Problem 106
Question
Simplify each expression. $$ -7(a-3)-5[3(a-4)-2(a+2)] $$
Step-by-Step Solution
Verified Answer
The expression simplifies to \(-12a + 101\).
1Step 1: Distribute within the first parenthesis
Simplify the expression \(-7(a-3)\) by distributing \(-7\) through the terms in the parenthesis. This gives: \[-7 \cdot a + 7 \cdot 3 = -7a + 21.\]
2Step 2: Distribute within the inner bracket
Simplify \(3(a-4)\) by distributing \(3\) to each term inside: \[3 \cdot a - 3 \cdot 4 = 3a - 12.\]Next, simplify \(-2(a+2)\) by distributing \(-2\) as follows: \[-2 \cdot a - 2 \cdot 2 = -2a - 4.\]
3Step 3: Combine terms in the bracket
Combine \(3a - 12\) and \(-2a - 4\) inside the brackets:\[(3a - 12) - (2a + 4) = 3a - 12 - 2a - 4 = (3a - 2a) + (-12 - 4) = a - 16.\]
4Step 4: Distribute the negative number through the bracket
Distribute \(-5\) through \((a - 16)\):\[-5 \cdot a - 5 \cdot (-16) = -5a + 80.\]
5Step 5: Combine like terms
Now add together all distributed terms:\((-7a + 21) - (5a - 80)\) becomes:\[-7a + 21 - 5a + 80 = (-7a - 5a) + (21 + 80) = -12a + 101.\]
Key Concepts
Distributive PropertyCombining Like TermsOrder of Operations
Distributive Property
The distributive property is a fundamental principle in algebra that involves multiplying a single term by each term inside a parenthesis. It's often written as \( a(b + c) = ab + ac \), which means you distribute (or multiply) the term outside the parenthesis to each of the terms within.
For example, in our expression
For example, in our expression
- \(-7(a-3)\), we distribute \(-7\) across \(a\) and \(-3\), giving us \(-7a + 21\).
- Similarly, to simplify \(3(a-4)\), we distribute \(3\) to both terms inside, resulting in \(3a - 12\).
Combining Like Terms
Combining like terms is an essential skill when simplifying algebraic expressions. Like terms are terms in an expression that have the same variable raised to the same power. Those terms can be easily added together by summing their coefficients.
Here's how it works in our problem:
Here's how it works in our problem:
- In the step \[(3a - 12) - (2a + 4),\] we combine \(3a\) and \(-2a\) because they both contain the variable \(a\). This results in \((3 - 2)a = a\).
- Similarly, we combine \(-12\) and \(-4\), both constant terms, to get \(-16\).
Order of Operations
The order of operations is a guiding principle in mathematics that dictates the sequence in which the operations should be executed to guarantee accurate results. A helpful acronym to remember is PEMDAS, which stands for:
- P: Parentheses first
- E: Exponents (i.e., powers and roots, etc.)
- M/D: Multiplication and Division (left-to-right)
- A/S: Addition and Subtraction (left-to-right)
- Simplify expressions inside parentheses first, using the distributive property where necessary.
- Combine like terms next.
- Handle any operations outside of parentheses, ensuring multiplication or division precedes addition or subtraction.
Other exercises in this chapter
Problem 106
Simplify each expression. $$8 x^{3}-x^{3}-\left(-2 x^{3}\right)$$
View solution Problem 106
Solve each equation. $$ 5 c-8-3 c=10+2 c-3 $$
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Evaluate each expression. $$ \text { a. }(-2-\sqrt{64})^{2} \quad \text { b. }-2-(\sqrt{64})^{2} $$
View solution Problem 107
Simplify each expression. $$19 a-\\{-2[4 a-2(a-16)]-3 a\\}$$
View solution