{1}{y^a} \). This transformation from a negative to a positive exponent involves flipping the base into a fraction.
Let's break down an example using \( y^{-40} \):
In simpler terms, \( y^{-a} = \frac{1}{y^a} \). This transformation from a negative to a positive exponent involves flipping the base into a fraction.
Let's break down an example using \( y^{-40} \):
- Recognize the negative exponent, which is -40.
- Convert it to a positive by taking the reciprocal: \( y^{-40} \) becomes \( \frac{1}{y^{40}} \).
Other exercises in this chapter
Problem 11
Fill in the blanks to add (subtract) the polynomials. $$ \left(6 x^{2}+2 x+3\right)+\left(4 x^{2}-7 x+1\right) $$ $$ \begin{aligned} &=\left(6 x^{2}+\quad\right
View solution Problem 11
Make a term-coefficient-degree table like that shown in Example 1 for each polynomial. $$ 8 x^{2}+x-7 $$ (TABLE NOT COPY)
View solution Problem 12
Complete each solution. $$ \text { True or false: } 6 x+4+\frac{-3}{x+2}=6 x+4-\frac{3}{x+2} $$
View solution Problem 12
Fill in the blanks. a. We read \(n^{2} n^{3} n\) as "n _____ times \(n\) _____M times \(n\). b. We read \(\frac{x^{7}}{x^{5}}\) as " \(x\) to the seventh power
View solution