Problem 106
Question
In Exercises 85-108, convert the polar equation to rectangular form. \(r=\dfrac{1}{1-\cos\ \theta}\)
Step-by-Step Solution
Verified Answer
The rectangular form of the given polar equation is \(x^2+y^2-x-r=0\).
1Step 1 Convert r and θ to rectangular coordinates
To convert the polar equation \(r=\dfrac{1}{1-\cos\ \theta}\) into rectangular form, we first note that in rectangular coordinates, \(r^2=x^2+y^2\) and \(\cos \theta = \frac{x}{r}\). Substitute \(\cos \theta\) with \(\frac{x}{r}\) in the polar equation.
2Step 2 Simplification
Substituting \(\cos \theta\) with \(\frac{x}{r}\) will yield the equation \(r=\dfrac{1}{1-\frac{x}{r}}\). Multiplying both sides of the equation by \((1-\frac{x}{r})\) we get \(r-\frac{x}{r^2} = 1\). Now multiply the entire equation by r to get rid of the denominator. This will give us \(r^2-x= r\). We can replace \(r^2\) with \(x^2+y^2\) on the left side.
3Step 3 Final Answer
Our rectangular form of \(r=\dfrac{1}{1-\cos\ \theta}\) is \(x^2+y^2-x = r \) after replacing \(r^2\) with \(x^2+y^2\). In other words we have \(x^2+y^2-x - r = 0\).
Key Concepts
Polar CoordinatesRectangular CoordinatesTrigonometric Substitution
Polar Coordinates
Polar coordinates are a system used to describe the location of a point in a plane by specifying its distance from a fixed point, known as the origin, and the angle formed with a fixed direction, usually the positive x-axis. This system is especially useful in scenarios where understanding relationships between lengths and angles is crucial, such as navigation and astronomy.
In polar coordinates, a point P is represented by the pair \(r, \theta\), where:
In polar coordinates, a point P is represented by the pair \(r, \theta\), where:
- \(r\) is the radial coordinate, indicating the distance from the origin to the point P.
- \(\theta\) is the angular coordinate, representing the counterclockwise angle from the positive x-axis to the line segment connecting the origin to point P.
Rectangular Coordinates
Rectangular coordinates, also known as Cartesian coordinates, define a point in the plane using two perpendicular lines, typically called the x-axis and y-axis. Each point is represented as \(x, y\), where:
When converting from polar to rectangular coordinates, the relationships between \(x, y\), \(r\), and \(\theta\) are essential:
- \(x\) is the horizontal component, indicating the point's position along the x-axis.
- \(y\) is the vertical component, representing the position along the y-axis.
When converting from polar to rectangular coordinates, the relationships between \(x, y\), \(r\), and \(\theta\) are essential:
- \(x = r \cos\theta\)
- \(y = r \sin\theta\)
- \(r = \sqrt{x^2 + y^2}\)
- \(\theta = \tan^{-1}(\frac{y}{x})\)
Trigonometric Substitution
Trigonometric substitution is a technique used to simplify the integration or transformation of expressions involving trigonometric functions. In the realm of coordinate conversion, it helps us handle the trigonometric components efficiently. In the context of converting polar equations to rectangular form, trigonometric identities provide the necessary substitutions.
Consider the polar equation given: \(r = \frac{1}{1 - \cos\theta}\). Substitution involves:
Consider the polar equation given: \(r = \frac{1}{1 - \cos\theta}\). Substitution involves:
- Recognizing that \(\cos\theta = \frac{x}{r}\) in rectangular terms.
- Replacing \(\cos\theta\) using this relationship to transform the polar equation.
- Handling the resulting equation to express it in terms of \(x\) and \(y\).
Other exercises in this chapter
Problem 104
In Exercises 85-108, convert the polar equation to rectangular form. \(r=3\ \sin\ 2\theta\)
View solution Problem 105
In Exercises 85-108, convert the polar equation to rectangular form. \(r=\dfrac{2}{1+\sin\ \theta}\)
View solution Problem 107
In Exercises 85-108, convert the polar equation to rectangular form. \(r=\dfrac{6}{2-3\sin\ \theta}\)
View solution Problem 108
In Exercises 85-108, convert the polar equation to rectangular form. \(r=\dfrac{6}{2\ \cos\ \theta-3\ \sin\ \theta}\)
View solution