Problem 11
Question
Complete each solution. Write the polynomial \(2 x^{2}-1+5 x^{4}\) in descending powers of \(x\) and insert placeholders for each missing term.
Step-by-Step Solution
Verified Answer
Reordered with placeholders: \(5x^4 + 0x^3 + 2x^2 + 0x - 1\).
1Step 1: Identify Polynomial Structure
The polynomial given is \(2x^2 - 1 + 5x^4\). Polynomials should be written with terms ordered in descending powers.
2Step 2: Arrange Terms by Descending Powers
Reorder the terms so that they are arranged from the highest power of \(x\) to the lowest. The highest exponent is \(4\), followed by \(2\), and the constant term. This gives us \(5x^4 + 2x^2 - 1\).
3Step 3: Insert Missing Terms as Zero Placeholder
Since there is no term with \(x^3\) and \(x\), insert placeholders by adding \(0x^3\) and \(0x\) in the polynomial. This brings the polynomial to: \(5x^4 + 0x^3 + 2x^2 + 0x - 1\).
Key Concepts
Descending PowersMissing TermsPlaceholder Terms
Descending Powers
When we talk about arranging polynomials in descending powers, it simply means that we organize the terms from the highest exponent to the smallest. Each term in a polynomial is a combination of a coefficient, a variable, and an exponent, such as in the expression \(5x^4\). In our example, we see the polynomial \(2x^2 - 1 + 5x^4\). This is initially unordered. To fix it, we need to rearrange it so that it follows the sequence where the exponents decrease step by step.
- The highest degree term in this expression is \(5x^4\), therefore it should come first.- Then follows any term with the next lower degree, such as \(2x^2\). - Finally, insert any remaining terms like constants, which are equivalent to \(x^0\).
After adjustment, the polynomial will become \(5x^4 + 2x^2 - 1\). This order helps in analyzing and working further with polynomials easier.
- The highest degree term in this expression is \(5x^4\), therefore it should come first.- Then follows any term with the next lower degree, such as \(2x^2\). - Finally, insert any remaining terms like constants, which are equivalent to \(x^0\).
After adjustment, the polynomial will become \(5x^4 + 2x^2 - 1\). This order helps in analyzing and working further with polynomials easier.
Missing Terms
Missing terms in a polynomial can confuse students if they aren't explicitly stated. When writing polynomials, especially for computational purposes, it's essential to represent all degrees, even those with zero coefficients. If a degree is missing, like \(x^3\) and \(x^1\) in our example \(5x^4 + 2x^2 - 1\), it means they have a coefficient of zero.
Here's why it's helpful:
Here's why it's helpful:
- It keeps consistency in the sequence of descending powers.
- It simplifies operations like addition, subtraction, and finding derivatives.
- It provides a comprehensive view of all degrees present, avoiding missed calculations.
Placeholder Terms
Inserting placeholders involves adding terms to represent degrees that are not present in the polynomial. You achieve this by including zero coefficients for any missing degrees. In the polynomial \(5x^4 + 2x^2 - 1\), placeholders are used for the missing \(x^3\) and \(x^1\) terms.
Incorporating placeholder terms means writing:
Incorporating placeholder terms means writing:
- \(0x^3\) to indicate there is no cubic term.
- \(0x\) to show a missing linear term.
Other exercises in this chapter
Problem 10
Simplify each expression. a. \(10^{24} \times 10^{33}\) b. \(\frac{10^{50}}{10^{36}}\) c. \(\frac{10^{15} \times 10^{27}}{10^{40}}\)
View solution Problem 10
Determine whether each statement is true or false. \(\begin{array}{ll}{\text { a. } 6^{-2}=-36} & {\text { b. } 6^{-2}=\frac{1}{36}} \\ {\text { c. } \frac{x^{3
View solution Problem 11
Find each product. See Example 1. $$ (m-6)^{2} $$
View solution Problem 11
Complete each solution. $$ \begin{aligned} (2 x+5)(3 x-2) &=2 x(3 x)-\quad(2)+\quad(3 x)-(2) \\ &=6 x^{2}-\quad+10 \\ &=6 x^{2}+\quad-10 \end{aligned} $$
View solution