Problem 106
Question
Evaluate each expression. $$ \text { a. }(-2-\sqrt{64})^{2} \quad \text { b. }-2-(\sqrt{64})^{2} $$
Step-by-Step Solution
Verified Answer
Part a evaluates to 100, and part b evaluates to -66.
1Step 1: Simplify the square root
First, calculate the square root of 64. Since 64 is a perfect square, we have \( \sqrt{64} = 8 \).
2Step 2: Substitute and evaluate part a
Now, substitute 8 into the expression for part a: \((-2-\sqrt{64})^2\). This simplifies to \((-2-8)^2 = (-10)^2\).
3Step 3: Compute the square
Find the square of -10. \((-10)^2 = 100\). Thus, the simplified value for part a is 100.
4Step 4: Substitute and evaluate part b
For part b, substitute 8 into the expression: \(-2-(\sqrt{64})^2\). This becomes \(-2 - 8^2\).
5Step 5: Compute the power
Calculate \(8^2\): \(8^2 = 64\).
6Step 6: Simplify the expression
Combine the terms in the expression, \(-2 - 64 = -66\). Thus, the simplified value for part b is -66.
Key Concepts
Square RootsPerfect SquaresSimplifying Expressions
Square Roots
When we talk about square roots, we're referring to a mathematical operation that finds a number which, when multiplied by itself, gives the original number. For example, the square root of 64 is 8. This is because 8 times 8 equals 64. Square roots are often represented using the radical symbol, \( \sqrt{} \).
- To find the square root of a number, you can think of it as reversing the process of squaring that number.
- If a number is a perfect square, its square root will be an integer.
Perfect Squares
A perfect square is a number that can be expressed as the product of an integer multiplied by itself. For instance, 64 is a perfect square because it equals \( 8 \times 8 \).
- Recognizing perfect squares helps in simplifying expressions and solving algebraic equations.
- Common perfect squares include numbers like 1, 4, 9, 16, 25, 36, 49, etc.
Simplifying Expressions
Simplifying expressions is a key part of algebra that involves reducing expressions to their simplest form. This is done by performing operations such as addition, subtraction, multiplication, division, squaring, or taking square roots.
For instance, in part a, this involved turning the expression \((-2-8)^{2}\) into a more manageable \((-10)^{2}\), and finally \(100\). This step-by-step process ensures clarity and accuracy in solving the expressions.
- Simplification often involves combining like terms or converting complex operations into simpler ones.
- For expressions involving brackets or powers, simplify step by step: address innermost operations first, follow order of operations (PEMDAS/BODMAS), and simplify as you go.
For instance, in part a, this involved turning the expression \((-2-8)^{2}\) into a more manageable \((-10)^{2}\), and finally \(100\). This step-by-step process ensures clarity and accuracy in solving the expressions.
Other exercises in this chapter
Problem 106
Solve each equation. $$ 5 c-8-3 c=10+2 c-3 $$
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Simplify each expression. $$ -7(a-3)-5[3(a-4)-2(a+2)] $$
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Simplify each expression. $$19 a-\\{-2[4 a-2(a-16)]-3 a\\}$$
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Simplify each expression and solve each equation. a. \(\frac{1}{2}(6 x+8)-10-\frac{2}{3}(6 x-9)\) b. \(\frac{1}{2}(6 x+8)-10=-\frac{2}{3}(6 x-9)\)
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