Problem 107
Question
In Exercises 85-108, convert the polar equation to rectangular form. \(r=\dfrac{6}{2-3\sin\ \theta}\)
Step-by-Step Solution
Verified Answer
The rectangular form of the polar equation \(r=\dfrac{6}{2-3\sin\ \theta}\) is \(4x^4 + 4xy^2 - 3x^2y^2 - 3y^4 = 36x^2 + 36y^2\)
1Step 1: Implement x and y relationships
Start by substituting \(x = r\cos \theta\) and \(y = r\sin \theta\) into the given polar equation \(r = \dfrac{6}{2-3\sin\ \theta}\). Rewrite the equation by multiplying both sides by \(r\), that result in \(r^2 = r \times \dfrac{6}{2-3\sin\ \theta}\). Therefore \(r^2 = \dfrac{6r}{2-3\sin\ \theta}\). Now use the relationships \(x = r\cos \theta\) and \(y = r\sin \theta\) where \(r^2 = x^2 + y^2\) and multiply both sides by \(2-3\sin \theta\).
2Step 2: Substitute and Simplify It
Substitute \(r^2\) for \(x^2 + y^2\) and simplify the equation. \((2-3\sin \theta)(x^2 + y^2) = 6r. \)here we replace \(r\sin \theta\) with \(y\) and \(r\) with \(\sqrt{x^2+y^2}\). So the equation becomes, \((2-3y)(x^2 + y^2) = 6\sqrt{x^2+y^2}\)
3Step 3: Square Both Sides to Eliminate the Square Root
When you square both sides of equation, you get: \(4x^4 + 4xy^2 - 3x^2y^2 - 3y^4 = 36x^2 + 36y^2\). This equation is the rectangular form of the given polar equation.
Key Concepts
Polar EquationsRectangular FormCoordinate Systems
Polar Equations
Polar equations are a way of expressing mathematical relationships using polar coordinates, which are characterized by the variables \(r\) and \(\theta\). Here, \(r\) represents the radial distance from the origin, and \(\theta\) signifies the angular displacement from the positive x-axis.
Polar equations are especially useful when dealing with problems that have symmetrical properties or circular paths. They provide a unique perspective, differing from the more commonly used rectangular form which relies on the x-y coordinate system.
Polar equations are especially useful when dealing with problems that have symmetrical properties or circular paths. They provide a unique perspective, differing from the more commonly used rectangular form which relies on the x-y coordinate system.
- The given equation \(r = \dfrac{6}{2-3\sin\ \theta}\) is expressed in polar form.
- This form is advantageous for describing curves and shapes that are more naturally radial, such as spirals or circles.
Rectangular Form
The rectangular form of an equation is based on the Cartesian coordinate system, using \(x\) and \(y\) coordinates. This form is more familiar to most students because it forms the foundation of most algebra and calculus operations.
To convert a polar equation like \(r = \dfrac{6}{2-3\sin\ \theta}\) into rectangular form, we utilize the relationships between the two systems. Here’s how:
By manipulating and simplifying these expressions, we achieve a rectangular equation. In this problem, simplifying and substituting gives us the rectangular form \(4x^4 + 4xy^2 - 3x^2y^2 - 3y^4 = 36x^2 + 36y^2\). This form is useful for plotting equations on a standard x-y graph and analyzing their geometric properties.
To convert a polar equation like \(r = \dfrac{6}{2-3\sin\ \theta}\) into rectangular form, we utilize the relationships between the two systems. Here’s how:
- First, we note that \(x = r\cos \theta\) and \(y = r\sin \theta\).
- We also know \(r^2 = x^2 + y^2\).
By manipulating and simplifying these expressions, we achieve a rectangular equation. In this problem, simplifying and substituting gives us the rectangular form \(4x^4 + 4xy^2 - 3x^2y^2 - 3y^4 = 36x^2 + 36y^2\). This form is useful for plotting equations on a standard x-y graph and analyzing their geometric properties.
Coordinate Systems
Coordinate systems are frameworks for locating points within a given space. Two primary types are the polar and rectangular coordinate systems.
The **rectangular coordinate system** is the most familiar; it uses a grid of perpendicular lines (x and y axes) to describe any point in two-dimensional space with an ordered pair \((x, y)\).
The **polar coordinate system**, however, uses a point's distance from a fixed origin \(r\), and an angle \(\theta\) from a reference direction (usually the positive x-axis). Points are denoted as \((r, \theta)\).
The **rectangular coordinate system** is the most familiar; it uses a grid of perpendicular lines (x and y axes) to describe any point in two-dimensional space with an ordered pair \((x, y)\).
The **polar coordinate system**, however, uses a point's distance from a fixed origin \(r\), and an angle \(\theta\) from a reference direction (usually the positive x-axis). Points are denoted as \((r, \theta)\).
- These systems each have their advantages. Rectangular coordinates are preferred for straightforward mathematical calculations and describing linear relationships.
- Polar coordinates are often used in situations involving curves, rotations, or radial symmetry.
Other exercises in this chapter
Problem 105
In Exercises 85-108, convert the polar equation to rectangular form. \(r=\dfrac{2}{1+\sin\ \theta}\)
View solution Problem 106
In Exercises 85-108, convert the polar equation to rectangular form. \(r=\dfrac{1}{1-\cos\ \theta}\)
View solution Problem 108
In Exercises 85-108, convert the polar equation to rectangular form. \(r=\dfrac{6}{2\ \cos\ \theta-3\ \sin\ \theta}\)
View solution Problem 109
In Exercises 109-118, describe the graph of the polar equation and find the corresponding rectangular equation. Sketch its graph. \(r=6\)
View solution