Problem 10
Question
Determine whether each statement is true or false. \(\begin{array}{ll}{\text { a. } 6^{-2}=-36} & {\text { b. } 6^{-2}=\frac{1}{36}} \\ {\text { c. } \frac{x^{3}}{y^{-2}}=\frac{y^{2}}{x^{3}}} & {\text { d. } \frac{-6 x^{-5}}{y^{-6}}=\frac{y^{6}}{6 x^{5}}}\end{array}\)
Step-by-Step Solution
Verified Answer
a: False, b: True, c: True, d: False.
1Step 1: Evaluate statement a
Statement a is \( 6^{-2} = -36 \). To evaluate this, recall that \( a^{-n} = \frac{1}{a^n} \). Therefore, \( 6^{-2} \) is \( \frac{1}{6^2} = \frac{1}{36} \), not \(-36\). The statement is false.
2Step 2: Evaluate statement b
Statement b is \( 6^{-2} = \frac{1}{36} \). Using the property \( a^{-n} = \frac{1}{a^n} \), we find that \( 6^{-2} = \frac{1}{6^2} = \frac{1}{36} \). The statement is true.
3Step 3: Evaluate statement c
Statement c is \( \frac{x^{3}}{y^{-2}}=\frac{y^{2}}{x^{3}} \). To simplify the left side, recall that \( y^{-n} = \frac{1}{y^n} \), so \( \frac{x^3}{y^{-2}} = x^3 \times y^2 = \frac{y^2 x^3}{1} \). Clearly, this matches the right side when simplified. Therefore, the statement is true.
4Step 4: Evaluate statement d
Statement d is \( \frac{-6 x^{-5}}{y^{-6}}=\frac{y^{6}}{6 x^{5}} \). By rewriting negative exponents, \( x^{-5} \) becomes \( \frac{1}{x^5} \) and \( y^{-6} \) becomes \( \frac{1}{y^6} \). Hence, \( \frac{-6 x^{-5}}{y^{-6}} = -6 \times \frac{y^6}{x^5} \). The statement simplifies to \( \frac{-6 y^6}{x^5} \), which is not equal to \( \frac{y^6}{6 x^5} \). Therefore, the statement is false.
Key Concepts
Properties of ExponentsSimplifying ExpressionsTrue or False Statements
Properties of Exponents
Understanding the properties of exponents is essential to evaluate algebraic expressions accurately. An exponent indicates how many times a number, known as the base, is multiplied by itself. A key rule is the negative exponent property, which states that any number raised to a negative exponent is equal to the reciprocal of that number raised to the positive exponent.
- If you have a number like \( a^{-n} \), it transforms to \( \frac{1}{a^n} \).
- This means \( 6^{-2} \) becomes \( \frac{1}{6^2} = \frac{1}{36} \).
- Expressions like \( x^{-5} \) become \( \frac{1}{x^5} \).
Simplifying Expressions
Simplifying algebraic expressions involves transforming them into a form that is easier to work with. This often includes applying exponent rules and performing basic arithmetic operations.
- The expression \( \frac{x^3}{y^{-2}} \) can be simplified by changing \( y^{-2} \) to \( y^2 \), resulting in \( x^3 \times y^2 \).
- For expressions like \( \frac{-6x^{-5}}{y^{-6}} \), rewrite \( x^{-5} \) as \( \frac{1}{x^5} \) and \( y^{-6} \) as \( y^6 \), then simplify.
- Ensure each term is rewritten with positive exponents to avoid mistakes.
True or False Statements
True or false exercises in algebra test your understanding of fundamental math concepts, such as exponent rules and simplifying expressions. They require careful evaluation to ensure accuracy.
- To verify a statement like \( 6^{-2} = -36 \), convert the exponent and calculate to find it is actually \( \frac{1}{36} \), making the statement false.
- For \( \frac{x^3}{y^{-2}} = \frac{y^2}{x^3} \), simplify both sides of the equation to confirm they match, proving it true.
- Evaluating statements requires checking each step for accuracy in conversion and simplification.
Other exercises in this chapter
Problem 10
What is the result of the subtraction in the \(x\) -column? $$ \begin{array}{rl} {8 x^{2}-7 x-1} & {8 x^{2}-7 x-1} \\ {-\left(4 x^{2}+6 x-9\right)} & {-4 x^{2}-
View solution Problem 10
Simplify each expression. a. \(10^{24} \times 10^{33}\) b. \(\frac{10^{50}}{10^{36}}\) c. \(\frac{10^{15} \times 10^{27}}{10^{40}}\)
View solution Problem 11
Complete each solution. Write the polynomial \(2 x^{2}-1+5 x^{4}\) in descending powers of \(x\) and insert placeholders for each missing term.
View solution Problem 11
Find each product. See Example 1. $$ (m-6)^{2} $$
View solution